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Q19:

Find the following integrals 19. $\int \frac{\sec^2 x}{\csc^2 x} dx$

Solution :

Step 1: Trigonometric Simplification

To evaluate the integral $\int \frac{\sec^2 x}{\csc^2 x} dx$, we must first express the integrand in terms of fundamental trigonometric functions, namely $\sin x$ and $\cos x$.

Using the reciprocal identities:

  • $\sec x = \frac{1}{\cos x} \implies \sec^2 x = \frac{1}{\cos^2 x}$ [Reciprocal Identity]
  • $\csc x = \frac{1}{\sin x} \implies \csc^2 x = \frac{1}{\sin^2 x}$ [Reciprocal Identity]

Substituting these into the integrand:

$\frac{\sec^2 x}{\csc^2 x} = \frac{\frac{1}{\cos^2 x}}{\frac{1}{\sin^2 x}} = \frac{1}{\cos^2 x} \cdot \frac{\sin^2 x}{1} = \frac{\sin^2 x}{\cos^2 x}$

Applying the quotient identity, $\frac{\sin x}{\cos x} = \tan x$, we obtain:

$\frac{\sin^2 x}{\cos^2 x} = \tan^2 x$ [Quotient Identity]

Step 2: Algebraic Manipulation for Integration

The standard integral table does not provide a direct primitive for $\tan^2 x$. We utilize the Pythagorean identity to express $\tan^2 x$ in a form that is directly integrable:

$1 + \tan^2 x = \sec^2 x \implies \tan^2 x = \sec^2 x - 1$ [Pythagorean Identity]

Thus, the integral becomes:

$I = \int (\sec^2 x - 1) dx$

Step 3: Execution of the Integration

By the Linearity Property of integrals, we split the expression into two separate integrals:

$I = \int \sec^2 x \, dx - \int 1 \, dx$

Applying the fundamental integration rules:

  • $\int \sec^2 x \, dx = \tan x + C_1$ [Standard Integral Formula]
  • $\int 1 \, dx = x + C_2$ [Power Rule: $\int x^n dx = \frac{x^{n+1}}{n+1}$ where $n=0$]

Combining these, where $C = C_1 - C_2$ is the constant of integration:

$I = \tan x - x + C$

Visual Representation of the Integrand Transformation

Conversion Pathway: f(x) = sec²x / csc²x ⇒ tan²x ⇒ sec²x - 1

Final Solution: $\tan x - x + C$


More Questions from Class 12 Mathematics Integrals EXERCISE 7.1


CBSE Solutions for Class 12 Mathematics Integrals


Chapters in CBSE - Class 12 Mathematics


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