Find the best tutors and institutes for Class 12 Tuition
Q77(vii):
State True or False: The solution of $\frac{dy}{dx} = (\frac{y}{x})^{\frac{1}{3}}$ is $y^{\frac{2}{3}} – x^{\frac{2}{3}} = c$.
Solution :
Step 1: Analyzing the Differential Equation
The given differential equation is a homogeneous first-order differential equation of the form $\frac{dy}{dx} = f\left(\frac{y}{x}\right)$.
Equation: $\frac{dy}{dx} = \left(\frac{y}{x}\right)^{1/3}$
Step 2: Applying the Substitution Method
To solve homogeneous equations, we substitute $y = vx$, which implies $\frac{dy}{dx} = v + x\frac{dv}{dx}$ [Per the standard method for solving homogeneous differential equations].
Substituting into the equation:
$v + x\frac{dv}{dx} = v^{1/3}$
$x\frac{dv}{dx} = v^{1/3} - v$
Step 3: Separating Variables
Rearrange the terms to separate the variables $v$ and $x$:
$\frac{dv}{v^{1/3} - v} = \frac{dx}{x}$
$\frac{dv}{v^{1/3}(1 - v^{2/3})} = \frac{dx}{x}$
Step 4: Integration
To integrate the left side, let $u = v^{1/3}$. Then $u^3 = v$, and differentiating both sides gives $3u^2 du = dv$.
Substituting these into the integral:
$\int \frac{3u^2 du}{u(1 - u^2)} = \int \frac{dx}{x}$
$3 \int \frac{u}{1 - u^2} du = \ln|x| + C$
Let $w = 1 - u^2$, then $dw = -2u du$, or $u du = -\frac{1}{2} dw$:
$3 \left( -\frac{1}{2} \right) \int \frac{dw}{w} = \ln|x| + C$
$-\frac{3}{2} \ln|1 - u^2| = \ln|x| + C$
Step 5: Back-Substitution
Substitute $u^2 = v^{2/3} = \left(\frac{y}{x}\right)^{2/3}$ back into the result:
$-\frac{3}{2} \ln|1 - \frac{y^{2/3}}{x^{2/3}}| = \ln|x| + C$
$-\frac{3}{2} \ln|\frac{x^{2/3} - y^{2/3}}{x^{2/3}}| = \ln|x| + C$
Simplifying the logarithmic expression:
$-\frac{3}{2} [\ln|x^{2/3} - y^{2/3}| - \ln|x^{2/3}|] = \ln|x| + C$
$-\frac{3}{2} \ln|x^{2/3} - y^{2/3}| + \frac{3}{2} \cdot \frac{2}{3} \ln|x| = \ln|x| + C$
$-\frac{3}{2} \ln|x^{2/3} - y^{2/3}| + \ln|x| = \ln|x| + C$
$- \frac{3}{2} \ln|x^{2/3} - y^{2/3}| = C'$
$\ln|x^{2/3} - y^{2/3}| = K$
$x^{2/3} - y^{2/3} = C_1$
Step 6: Comparative Analysis
The derived general solution is $x^{2/3} - y^{2/3} = C_1$. The expression provided in the prompt is $y^{2/3} - x^{2/3} = c$. Since $-(x^{2/3} - y^{2/3}) = y^{2/3} - x^{2/3}$, the constants are simply negatives of each other, which is mathematically consistent for an arbitrary constant of integration.
Final Solution: True. The algebraic structure derived matches the proposed form within the domain of the arbitrary constant $c$.
More Questions from Class 12 Mathematics Differential Equations EXERCISE 9.3
- Q1: Find the solution of $\frac{dy}{dx} = \frac{2y}{x}$.
- Q2: Find the differential equation of all non vertical lines in a plane.
- Q3: Given that $\frac{dy}{dx} = e^{-2y}$ and $y = 0$ when $x = 5$. Find the value of $x$ when $y = 3$.
- Q4: Solve the differential equation $(x^2 – 1) \frac{dy}{dx} + 2xy = \frac{1}{x^2 - 1}$.
- Q5: Solve the differential equation $\frac{dy}{dx} + 2xy = y^2$.
- Q6: Find the general solution of $\frac{dy}{dx} + ay = e^{mx}$.
- Q7: Solve the differential equation $\frac{dy}{dx} + 1 = e^{x+y}$.
- Q8: Solve: $ydx – xdy = x^2ydx$.
- Q9: Solve the differential equation $\frac{dy}{dx} = 1 + x + y^2 + xy^2$, when $y = 0$, $x = 0$.
- Q10: Find the general solution of $(x + 2y^3)\frac{dy}{dx} = y$.
- Q11: If $y(x)$ is a solution of $\frac{dy}{dx} + \frac{2x}{1+x^2}y = \frac{1}{(1+x^2)^2}$ and $y (0) = 1$, then find the value of $y(\frac{\pi}{2})$.
- Q12: If $y(t)$ is a solution of $(1 + t)\frac{dy}{dt} – ty = 1$ and $y (0) = – 1$, then show that $y (1) = –\frac{1}{2}$.
- Q13: Form the differential equation having $y = (\sin^{-1}x)^2 + A\cos^{-1}x + B$, where $A$ and $B$ are arbitrary constants, as its general solution.
- Q14: Form the differential equation of all circles which pass through origin and whose centres lie on y-axis.
- Q15: Find the equation of a curve passing through origin and satisfying the differential equation $(1+x^2)\frac{dy}{dx} + 2xy = 4x^2$.
- Q16: Solve : $x^2\frac{dy}{dx} = x^2 + xy + y^2$.
- Q17: Find the general solution of the differential equation $(1 + y^2) + (x – e^{\tan^{-1}y})\frac{dy}{dx} = 0$.
- Q18: Find the general solution of $y^2dx + (x^2 – xy + y^2) dy = 0$.
- Q19: Solve : $(x + y) (dx – dy) = dx + dy$.[Hint: Substitute $x + y = z$ after seperating $dx$ and $dy$]
- Q20: Solve : $2 (y + 3) – xy\frac{dy}{dx} = 0$, given that $y (1) = – 2$.
- Q21: Solve the differential equation $dy = \cos x (2 – y \csc x) dx$ given that $y = 2$ when $x = \frac{\pi}{2}$.
- Q22: Form the differential equation by eliminating $A$ and $B$ in $Ax^2 + By^2 = 1$.
- Q23: Solve the differential equation $(1 + y^2) \tan^{-1}x dx + 2y (1 + x^2) dy = 0$.
- Q24: Find the differential equation of system of concentric circles with centre (1, 2).
- Q25: Solve : $\frac{d}{dx}(y + xy) = x (\sin x + \log x)$
- Q26: Find the general solution of $(1 + \tan y) (dx – dy) + 2xdy = 0$.
- Q27: Solve : $\frac{dy}{dx} = \cos(x + y) + \sin (x + y)$.[Hint: Substitute $x + y = z$]
- Q28: Find the general solution of $\frac{dy}{dx} - 3y = \sin 2x$.
- Q29: Find the equation of a curve passing through (2, 1) if the slope of the tangent to the curve at any point $(x, y)$ is $\frac{x^2 + y^2}{2xy}$.
- Q30: Find the equation of the curve through the point (1, 0) if the slope of the tangent to the curve at any point $(x, y)$ is $\frac{y-1}{x^2+x}$.
- Q31: Find the equation of a curve passing through origin if the slope of the tangent to the curve at any point $(x, y)$ is equal to the square of the difference of the abcissa and ordinate of the point.
- Q32: Find the equation of a curve passing through the point (1, 1). If the tangent drawn at any point P $(x, y)$ on the curve meets the co-ordinate axes at A and B such that P is the mid-point of AB.
- Q33: Solve : $x\frac{dy}{dx} = y (\log y – \log x + 1)$
- Q34: The degree of the differential equation $(\frac{d^2y}{dx^2})^2 + (\frac{dy}{dx})^2 = x \sin(\frac{dy}{dx})$ is:
- Q35: The degree of the differential equation $[1 + (\frac{dy}{dx})^2]^{\frac{3}{2}} = \frac{d^2y}{dx^2}$ is
- Q36: The order and degree of the differential equation $(\frac{d^2y}{dx^2})^{\frac{1}{2}} + (\frac{dy}{dx})^{\frac{1}{5}} + 4 = 0$, respectively, are
- Q37: If $y = e^{-x} (A\cos x + B\sin x)$, then $y$ is a solution of
- Q38: The differential equation for $y = A\cos \alpha x + B\sin \alpha x$, where $A$ and $B$ are arbitrary constants is
- Q39: Solution of differential equation $xdy – ydx = 0$ represents :
- Q40: Integrating factor of the differential equation $\cos x \frac{dy}{dx} + y\sin x = 1$ is :
- Q41: Solution of the differential equation $\tan y \sec^2x dx + \tan x \sec^2y dy = 0$ is :
- Q42: Family $y = Ax + A^3$ of curves is represented by the differential equation of degree :
- Q43: Integrating factor of $x\frac{dy}{dx} – y = x^4 – 3x$ is :
- Q44: Solution of $\frac{dy}{dx} - y = 1$, $y (0) = 1$ is given by
- Q45: The number of solutions of $\frac{dy}{dx} = \frac{y+1}{x-1}$ when $y (1) = 2$ is :
- Q46: Which of the following is a second order differential equation?
- Q47: Integrating factor of the differential equation $(1 – x^2)\frac{dy}{dx} - xy = 1$ is
- Q48: $\tan^{-1} x + \tan^{-1} y = c$ is the general solution of the differential equation:
- Q49: The differential equation $y\frac{dy}{dx} + x = c$ represents :
- Q50: The general solution of $e^x \cos y dx – e^x \sin y dy = 0$ is :
- Q51: The degree of the differential equation $(\frac{d^2y}{dx^2})^2 + (\frac{dy}{dx})^3 + y^5 + 6 = 0$ is :
- Q52: The solution of $\frac{dy}{dx} + y = e^{-x}, y(0) = 0$ is :
- Q53: Integrating factor of the differential equation $\frac{dy}{dx} + y \tan x - \sec x = 0$ is:
- Q54: The solution of the differential equation $\frac{dy}{dx} = \frac{1+y^2}{1+x^2}$ is:
- Q55: The integrating factor of the differential equation $\frac{dy}{dx} + (1+\frac{1}{x})y = ...$ is:
- Q56: $y = ae^{mx} + be^{-mx}$ satisfies which of the following differential equation?
- Q57: The solution of the differential equation $\cos x \sin y dx + \sin x \cos y dy = 0$ is :
- Q58: The solution of $\frac{dy}{dx} + \frac{y}{x} = e^x$ is:
- Q59: The differential equation of the family of curves $x^2 + y^2 – 2ay = 0$, where $a$ is arbitrary constant, is:
- Q60: Family $y = Ax + A^3$ of curves will correspond to a differential equation of order
- Q61: The general solution of $\frac{dy}{dx} = e^{y-2x}$ is :
- Q62: The curve for which the slope of the tangent at any point is equal to the ratio of the abcissa to the ordinate of the point is :
- Q63: The general solution of the differential equation $\frac{dy}{dx} = e^{x^2} + 2xy$ is :
- Q64: The solution of the equation $(2y – 1) dx – (2x + 3)dy = 0$ is :
- Q65: The differential equation for which $y = a\cos x + b\sin x$ is a solution, is :
- Q66: The solution of $\frac{dy}{dx} + y = e^{-x}, y (0) = 0$ is :
- Q67: The order and degree of the differential equation $(\frac{d^3y}{dx^3})^2 - 3(\frac{d^2y}{dx^2}) + 2(\frac{dy}{dx})^4 = y$ are :
- Q68: The order and degree of the differential equation $[1 + (\frac{dy}{dx})^2]^{\frac{3}{2}} = \frac{d^2y}{dx^2}$ are :
- Q69: The differential equation of the family of curves $y^2 = 4a (x + a)$ is :
- Q70: Which of the following is the general solution of $\frac{d^2y}{dx^2} - 2\frac{dy}{dx} + 2y = 0$ ?
- Q71: General solution of $\frac{dy}{dx} + y \tan x = \sec x$ is :
- Q72: Solution of the differential equation $\frac{dy}{dx} + \frac{y}{x} = \sin x$ is :
- Q73: The general solution of the differential equation $(e^x + 1) ydy = (y + 1) e^x dx$ is:
- Q74: The solution of the differential equation $\frac{dy}{dx} = e^{x-y} + x^2 e^{-y}$ is :
- Q75: The solution of the differential equation $\frac{dy}{dx} + \frac{2xy}{1+x^2} = \frac{1}{(1+x^2)^2}$ is :
- Q76(i): Fill in the blanks: The degree of the differential equation $\frac{d^2y}{dx^2} + e^{\frac{dy}{dx}} = 0$ is _________.
- Q76(ii): Fill in the blanks: The degree of the differential equation $\sqrt{1 + (\frac{dy}{dx})^2} = x$ is _________.
- Q76(iii): Fill in the blanks: The number of arbitrary constants in the general solution of a differential equation of order three is _________.
- Q76(iv): Fill in the blanks: $\frac{dy}{dx} + \frac{y}{x\log x} = \frac{1}{x}$ is an equation of the type _________.
- Q76(ix): Fill in the blanks: General solution of $\frac{dy}{dx} + \frac{y}{x} = \sin x$ is _________.
- Q76(v): Fill in the blanks: General solution of the differential equation of the type $\frac{dx}{dy} + P_1 x = Q_1$ is given by _________.
- Q76(vi): Fill in the blanks: The solution of the differential equation $x\frac{dy}{dx} + 2y = x^2$ is _________.
- Q76(vii): Fill in the blanks: The solution of $(1 + x^2) \frac{dy}{dx} +2xy – 4x^2 = 0$ is _________.
- Q76(viii): Fill in the blanks: The solution of the differential equation $ydx + (x + xy)dy = 0$ is ______.
- Q76(x): Fill in the blanks: The solution of differential equation $\cot y dx = xdy$ is _________.
- Q76(xi): Fill in the blanks: The integrating factor of $\frac{dy}{dx} + \frac{y}{x(y+1)} = 1$ is _________.
- Q77(i): State True or False: Integrating factor of the differential of the form $\frac{dx}{dy} + p_1 x = Q_1$ is given by $e^{\int p_1 dy}$.
- Q77(ii): State True or False: Solution of the differential equation of the type $\frac{dx}{dy} + p_1 x = Q_1$ is given by $x \cdot I.F. = \int (Q_1 \times I.F.) dy$.
- Q77(iii): State True or False: Correct substitution for the solution of the differential equation of the type $\frac{dy}{dx} = f(x, y)$, where $f (x, y)$ is a homogeneous function of zero degree is $y = vx$.
- Q77(iv): State True or False: Correct substitution for the solution of the differential equation of the type $\frac{dx}{dy} = g(x, y)$ where $g(x, y)$ is a homogeneous function of the degree zero is $x = vy$.
- Q77(ix): State True or False: The solution of the differential equation $\frac{dy}{dx} = \frac{x+2y}{x}$ is $x + y = kx^2$.
- Q77(v): State True or False: Number of arbitrary constants in the particular solution of a differential equation of order two is two.
- Q77(vi): State True or False: The differential equation representing the family of circles $x^2 + (y – a)^2 = a^2$ will be of order two.
- Q77(viii): State True or False: Differential equation representing the family of curves $y = e^x (A\cos x + B\sin x)$ is $\frac{d^2y}{dx^2} – 2\frac{dy}{dx} + 2y = 0$.
- Q77(x): State True or False: Solution of $\frac{dy}{dx} = \frac{y}{x} + \tan(\frac{y}{x})$ is $\sin(\frac{y}{x}) = cx$.
- Q77(xi): State True or False: The differential equation of all non horizontal lines in a plane is $\frac{d^2x}{dy^2} = 0$.
CBSE Solutions for Class 12 Mathematics Differential Equations
Chapters in CBSE - Class 12 Mathematics
Top Tutors who teach Differential Equations
I am an AI-enabled Social Science educator with experience teaching Grades 6–10 at Physics Wallah. I specialize in simplifying complex concepts through visual PPT-based learning, storytelling, and engaging teaching methods. With a strong focus on conceptual clarity and student engagement, I also integrate AI tools to create modern, effective learning experiences. My goal is to make Social Science easy, interesting, and relatable for every student.
Very Good experience.
My Qualification : M.com., M.A., M.Phil., M.Ed I have total 30+ years of experience handling following subjects : 1] Accountancy 2] Cost Accountancy 3] Management Accountancy 4] Business Management 5] English for B.Ed only For the following Degrees : B.Com, B.B.A., M.B.A., +1 & +2 [Commerce and Accountancy] Rich Teaching Experoences i various colleges.
I have both experience and knowledge in tutoring of Mathematics. I have been giving tutoring for last 10 years. I have a great academic record both at school and college level. I believe in making the student understand the concept which is important from exam point of view also and also for future growth of student Personal attention with quality learning can provide you better understanding of concepts. This is what I want to ensure to the students so that I will be able to make difference between their past, present and future. I am also a good motivator and a creative person as well. So, it will help the students to learn the concepts clearly. I find satisfaction in making students understand their subjects by making them finding their own areas of strength. As I qualified GATE and have a good exposure of lab so I know the level of topics and questions ask in competitive exams. I am motivated person so always try to appreciate and boost my students. Good in communications. My focus will be on developing a strong base of each and every subject taught to the student. Innovative techniques of learning will be introduced based on the efficiency of the student to grasp the subject matter. Another area of focus would be helping the students to strategies methodology for self-study purpose. Adequate time will be provided and clearing doubts will always be the top priority. Fluency in all subjects is assured.
He is an excellent math teacher. He is very cooperative, and helpful. Having very good knowledge of his subject.
I'm a mathematics' teacher. My goal is to teach you how you can think out a solution rather than roboting your way out. We will dive deep into concepts of mathematics and come out as a well learned and scrupulous student. I am ready to clear your hurdles with most accurate way. I have taught at many academies for JEE preparations. In addition to it I have taught online in UrbanPro from past 4 years.
Suman is an awesome teacher and connects well with the student and gets them to grasp concepts and be interested in the subject. Highly recommend him for math.
PHYSICS TUTORING WITH A PHYSICS EXPERT: STRATEGIES THAT MAKE SENSE FOR YOU! ABOUT SUBJECT Students will receive personalized instruction from a Physics expert. We will use the most successfully proven teaching techniques, and will also create brand new strategies to fit the students' individual needs. DESCRIPTION In this private tutoring session, I will thoroughly explain whatever Physics concepts you are currently struggling with, or we can learn new topics if you want to get ahead. I have taught Physics for over 5 years, and I am passionate about helping students understand it. Just name a topic of Physics (Mechanics, Heat, Wave, Electromagnetism, Modern Physics), and I will explain it in a way that makes the most sense to you. Then we will complete practice problems together to make sure you feel confident moving forward. I will also develop individualized strategies for you to use moving forward. Don't be surprised if I get really excited about the information you're learning - PHYSICS MAKES ME HAPPY AND I HOPE MY ENJOYMENT OF THE SUBJECT MAKES IT LESS INTIMIDATING TO YOU. Physics isn't your enemy; you just need someone to explain it in a way you understand. Please let me! Teacher Expertise I have a B.Tech degree in Computer Science and I have been teaching Physics exclusively for the past 5 years. ABOUT ME I am a Physics lover through and through! I've always said “PHYSICS DOESN'T HAVE TO BE HARD; YOU JUST NEED SOMEONE TO EXPLAIN IT IN A WAY YOU UNDERSTAND." I can do that! I’m passionate about helping students gain confidence and mastery in Physics. Physics is my favorite subjects, so you'll see me get really excited about them! When I teach, I customize my strategies to fit your individual needs, and I have so many tricks up my sleeve for teaching Physics concepts, I can always find a method that works for you. And of course, it is especially important to me to make sure every student feels safe to make mistakes in my class – we celebrate mistakes! The only way to master Physics is to learn from your mistakes! I've taught JEE & NEET Physics online for 5 years and in coaching industry for over 5 years. It's a real pleasure to help students achieve their goals in IIT-JEE & NEET.
I have joined for NEET preparation and got 595 marks. You help me alot how to prepare and how to manage my time to prepare NEET exam. One thing which is great motivation for me is- In the NEET EXAM first you learn what they asked, what is the weightage marks asked in exam, I go through it. Here some fundamental chapters are important in physics and you clear it first and after that whole physics look like easy for me. Thank a lot to clear my mechanics and electrostatics which is tough part in this, also thanks for all chapters which goes easy for me and I got success in NEET.
Other Subjects in CBSE - Class 12
Download free CBSE - Class 12 Mathematics Differential Equations EXERCISE 9.3 worksheets
Download Now