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Q1(ii):
Compute the magnitude of the following vectors: $\vec{b} = 2\hat{i} - 7\hat{j} - 3\hat{k}$

Solution :

Step 1: Identification of Vector Components

The vector $\vec{b}$ is expressed in terms of its rectangular components in a 3D Cartesian coordinate system:

$\vec{b} = x\hat{i} + y\hat{j} + z\hat{k}$

Given the vector $\vec{b} = 2\hat{i} - 7\hat{j} - 3\hat{k}$, we identify the scalar components as:

  • $x = 2$
  • $y = -7$
  • $z = -3$

Step 2: Mathematical Formulation of Magnitude

The magnitude of a vector $\vec{a} = x\hat{i} + y\hat{j} + z\hat{k}$, denoted by $|\vec{a}|$, is defined as the square root of the sum of the squares of its components [Per the definition of the Euclidean norm in $\mathbb{R}^3$]:

$|\vec{b}| = \sqrt{x^2 + y^2 + z^2}$

Step 3: Execution of Calculation

Substituting the identified values into the magnitude formula:

$|\vec{b}| = \sqrt{(2)^2 + (-7)^2 + (-3)^2}$

$|\vec{b}| = \sqrt{4 + 49 + 9}$

$|\vec{b}| = \sqrt{62}$

Step 4: Vector Visualization

|b| = √62 x y O

Analytical Conclusion

The magnitude represents the scalar length of the vector in Euclidean space. Since $62$ is a square-free integer, the radical form is the most precise representation.

Final Solution: $|\vec{b}| = \sqrt{62}$ units


More Questions from Class 12 Mathematics Vector Algebra EXERCISE 10.2


CBSE Solutions for Class 12 Mathematics Vector Algebra


Chapters in CBSE - Class 12 Mathematics


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