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Q1.23(i):
Suggest the most important type of intermolecular attractive interaction in the following pairs. (i) n-hexane and n-octane

Solution :

Step 1: Analyzing Molecular Structure

To determine the nature of the intermolecular forces, we must first analyze the chemical composition and structural characteristics of the two components:

  • n-hexane ($C_6H_{14}$): A straight-chain alkane. It consists of a non-polar hydrocarbon backbone where the electronegativity difference between Carbon ($\chi \approx 2.55$) and Hydrogen ($\chi \approx 2.20$) is minimal ($\Delta\chi \approx 0.35$). [Per the Pauling Scale of electronegativity].
  • n-octane ($C_8H_{18}$): A straight-chain alkane. Similarly, it is composed of non-polar $C-C$ and $C-H$ bonds.

Step 2: Evaluating Molecular Polarity

Because both molecules consist solely of $C$ and $H$ atoms arranged in symmetric, non-polar chains, the net dipole moment ($\mu$) for both molecules is essentially zero ($\mu = 0$). [By the principle of molecular vector summation]. Consequently, these molecules cannot participate in dipole-dipole interactions or hydrogen bonding.

Step 3: Identification of Intermolecular Force

Since both substances are non-polar, the only available attractive forces arise from the temporary fluctuations in electron density within the electron clouds, which induce instantaneous dipoles in adjacent molecules. These are known as London Dispersion Forces (or induced dipole-induced dipole interactions).

Molecule A (n-hexane) Molecule B (n-octane) London Dispersion Forces

Step 4: Theoretical Justification

The interaction between two non-polar species is governed by the London Dispersion Force, which is characterized by:

  • Instantaneous Polarization: Even in non-polar molecules, electrons are in constant motion, creating temporary asymmetric distributions.
  • Induced Polarity: An instantaneous dipole in one molecule induces a corresponding dipole in the neighboring molecule.
  • Magnitude: The strength of these forces increases with the surface area of the molecule and the number of electrons (polarizability), which is why both substances exist as liquids at standard conditions [Per the properties of Van der Waals forces].

Final Solution: The most important type of intermolecular attractive interaction between n-hexane and n-octane is London Dispersion Forces (also known as induced dipole-induced dipole interactions).


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