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Q9:
For given vectors, $\vec{a} = 2\hat{i} - \hat{j} + 2\hat{k}$ and $\vec{b} = -\hat{i} + \hat{j} - \hat{k}$, find the unit vector in the direction of the vector $\vec{a} + \vec{b}$.

Solution :

Step 1: Define the Given Vectors

The vectors are provided in component form as follows:

  • $\vec{a} = 2\hat{i} - \hat{j} + 2\hat{k}$
  • $\vec{b} = -\hat{i} + \hat{j} - \hat{k}$

Step 2: Calculate the Resultant Vector $\vec{c} = \vec{a} + \vec{b}$

To find the sum of two vectors, we add their respective components [Per the principle of Vector Addition]:

$\vec{c} = (2 - 1)\hat{i} + (-1 + 1)\hat{j} + (2 - 1)\hat{k}$

$\vec{c} = 1\hat{i} + 0\hat{j} + 1\hat{k}$

$\vec{c} = \hat{i} + \hat{k}$

Step 3: Determine the Magnitude of the Resultant Vector

The magnitude of a vector $\vec{r} = x\hat{i} + y\hat{j} + z\hat{k}$ is defined as $|\vec{r}| = \sqrt{x^2 + y^2 + z^2}$ [By Definition of Euclidean Norm].

$|\vec{c}| = \sqrt{(1)^2 + (0)^2 + (1)^2}$

$|\vec{c}| = \sqrt{1 + 0 + 1} = \sqrt{2}$

Step 4: Compute the Unit Vector $\hat{c}$

The unit vector in the direction of any vector $\vec{v}$ is given by the formula $\hat{v} = \frac{\vec{v}}{|\vec{v}|}$ [Per the definition of normalized vectors].

$\hat{c} = \frac{\vec{c}}{|\vec{c}|} = \frac{\hat{i} + \hat{k}}{\sqrt{2}}$

$\hat{c} = \frac{1}{\sqrt{2}}\hat{i} + 0\hat{j} + \frac{1}{\sqrt{2}}\hat{k}$

Visual Representation of the Resultant Vector

Resultant Vector (c) x z

Final Solution: The unit vector in the direction of $\vec{a} + \vec{b}$ is $\frac{1}{\sqrt{2}}\hat{i} + \frac{1}{\sqrt{2}}\hat{k}$.


More Questions from Class 12 Mathematics Vector Algebra EXERCISE 10.2


CBSE Solutions for Class 12 Mathematics Vector Algebra


Chapters in CBSE - Class 12 Mathematics


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