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Q21:

Choose the correct answer 21. The anti derivative of $(\sqrt{x} + \frac{1}{\sqrt{x}})$ equals

Solution :

Given Variables & Initial Setup

We are tasked with finding the antiderivative (indefinite integral) of the function $f(x) = \sqrt{x} + \frac{1}{\sqrt{x}}$.

The integral to be evaluated is:
$I = \int \left( \sqrt{x} + \frac{1}{\sqrt{x}} \right) dx$

Step 1: Algebraic Simplification

To integrate, we express the function using fractional exponents [Per the Laws of Exponents: $\sqrt[n]{x^m} = x^{m/n}$ and $\frac{1}{x^n} = x^{-n}$]:

$\sqrt{x} = x^{1/2}$

$\frac{1}{\sqrt{x}} = \frac{1}{x^{1/2}} = x^{-1/2}$

Substituting these into the integral:
$I = \int (x^{1/2} + x^{-1/2}) dx$

Step 2: Application of Linearity and Power Rule

We utilize the Sum Rule of integration: $\int [f(x) + g(x)] dx = \int f(x) dx + \int g(x) dx$.

$I = \int x^{1/2} dx + \int x^{-1/2} dx$

Applying the Power Rule of integration, which states $\int x^n dx = \frac{x^{n+1}}{n+1} + C$ for $n \neq -1$:

For the first term ($n = 1/2$):
$\int x^{1/2} dx = \frac{x^{1/2 + 1}}{1/2 + 1} = \frac{x^{3/2}}{3/2} = \frac{2}{3}x^{3/2}$

For the second term ($n = -1/2$):
$\int x^{-1/2} dx = \frac{x^{-1/2 + 1}}{-1/2 + 1} = \frac{x^{1/2}}{1/2} = 2x^{1/2}$

Step 3: Assembly and Constant Integration

Combining the results and adding the constant of integration $C$:

$I = \frac{2}{3}x^{3/2} + 2x^{1/2} + C$

Visual Representation of the Power Function Integration

x y f(x) = x^(1/2) + x^(-1/2)

Final Solution

Final Solution: $\frac{2}{3}x^{3/2} + 2\sqrt{x} + C$


More Questions from Class 12 Mathematics Integrals EXERCISE 7.1


CBSE Solutions for Class 12 Mathematics Integrals


Chapters in CBSE - Class 12 Mathematics


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