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Q11:

Find the following integrals 11. $\int \frac{x^3 + 5x^2 - 4}{x^2} dx$

Solution :

Step 1: Decomposition of the Rational Function

Given the integral: $I = \int \frac{x^3 + 5x^2 - 4}{x^2} dx$

To evaluate this, we distribute the denominator $x^2$ to each term in the numerator. This is permissible as $x \neq 0$ [By the property of algebraic division of polynomials]:

$I = \int \left( \frac{x^3}{x^2} + \frac{5x^2}{x^2} - \frac{4}{x^2} \right) dx$

Step 2: Simplification of Terms

Apply the laws of exponents $\frac{x^a}{x^b} = x^{a-b}$ and $\frac{1}{x^n} = x^{-n}$ to simplify the integrand:

$I = \int \left( x + 5 - 4x^{-2} \right) dx$

Step 3: Applying Linearity of Integration

The integral of a sum/difference is the sum/difference of the integrals [Per the Sum/Difference Rule of Integration]. We split the integral into individual components:

$I = \int x \, dx + \int 5 \, dx - \int 4x^{-2} \, dx$

Step 4: Integration Using Power Rule

Apply the Power Rule $\int x^n dx = \frac{x^{n+1}}{n+1} + C$ for $n \neq -1$:

  • $\int x^1 dx = \frac{x^{1+1}}{1+1} = \frac{x^2}{2}$
  • $\int 5 dx = 5x$
  • $\int 4x^{-2} dx = 4 \left( \frac{x^{-2+1}}{-2+1} \right) = 4 \left( \frac{x^{-1}}{-1} \right) = -4x^{-1}$

Step 5: Final Assembly and Integration Constant

Combine the results and include the constant of integration $C$:

$I = \frac{x^2}{2} + 5x - (-4x^{-1}) + C$

$I = \frac{x^2}{2} + 5x + \frac{4}{x} + C$

Integral Domain: x ≠ 0 Graph of Function: f(x) = x + 5 - 4/x²

Final Solution: $\frac{x^2}{2} + 5x + \frac{4}{x} + C$


More Questions from Class 12 Mathematics Integrals EXERCISE 7.1


CBSE Solutions for Class 12 Mathematics Integrals


Chapters in CBSE - Class 12 Mathematics


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