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Lesson Posted on 23 May CBSE/Class 11/Science/Physics IIT JEE/IIT - JEE Advanced/Physics/Modern Physics Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching +1 Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/IIT JEE Crash Course less

Work and Energy

Vishesh Nigam

I am a Chemical Engineer and Khan Academy Talent Hunt Finalist (2017)(please watch my winning video below...

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Lesson Posted on 05 May IIT JEE/IIT - JEE Advanced/Chemistry/Physical Chemistry

Mole Concept

Prashant R.

I am a B.tech in Chemical Engineering from IIT Bombay & I have 5 years of experience in teaching & mentoring...

Mole is the foundation of Chemistry. It is the fundamental thing, yet many students get difficulty in understanding this concept & there are various reasons for different students.In this lesson, I am going to talk about mole concept in very basic detail. The mole is the unit of measurement for the... read more

Mole is the foundation of Chemistry. It is the fundamental thing, yet many students get difficulty in understanding this concept & there are various reasons for different students.

In this lesson, I am going to talk about mole concept in very basic detail.

The mole is the unit of measurement for the amount of substance in the International System of Units (SI). Just like kg for mass, litre for volume. we can relate mole to a dozen in an interesting way as we define dozen as an amount which contains 12 number of units of anything in the same way 1 mole is the amount of any substance which contains 6.022 × 10^23 entities

here entities can be anything like atoms, molecules, ions, electrons, protons or neutrons

e.g.                1 mole = 6.022×10^23 atoms

                      1 dozen = 12 atoms or bananas   

Standard definition - it is the amount of substance which contains the same number of entities as there are in 12 gm of the C-12 atom.

further, it was found that number of entities are 6.022×10^23

Carbon-12 is the most abundant stable isotope of carbon, and it is used for measuring atomic masses of all nuclides.

Relation of moles with mass, Volume & Number of entities

as we know,

1 mole contains 6.022×10^23 entities

 

number of moles = Number of entities⁄6.022×10^23

in the same way as 12 gm of carbon contain 1 mole

then we can write

no of moles = mass in grams/molecular mass(atomic mass)

and by Avogadro's law which says the equal volume of gases contain an equal number of molecules irrespective of nature of gases

we can write

number of moles=Volume at STP(litre)/22.4

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Lesson Posted on 16 Apr Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching Exam Coaching/UPSC Exams Coaching/NDA (National Defence Acadamy and Naval Acadamy) Exam Coaching Exam Coaching/Engineering Entrance Coaching +2 IIT JEE/IIT JEE MAINS/Mathematics IIT JEE/IIT - JEE Advanced/Mathematics less

How to prepare for IIT as mains exam over

Deepak

I have 7 year teaching experience with IIT as well as board classes ( 10th , 11th , and 12th ) for maths...

These are my few suggestions for 2018 Jee advance aspirants on how to begin JEE-ADVANCED 2018 Preparation.My wishing you best of luck a day before the exam will not work, you will have to study in next 40 days as a commando because you are on a mission to launch your self into the real world.First solve... read more

These are my few suggestions for 2018 Jee advance aspirants on how to begin JEE-ADVANCED 2018 Preparation.
My wishing you best of luck a day before the exam will not work, you will have to study in next 40 days as a commando because you are on a mission to launch your self into the real world.
First solve last five years JEE(A) papers in first five days in examination like conditions, after papers continue your regular scheduled study.
It will give you exposure to the topics that you feel strongly, i.e. you will have a battle plan of about 75 % syllabus first.
Identify topics that you are weak and questions have been asked very frequently from it. Divide these into four units, read class notes ( whatever I taught and stuck yourself on the chapter which you have done yourself) on them, solve two basic exercise and JEE questions on them and then move on. It will ensure that if an easy problem comes from it, you will be able to crack it.
Make your daily routine a very disciplined one like a soldier. Get up by 7 am in the morning, get ready like you are going to school have to breakfast by 8 am. Now you are on a mission. Study continuously in three-hour sittings. Take proper lunch, avoid napping, the slot of 2 pm to 5 pm must be study hours. Try to take two full JEE LEVEL tests every week in examination conditions.
#JEEADVANCE2018

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Lesson Posted on 16 Apr IIT JEE/IIT JEE MAINS/Mathematics IIT JEE/IIT - JEE Advanced

How to prepare for IIT advance after 40days duration of Jee Mains to Advance

Deepak

I have 7 year teaching experience with IIT as well as board classes ( 10th , 11th , and 12th ) for maths...

These are my few suggestions for 2018 Jee advance aspirants on how to begin JEE-ADVANCED 2018 Preparation.My wishing you best of luck a day before the exam will not work, you will have to study in next 40 days as a commando because you are on a mission to launch your self into the real world.First solve... read more

These are my few suggestions for 2018 Jee advance aspirants on how to begin JEE-ADVANCED 2018 Preparation.
My wishing you best of luck a day before the exam will not work, you will have to study in next 40 days as a commando because you are on a mission to launch your self into the real world.
First solve last five years JEE(A) papers in first five days in examination like conditions, after papers continue your regular scheduled study.
It will give you exposure to the topics that you feel strongly, i.e. you will have a battle plan of about 75 % syllabus first.
Identify topics that you are weak and questions have been asked very frequently from it. Divide these into four units, read class notes ( whatever I taught and stuck yourself on the chapter which you have done yourself) on them, solve two basic exercise and JEE questions on them and then move on. It will ensure that if an easy problem comes from it, you will be able to crack it.
Make your daily routine a very disciplined one like a soldier. Get up by 7 am in the morning, get ready like you are going to school have to breakfast by 8 am. Now you are on a mission. Study continuously in three-hour sittings. Take proper lunch, avoid napping, the slot of 2 pm to 5 pm must be study hours. Try to take two full JEE LEVEL tests every week in examination conditions.
#JEEADVANCE2018

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Lesson Posted on 01 Apr IIT JEE/IIT - JEE Advanced/Physics/Modern Physics CBSE/Class 11/Science/Physics Tuition/Class XI-XII Tuition (PUC)/Physical Education

why 200 volt AC is more dangerous than 220 volt DC???

Sandip Mandal

current or voltage we measure for AC are alaways rms(root mean square) value not the actual magnitude so 220 volt ac(rms)= 220*sqrt(2)=311 volt but 220 volt DC alaways gives the magnitude of curret or voltage =220 volt. since 200volt AC have grater magnitude than 220volt AC ,so 220... read more

current or  voltage we measure for AC  are alaways rms(root mean square) value not the actual magnitude         so 220 volt ac(rms)= 220*sqrt(2)=311 volt

    but 220 volt DC alaways gives the magnitude of curret or voltage =220 volt.

  since 200volt AC have grater magnitude than 220volt AC ,so 220 volt AC is more dangerous.

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Lesson Posted on 27 Mar IIT JEE/IIT - JEE Advanced/Physics/Mechanics

For a block of mass m in the spring block system as shown in the figure. Find out the time period

Kumar Kumar Sir

Earlier working with FIITJEE and Aakash about 18 years and now running an institute in The name of Kumar...

In equilibrium position of the block, extension in spring is x0 (say)\ kx0 = mg .-(i) Now, if we displace the block by x in the downward direction, the net force on the block towards mean position is F = k(x + x0) – mg = kx (using (i)) Hence the net force is acting towards mean position... read more
  • In equilibrium position of the block, extension in spring is x0 (say)
    \ kx0 = mg .-(i)

    Now, if we displace the block by x in the downward direction, the net force on the block towards mean position is

    F = k(x + x0) – mg = kx (using (i)) Hence the net force is acting towards mean position and is also proportional to x. So, the particle will perform SHM and its time period would be

    T=2pie root m/ k

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Lesson Posted on 02 Feb IIT JEE/IIT - JEE Advanced/Mathematics/Analytical geometry (2 dimensions)

Plane Analytic Geometry

Raj Kumar

I am Six Sigma Black belt certified. I am 2011 pass out in B.tech from NIT Srinagar. I am an experienced,...

The curves that we learn about in this chapter are called conic sections. They arise naturally in many situations and are the result of slicing a cone at various angles. Depending on where we slice our cone, and at what angle, we will either have... read more

                                                    conic section - ellipse

The curves that we learn about in this chapter are called conic sections. They arise naturally in many situations and are the result of slicing a cone at various angles.

Depending on where we slice our cone, and at what angle, we will either have a straight line, a circle, a parabola, an ellipse or a hyperbola. Of course, we could also get a single point, too.

Why study analytic geometry?

Science and engineering involves the study of quantities that change relative to each other (for example, distance-time, velocity-time, population-time, force-distance, etc).

It is much easier to understand what is going on in these problems if we draw graphs showing the relationship between the quantities involved.

The study of calculus depends heavily on a clear understanding of functions, graphs, slopes of curves and shapes of curves. For example, in the Differentiation chapter we use graphs to demonstrate relationships between varying quantities.

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Lesson Posted on 31 Jan IIT JEE/IIT - JEE Advanced/Physics/Modern Physics Tuition/Class XI-XII Tuition (PUC)/Physics

Why There Is A Bigger Hole (Compare To Other Two) In A Electric Socket?

Sujoy D.

1. Strong concept building classes. 2. Weekly tests in weak areas for students to improve their confidence. 3....

Point 1: For case for ground pin. Also ground pin is larger that other two pins so that it would be the first to go into the hole and the last to come out of the hole just for sake of safety Point 2: This is done to prevent the user from accidentally inserting the live or neutral pin into the ground... read more

Point 1: For case for ground pin. Also ground pin is larger that other two pins so that it would be the first to go into the hole and the last to come out of the hole just for sake of safety

Point 2: This is done to prevent the user from accidentally inserting the live or neutral pin into the ground pin.

Point 3: It is because of simple thing:

i. If all are same sized then you will have 3 choices to plug in but every time you will not make it right so you get confusion.

ii. In order to eliminate that one of them is bigger than remaining ones so that every time you plugin you will get supply even if you use 2 pin plug.

Point 4: R proportional to L/A. So larger the cross sectional area lesser the resistance!  So with less resistance in case of fault all the current will pass through that pin(which is the ground) and make no harm to your circuit! Basically its for electrical safety!

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Lesson Posted on 16 Jan Tuition/Class XI-XII Tuition (PUC)/Physics IIT JEE/IIT - JEE Advanced/Physics/Modern Physics

How To Solve A Mechanics Problem?

Satya Reddy

I have graduated from IIT Kharagpur from Civil Engineering Discipline. I have been working for Ola Cabs...

Solving a mechanics problem especially at JEE level is all about getting into right thinking framework. Step 1: Picking a frame of reference. It can be solved from inertial frame of reference or non-nertial frame of reference (where a pseudo force acts). Step 2: Divide the problem into small parts... read more

Solving a mechanics problem especially at JEE level is all about getting into right thinking framework. 

Step 1: Picking a frame of reference. It can be solved from inertial frame of reference or non-nertial frame of reference (where a pseudo force acts).

Step 2: Divide the problem into small parts and then draw the free body diagrams.

Step 3: Use the Newton's 3 Laws to write the equations.

Step 4: Solve the equations to get the answer.

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Asked on 16 Jan IIT JEE/IIT - JEE Advanced/Physics/Modern Physics

Is self induced emf in an inductor will be equal and opposite to the applied voltage? If yes then why... read more

Is self induced emf in an inductor will be equal and opposite to the applied voltage? If yes then why current flow in the circuit?

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