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Answered on 02/06/2022 Learn Civil Engineering Diploma
Chirag Sharma
with 7 years of teaching experience in Maths and sciencr for class 9th to 12th
Lesson Posted on 15/03/2021 Learn Civil Engineering Diploma
Tanmoy Mukherjee
I am an experienced, qualified Civil Engineering Teacher and tutor with over 12 years of experience in...
Bar Bending Schedule, commonly referred to as “BBS” is a comprehensive list that describes the location, mark, type, size, length and number, and bending details of each bar or fabric in a Reinforcement Drawing of a Structure. ... In context of Reinforcement bars, it is called bar scheduling.
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TIME TO MAKE A MOVE FROM AUTOCAD TO AUTODESK REVIT
Venuka V
I gave training on AutoCAD and Revit architecture for more than 10 students and on Primavera to 5 students....
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Lesson Posted on 15/05/2019 Learn Civil Engineering Diploma
DIFFERENT GRADES OF CONCRETE AND ITS STRENGTH
Aneesh S V
I am a civil engineering diploma holder have 4 years teaching experience of various polytechnics, and...
Different mixes (M) come in various mix proportions of the various ingredients of cement, sand and coarse aggregates. For instance, M20 comes in the respective ratio of 1:1:5:3. You can see other examples below in the table.
Concrete Grade | Mix Ratio (cement : sand : aggregates) | Compressive Strength | |
MPa (N/mm2) | psi | ||
Grades of Concrete | |||
M5 | 1 : 5 : 10 | 5 MPa | 725 psi |
M7.5 | 1 : 4 : 8 | 7.5 MPa | 1087 psi |
M10 | 1 : 3 : 6 | 10 MPa | 1450 psi |
M15 | 1 : 2 : 4 | 15 MPa | 2175 psi |
M20 | 1 : 1.5 : 3 | 20 MPa | 2900 psi |
Lesson Posted on 11/01/2018 Learn Civil Engineering Diploma
Difference Between Short And Long Term Deflections (Limit State Of Serviceability)
MOHAMMED BASEER
Working as an Assistant Professor in one the Reputed Engineering college of A.P, Experience of 5 years,...
Lesson Posted on 21/11/2017 Learn Civil Engineering Diploma
RCC (Reinforced Cement Concrete)
Gopinath B
Worked as a home Tutor for 4 years in Hyderabad. My way of teaching starts with motivating the student...
Cement Concrete
Cement |
Predetermined proportions.
|
Fine Aggregate | |
Coarse Aggregate | |
Water |
When water is added, chemical reaction will occur, which is very much slow and requires time (setting time) and favourable temperature for its completion,
This setting time can be divided into 3 distinct phases known as:
Initial set | 30-60 minutes |
Final set | 5-6 hours) |
Progressive hardening (increase in strength) |
|
Concrete has enough strength in compression but has little strength in tension, so obviously concrete is weak in Bending, Shear and Torsion.
So, to use Cement Concrete in structures which will be having tensile loads (Beams, Slabs etc.) steel bars may be placed at tensile zones of the structure.
The steel bars (steel reinforcement) takes the tensile stresses & Concrete so obtained is known as reinforced cement concrete (R.C.C)
Grades of concrete:
IS 456:2000 specifies 15 grades of concrete.
Group |
Grade Designation | Specified characteristic compressive strength of 150 mm cube at 28 days (N/mm2) |
Ordinary concrete | M10 | 10 |
M15 | 15 | |
M20 | 20 | |
Standard Concrete | M25 | 25 |
M30 | 30 | |
M35 | 35 | |
M40 | 40 | |
M45 | 45 | |
M50 | 50 | |
M55 | 55 | |
High Strength Concrete | M60 | 60 |
M65 | 65 | |
M70 | 70 | |
M75 | 75 | |
M80 | 80 |
Letter M refers as the Mix and the number to the Specified Characteristic Strength ( ) of 150 mm cube at 28 days (in N/mm2).
Characteristic Strength:
i. It is the strength of the material below which not more than 5 % of the test results are expected to fall.
ii. As per IS 456:2000 minimum grade of concrete shall not be less than M 20 in RCC.
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Answered on 09/12/2017 Learn Civil Engineering Diploma
Arpit Dangarh
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Answered on 07/03/2017 Learn Civil Engineering Diploma
Prashanth Kannadaguli
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Lesson Posted on 22/02/2017 Learn Civil Engineering Diploma
Strain Energy Stored Due To Axial Loading
Raviteja
Let us assume a member with uniform cross section A and of lenth l, be subjected to external axial load W as shown in the figure.
As the load is gradually applied the load is incresed from 0 to W, due to which the member is gradually extended by Δ.
Work done due to load is given by the product of avarage load and the displacement Δ.
work done = 1/2 * W * Δ
Let the tenstion developed in the member be T, @ Equilibrium W = T
Tensile stress (ƒ) = T/A
Tensile strain(e) = ƒ/E = T/AE
Δ = el = S/AE *l]
Strain Energy Stored = Work Done = 1/2*W*Δ = 1/2*T*Tl/AE = T2l/2AE
Strain Energy Stored per unit volume = (T2l/2AE)/V =T2/2A2E=ƒ2/2E)
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Answered on 05/04/2016 Learn Civil Engineering Diploma
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