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Answered on 27 Feb Learn Data Handling
Sadika
Let us assume the heights (in cm) of 10 students of our class as :
120, 122, 125, 137, 139, 150, 142, 133, 145, 158
By observing the above-mentioned values, the highest value is = 158 cm
By observing the above-mentioned values, the lowest value is = 120 cm
The range is the difference between the highest value and the lowest value of the data. It helps in knowing the spread of the data.
Then,
Range of Heights = Highest value – Lowest value
= 158 – 120
= 38 cm
read lessAnswered on 27 Feb Learn Data Handling
Sadika
As per the question, we use the basic definition of parameters of statistics like mean and range to solve the problem.
The given data is as follows,
4, 6, 7, 5, 3, 5, 4, 5, 2, 6, 2, 5, 1, 9, 6, 5, 8, 4, 6, 7
Let's tabulate the data as shown below.
(i)The highest number is 9.
(ii)The lowest number is 1.
read lessAnswered on 27 Feb Learn Data Handling
Sadika
We use the basic formula of average or mean to solve the problem given.
Total numbers = 5
The first five whole numbers are 0, 1, 2, 3, 4
Mean of first five whole numbers = Sum of the first 5 whole numbers / Total numbers
= (0 + 1 + 2 + 3 + 4) / 5
= 10 / 5
= 2
Thus, the mean of the first five whole numbers is 5.
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Answered on 27 Feb Learn Data Handling
Sadika
Answered on 27 Feb Learn Data Handling
Sadika
Answered on 27 Feb Learn Data Handling
Sadika
To find the mean enrollment of the school for the given period, you need to sum up all the enrollments over the six years and then divide by the number of years.
Given enrollments: 1555, 1670, 1750, 2013, 2540, 2820
Step 1: Add up all the enrollments: 1555 + 1670 + 1750 + 2013 + 2540 + 2820 = 11348
Step 2: Count the number of years (which is 6).
Step 3: Calculate the mean by dividing the total enrollment by the number of years: Mean enrollment = Total enrollment / Number of years Mean enrollment = 11348 / 6 Mean enrollment ≈ 1891.333
So, the mean enrollment of the school for the period is approximately 1891.333 students.
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Answered on 27 Feb Learn Data Handling
Sadika
To find the height of the tallest girl and the shortest girl, you simply need to identify the maximum and minimum values from the given data set.
Given heights of 10 girls: 135, 150, 139, 128, 151, 132, 146, 149, 143, 141
(i) The height of the tallest girl is the maximum value from the given data set: Tallest height = 151 cm
(ii) The height of the shortest girl is the minimum value from the given data set: Shortest height = 128 cm
So, the height of the tallest girl is 151 cm, and the height of the shortest girl is 128 cm.
Answered on 27 Feb Learn Data Handling
Sadika
To find the mode and median of the given data set, let's first arrange the scores in ascending order:
5, 9, 10, 12, 15, 16, 19, 20, 20, 20, 20, 23, 24, 25, 25
Now, let's find the mode and median:
Mode: The mode is the value that appears most frequently in the data set.
In this case, the mode is 20 because it appears four times, which is more frequently than any other score.
Median: The median is the middle value of a data set when it's arranged in ascending order.
Since there are 15 scores, the median will be the average of the 8th and 7th scores.
Median = (15th + 16th scores) / 2 Median = (20 + 20) / 2 Median = 20
So, the mode is 20, and the median is also 20.
Therefore, yes, in this case, the mode and median are the same.
Answered on 27 Feb Learn Data Handling
Sadika
To find the mean, mode, and median of the given data set, let's first arrange the runs scored in ascending order:
6, 8, 10, 10, 15, 15, 15, 50, 80, 100, 120
Now, let's calculate the mean, mode, and median:
Mean: The mean is the average of all the values in the data set.
Mean = (6 + 8 + 10 + 10 + 15 + 15 + 15 + 50 + 80 + 100 + 120) / 11 Mean = 451 / 11 Mean ≈ 41
Mode: The mode is the value that appears most frequently in the data set.
In this case, the mode is 15 because it appears three times, which is more frequently than any other score.
Median: The median is the middle value of a data set when it's arranged in ascending order.
Since there are 11 scores, the median will be the 6th score.
Median = 15
So, the mean is approximately 41, the mode is 15, and the median is also 15.
Therefore, in this case, the mode and median are the same, but the mean is different.
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Answered on 27 Feb Learn Data Handling
Sadika
To find the mode and median of the given data set, let's first arrange the weights in ascending order:
32, 35, 36, 37, 38, 38, 38, 40, 42, 43, 43, 43, 45, 47, 50
Now, let's calculate the mode and median:
Mode: The mode is the value that appears most frequently in the data set.
In this case, the mode is 38 because it appears three times, which is more frequently than any other weight.
Median: The median is the middle value of a data set when it's arranged in ascending order.
Since there are 15 weights, the median will be the average of the 8th and 9th weights (since there is an odd number of weights).
Median = (38 + 38) / 2 Median = 38
So, the mode is 38, and the median is also 38.
Therefore, in this case, the mode and median are the same.
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