Find the best tutors and institutes for Class 12 Tuition
Q1.10:
What role does the molecular interaction play in a solution of alcohol and water?
Solution :
1. Theoretical Foundation of Molecular Interactions
In a solution of alcohol (e.g., ethanol, $C_2H_5OH$) and water ($H_2O$), the thermodynamic behavior of the mixture is governed by the nature and strength of the intermolecular forces (IMFs) present in the pure components versus the binary solution. Both substances are polar and exhibit extensive hydrogen bonding.
2. Analysis of Intermolecular Forces (IMFs)
To understand the role of these interactions, we categorize them into two distinct states:
| State | Predominant Interactions |
|---|---|
| Pure Ethanol | $O-H \cdots O$ hydrogen bonding between ethanol molecules. |
| Pure Water | $O-H \cdots O$ hydrogen bonding between water molecules. |
| Ethanol-Water Solution | New $O-H \cdots O$ hydrogen bonds between the hydroxyl group of ethanol and the water molecules. |
3. Deviation from Raoult's Law
When ethanol is added to water, the interaction between ethanol and water molecules is weaker than the hydrogen bonding present in pure water. [Per the principles of non-ideal solutions]:
- The solute-solvent interaction ($A-B$) is weaker than the solvent-solvent ($A-A$) and solute-solute ($B-B$) interactions.
- This leads to an increase in the escaping tendency of the molecules from the surface of the liquid.
- Consequently, the solution exhibits positive deviation from Raoult’s Law.
4. Thermodynamic Consequences
The role of these molecular interactions manifests in specific macroscopic properties:
A. Vapor Pressure: Due to the weaker interaction in the mixture compared to pure components, the molecules escape more easily into the vapor phase, resulting in a total vapor pressure higher than that predicted by Raoult's Law ($P_{total} > P_A^o X_A + P_B^o X_B$).
B. Enthalpy of Mixing ($\Delta_{mix} H$): Energy must be absorbed to break the stronger hydrogen bonds in pure water and pure alcohol, while less energy is released upon forming the weaker ethanol-water interactions. Therefore, the process is endothermic ($\Delta_{mix} H > 0$).
C. Volume of Mixing ($\Delta_{mix} V$): The disruption of the hydrogen-bonded networks leads to an increase in the average distance between molecules, resulting in an expansion of the solution ($\Delta_{mix} V > 0$).
5. Visual Representation of Hydrogen Bonding
Final Solution: The molecular interaction between alcohol and water is characterized by the formation of new hydrogen bonds that are weaker than the existing hydrogen bonds in pure water. This causes the solution to exhibit positive deviation from Raoult’s Law, resulting in an increase in total vapor pressure, a positive enthalpy of mixing ($\Delta_{mix} H > 0$), and a positive volume of mixing ($\Delta_{mix} V > 0$).
More Questions from Class 12 Chemistry Solutions Exercises
- Q1.1: Define the term solution. How many types of solutions are formed? Write briefly about each type with an example.
- Q1.1: Define the term solution. How many types of solutions are formed? Write briefly about each type with an example.
- Q1.10: What role does the molecular interaction play in a solution of alcohol and water?
- Q1.11: Why do gases always tend to be less soluble in liquids as the temperature is raised?
- Q1.11: Why do gases always tend to be less soluble in liquids as the temperature is raised?
- Q1.12: State Henry’s law and mention some important applications.
- Q1.12: State Henry’s law and mention some important applications.
- Q1.13: The partial pressure of ethane over a solution containing \(6.56 \times 10^{-3}\) g of ethane is 1 bar. If the solution contains \(5.00 \times 10^{-2}\) g of ethane, then what shall be the partial pressure of the gas?
- Q1.13: The partial pressure of ethane over a solution containing (6.56 \times 10^{-3}) g of ethane is 1 bar. If the solution contains (5.00 \times 10^{-2}) g of ethane, then what shall be the partial pressure of the gas?
- Q1.14: What is meant by positive and negative deviations from Raoult's law and how is the sign of \(\Delta_{mix}H\) related to positive and negative deviations from Raoult's law?
- Q1.14: What is meant by positive and negative deviations from Raoult's law and how is the sign of (\Delta_{mix}H) related to positive and negative deviations from Raoult's law?
- Q1.15: An aqueous solution of 2% non-volatile solute exerts a pressure of 1.004 bar at the normal boiling point of the solvent. What is the molar mass of the solute?
- Q1.15: An aqueous solution of 2% non-volatile solute exerts a pressure of 1.004 bar at the normal boiling point of the solvent. What is the molar mass of the solute?
- Q1.16: Heptane and octane form an ideal solution. At 373 K, the vapour pressures of the two liquid components are 105.2 kPa and 46.8 kPa respectively. What will be the vapour pressure of a mixture of 26.0 g of heptane and 35 g of octane?
- Q1.16: Heptane and octane form an ideal solution. At 373 K, the vapour pressures of the two liquid components are 105.2 kPa and 46.8 kPa respectively. What will be the vapour pressure of a mixture of 26.0 g of heptane and 35 g of octane?
- Q1.17: The vapour pressure of water is 12.3 kPa at 300 K. Calculate vapour pressure of 1 molal solution of a non-volatile solute in it.
- Q1.17: The vapour pressure of water is 12.3 kPa at 300 K. Calculate vapour pressure of 1 molal solution of a non-volatile solute in it.
- Q1.18: Calculate the mass of a non-volatile solute (molar mass 40 g \(mol^{-1}\)) which should be dissolved in 114 g octane to reduce its vapour pressure to 80%.
- Q1.18: Calculate the mass of a non-volatile solute (molar mass 40 (g mol^{-1})) which should be dissolved in 114 g octane to reduce its vapour pressure to 80%.
- Q1.19 (i): A solution containing 30 g of non-volatile solute exactly in 90 g of water has a vapour pressure of 2.8 kPa at 298 K. Further, 18 g of water is then added to the solution and the new vapour pressure becomes 2.9 kPa at 298 K. Calculate: (i) molar mass of the solute
- Q1.19 (ii): A solution containing 30 g of non-volatile solute exactly in 90 g of water has a vapour pressure of 2.8 kPa at 298 K. Further, 18 g of water is then added to the solution and the new vapour pressure becomes 2.9 kPa at 298 K. Calculate: (ii) vapour pressure of water at 298 K.
- Q1.19(i): A solution containing 30 g of non-volatile solute exactly in 90 g of water has a vapour pressure of 2.8 kPa at 298 K. Further, 18 g of water is then added to the solution and the new vapour pressure becomes 2.9 kPa at 298 K. Calculate: (i) molar mass of the solute
- Q1.19(ii): A solution containing 30 g of non-volatile solute exactly in 90 g of water has a vapour pressure of 2.8 kPa at 298 K. Further, 18 g of water is then added to the solution and the new vapour pressure becomes 2.9 kPa at 298 K. Calculate: (ii) vapour pressure of water at 298 K.
- Q1.2: Give an example of a solid solution in which the solute is a gas.
- Q1.2: Give an example of a solid solution in which the solute is a gas.
- Q1.20: A 5% solution (by mass) of cane sugar in water has freezing point of 271K. Calculate the freezing point of 5% glucose in water if freezing point of pure water is 273.15 K.
- Q1.20: A 5% solution (by mass) of cane sugar in water has freezing point of 271K. Calculate the freezing point of 5% glucose in water if freezing point of pure water is 273.15 K.
- Q1.21: Two elements \(A\) and \(B\) form compounds having formula \(AB_{2}\) and \(AB_{4}\). When dissolved in 20 g of benzene (\(C_{6}H_{6}\)), 1 g of \(AB_{2}\) lowers the freezing point by 2.3 K whereas 1.0 g of \(AB_{4}\) lowers it by 1.3 K. The molar depression constant for benzene is 5.1 K kg \(mol^{-1}\). Calculate atomic masses of \(A\) and \(B\).
- Q1.21: Two elements (A) and (B) form compounds having formula (AB_{2}) and (AB_{4}). When dissolved in 20 g of benzene ((C_{6}H_{6})), 1 g of (AB_{2}) lowers the freezing point by 2.3 K whereas 1.0 g of (AB_{4}) lowers it by 1.3 K. The molar depression constant for benzene is 5.1 K kg mol–1. Calculate atomic masses of (A) and (B).
- Q1.22: At 300 K, 36 g of glucose present in a litre of its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of the solution is 1.52 bars at the same temperature, what would be its concentration?
- Q1.22: At 300 K, 36 g of glucose present in a litre of its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of the solution is 1.52 bars at the same temperature, what would be its concentration?
- Q1.23 (i): Suggest the most important type of intermolecular attractive interaction in the following pairs. (i) n-hexane and n-octane
- Q1.23 (ii): Suggest the most important type of intermolecular attractive interaction in the following pairs. (ii) \(I_{2}\) and \(CCl_{4}\)
- Q1.23 (iii): Suggest the most important type of intermolecular attractive interaction in the following pairs. (iii) \(NaClO_{4}\) and water
- Q1.23 (iv): Suggest the most important type of intermolecular attractive interaction in the following pairs. (iv) methanol and acetone
- Q1.23 (v): Suggest the most important type of intermolecular attractive interaction in the following pairs. (v) acetonitrile (\(CH_{3}CN\)) and acetone (\(C_{3}H_{6}O\)).
- Q1.23(i): Suggest the most important type of intermolecular attractive interaction in the following pairs. (i) n-hexane and n-octane
- Q1.23(ii): Suggest the most important type of intermolecular attractive interaction in the following pairs. (ii) (I_{2}) and (CCl_{4})
- Q1.23(iii): Suggest the most important type of intermolecular attractive interaction in the following pairs. (iii) (NaClO_{4}) and water
- Q1.23(iv): Suggest the most important type of intermolecular attractive interaction in the following pairs. (iv) methanol and acetone
- Q1.23(v): Suggest the most important type of intermolecular attractive interaction in the following pairs. (v) acetonitrile ((CH_{3}CN)) and acetone ((C_{3}H_{6}O)).
- Q1.24: Based on solute-solvent interactions, arrange the following in order of increasing solubility in n-octane and explain. Cyclohexane, KCl, \(CH_{3}OH\), \(CH_{3}CN\).
- Q1.24: Based on solute-solvent interactions, arrange the following in order of increasing solubility in n-octane and explain. Cyclohexane, (KCl), (CH_{3}OH), (CH_{3}CN).
- Q1.25 (i): Amongst the following compounds, identify which are insoluble, partially soluble and highly soluble in water? (i) phenol
- Q1.25 (ii): Amongst the following compounds, identify which are insoluble, partially soluble and highly soluble in water? (ii) toluene
- Q1.25 (iii): Amongst the following compounds, identify which are insoluble, partially soluble and highly soluble in water? (iii) formic acid
- Q1.25 (iv): Amongst the following compounds, identify which are insoluble, partially soluble and highly soluble in water? (iv) ethylene glycol
- Q1.25 (v): Amongst the following compounds, identify which are insoluble, partially soluble and highly soluble in water? (v) chloroform
- Q1.25 (vi): Amongst the following compounds, identify which are insoluble, partially soluble and highly soluble in water? (vi) pentanol.
- Q1.25(i): Amongst the following compounds, identify which are insoluble, partially soluble and highly soluble in water? (i) phenol
- Q1.25(ii): Amongst the following compounds, identify which are insoluble, partially soluble and highly soluble in water? (ii) toluene
- Q1.25(iii): Amongst the following compounds, identify which are insoluble, partially soluble and highly soluble in water? (iii) formic acid
- Q1.25(iv): Amongst the following compounds, identify which are insoluble, partially soluble and highly soluble in water? (iv) ethylene glycol
- Q1.25(v): Amongst the following compounds, identify which are insoluble, partially soluble and highly soluble in water? (v) chloroform
- Q1.25(vi): Amongst the following compounds, identify which are insoluble, partially soluble and highly soluble in water? (vi) pentanol.
- Q1.26: If the density of some lake water is 1.25g \(mL^{-1}\) and contains 92 g of \(Na^{+}\) ions per kg of water, calculate the molarity of \(Na^{+}\) ions in the lake.
- Q1.26: If the density of some lake water is 1.25g (mL^{-1}) and contains 92 g of (Na^{+}) ions per kg of water, calculate the molarity of (Na^{+}) ions in the lake.
- Q1.27: If the solubility product of CuS is \(6 \times 10^{-16}\), calculate the maximum molarity of CuS in aqueous solution.
- Q1.27: If the solubility product of CuS is (6 \times 10^{-16}), calculate the maximum molarity of CuS in aqueous solution.
- Q1.28: Calculate the mass percentage of aspirin (\(C_{9}H_{8}O_{4}\)) in acetonitrile (\(CH_{3}CN\)) when 6.5 g of \(C_{9}H_{8}O_{4}\) is dissolved in 450 g of \(CH_{3}CN\).
- Q1.28: Calculate the mass percentage of aspirin ((C_{9}H_{8}O_{4})) in acetonitrile ((CH_{3}CN)) when 6.5 g of (C_{9}H_{8}O_{4}) is dissolved in 450 g of (CH_{3}CN).
- Q1.29: Nalorphene (\(C_{19}H_{21}NO_{3}\)), similar to morphine, is used to combat withdrawal symptoms in narcotic users. Dose of nalorphene generally given is 1.5 mg. Calculate the mass of \(1.5 \times 10^{-3}\) m aqueous solution required for the above dose.
- Q1.29: Nalorphene ((C_{19}H_{21}NO_{3})), similar to morphine, is used to combat withdrawal symptoms in narcotic users. Dose of nalorphene generally given is 1.5 mg. Calculate the mass of (1.5 \times 10^{-3} m) aqueous solution required for the above dose.
- Q1.3 (i): Define the following terms: (i) Mole fraction
- Q1.3 (ii): Define the following terms: (ii) Molality
- Q1.3 (iii): Define the following terms: (iii) Molarity
- Q1.3 (iv): Define the following terms: (iv) Mass percentage.
- Q1.3(i): Define the following terms: (i) Mole fraction
- Q1.3(ii): Define the following terms: (ii) Molality
- Q1.3(iii): Define the following terms: (iii) Molarity
- Q1.3(iv): Define the following terms: (iv) Mass percentage.
- Q1.30: Calculate the amount of benzoic acid (\(C_{6}H_{5}COOH\)) required for preparing 250 mL of 0.15 M solution in methanol.
- Q1.30: Calculate the amount of benzoic acid ((C_{6}H_{5}COOH)) required for preparing 250 mL of 0.15 M solution in methanol.
- Q1.31: The depression in freezing point of water observed for the same amount of acetic acid, trichloroacetic acid and trifluoroacetic acid increases in the order given above. Explain briefly.
- Q1.31: The depression in freezing point of water observed for the same amount of acetic acid, trichloroacetic acid and trifluoroacetic acid increases in the order given above. Explain briefly.
- Q1.32: Calculate the depression in the freezing point of water when 10 g of \(CH_{3}CH_{2}CHClCOOH\) is added to 250 g of water. \(K_{a} = 1.4 \times 10^{-3}\), \(K_{f} = 1.86\) K kg \(mol^{-1}\).
- Q1.32: Calculate the depression in the freezing point of water when 10 g of (CH_{3}CH_{2}CHClCOOH) is added to 250 g of water. (K_{a} = 1.4 \times 10^{-3}), (K_{f} = 1.86 K kg mol^{-1}).
- Q1.33: 19.5 g of \(CH_{2}FCOOH\) is dissolved in 500 g of water. The depression in the freezing point of water observed is 1.00 C. Calculate the van’t Hoff factor and dissociation constant of fluoroacetic acid.
- Q1.33: 19.5 g of (CH_{2}FCOOH) is dissolved in 500 g of water. The depression in the freezing point of water observed is (1.0^{\circ}C). Calculate the van’t Hoff factor and dissociation constant of fluoroacetic acid.
- Q1.34: Vapour pressure of water at 293 K is 17.535 mm Hg. Calculate the vapour pressure of water at 293 K when 25 g of glucose is dissolved in 450 g of water.
- Q1.34: Vapour pressure of water at 293 K is 17.535 mm Hg. Calculate the vapour pressure of water at 293 K when 25 g of glucose is dissolved in 450 g of water.
- Q1.35: Henry’s law constant for the molality of methane in benzene at 298 K is \(4.27 \times 10^{5}\) mm Hg. Calculate the solubility of methane in benzene at 298 K under 760 mm Hg.
- Q1.35: Henry’s law constant for the molality of methane in benzene at 298 K is (4.27 \times 10^{5}) mm Hg. Calculate the solubility of methane in benzene at 298 K under 760 mm Hg.
- Q1.36: 100 g of liquid A (molar mass 140 g \(mol^{-1}\)) was dissolved in 1000 g of liquid B (molar mass 180 g \(mol^{-1}\)). The vapour pressure of pure liquid B was found to be 500 torr. Calculate the vapour pressure of pure liquid A and its vapour pressure in the solution if the total vapour pressure of the solution is 475 Torr.
- Q1.36: 100 g of liquid A (molar mass 140 (g mol^{-1})) was dissolved in 1000 g of liquid B (molar mass 180 (g mol^{-1})). The vapour pressure of pure liquid (B) was found to be 500 torr. Calculate the vapour pressure of pure liquid (A) and its vapour pressure in the solution if the total vapour pressure of the solution is 475 Torr.
- Q1.37: Vapour pressures of pure acetone and chloroform at 328 K are 741.8 mm Hg and 632.8 mm Hg respectively. Assuming that they form ideal solution over the entire range of composition, plot \(p_{total}\), \(p_{chloroform}\), and \(p_{acetone}\) as a function of \(x_{acetone}\). The experimental data observed for different compositions of mixture is: Plot this data also on the same graph paper. Indicate whether it has positive deviation or negative deviation from the ideal solution.
- Q1.37: Vapour pressures of pure acetone and chloroform at 328 K are 741.8 mm Hg and 632.8 mm Hg respectively. Assuming that they form ideal solution over the entire range of composition, plot (p_{total}), (p_{chloroform}), and (p_{acetone}) as a function of (x_{acetone}). The experimental data observed for different compositions of mixture is: Plot this data also on the same graph paper. Indicate whether it has positive deviation or negative deviation from the ideal solution.
- Q1.38: Benzene and toluene form ideal solution over the entire range of composition. The vapour pressure of pure benzene and toluene at 300 K are 50.71 mm Hg and 32.06 mm Hg respectively. Calculate the mole fraction of benzene in vapour phase if 80 g of benzene is mixed with 100 g of toluene.
- Q1.38: Benzene and toluene form ideal solution over the entire range of composition. The vapour pressure of pure benzene and toluene at 300 K are 50.71 mm Hg and 32.06 mm Hg respectively. Calculate the mole fraction of benzene in vapour phase if 80 g of benzene is mixed with 100 g of toluene.
- Q1.39: The air is a mixture of a number of gases. The major components are oxygen and nitrogen with approximate proportion of 20% is to 79% by volume at 298 K. The water is in equilibrium with air at a pressure of 10 atm. At 298 K if the Henry’s law constants for oxygen and nitrogen at 298 K are \(3.30 \times 10^{7}\) mm and \(6.51 \times 10^{7}\) mm respectively, calculate the composition of these gases in water.
- Q1.39: The air is a mixture of a number of gases. The major components are oxygen and nitrogen with approximate proportion of 20% is to 79% by volume at 298 K. The water is in equilibrium with air at a pressure of 10 atm. At 298 K if the Henry’s law constants for oxygen and nitrogen at 298 K are (3.30 \times 10^{7}) mm and (6.51 \times 10^{7}) mm respectively, calculate the composition of these gases in water.
- Q1.4: Concentrated nitric acid used in laboratory work is 68% nitric acid by mass in aqueous solution. What should be the molarity of such a sample of the acid if the density of the solution is 1.504 g \(mL^{-1}\)?
- Q1.4: Concentrated nitric acid used in laboratory work is 68% nitric acid by mass in aqueous solution. What should be the molarity of such a sample of the acid if the density of the solution is 1.504 g mL–1?
- Q1.40: Determine the amount of \(CaCl_{2}\) (\(i\) = 2.47) dissolved in 2.5 litre of water such that its osmotic pressure is 0.75 atm at 27° C.
- Q1.40: Determine the amount of (CaCl_{2}) ((i = 2.47)) dissolved in 2.5 litre of water such that its osmotic pressure is 0.75 atm at (27^{\circ} C).
- Q1.41: Determine the osmotic pressure of a solution prepared by dissolving 25 mg of \(K_{2}SO_{4}\) in 2 litre of water at 25° C, assuming that it is completely dissociated.
- Q1.41: Determine the osmotic pressure of a solution prepared by dissolving 25 mg of (K_{2}SO_{4}) in 2 litre of water at (25^{\circ} C), assuming that it is completely dissociated.
- Q1.5: A solution of glucose in water is labelled as 10% w/w, what would be the molality and mole fraction of each component in the solution? If the density of solution is 1.2 g \(mL^{-1}\), then what shall be the molarity of the solution?
- Q1.5: A solution of glucose in water is labelled as 10% w/w, what would be the molality and mole fraction of each component in the solution? If the density of solution is 1.2 g mL–1, then what shall be the molarity of the solution?
- Q1.6: How many mL of 0.1 M HCl are required to react completely with 1 g mixture of \(Na_{2}CO_{3}\) and \(NaHCO_{3}\) containing equimolar amounts of both?
- Q1.6: How many mL of 0.1 M HCl are required to react completely with 1 g mixture of (Na_{2}CO_{3}) and (NaHCO_{3}) containing equimolar amounts of both?
- Q1.7: A solution is obtained by mixing 300 g of 25% solution and 400 g of 40% solution by mass. Calculate the mass percentage of the resulting solution.
- Q1.7: A solution is obtained by mixing 300 g of 25% solution and 400 g of 40% solution by mass. Calculate the mass percentage of the resulting solution.
- Q1.8: An antifreeze solution is prepared from 222.6 g of ethylene glycol (\(C_{2}H_{6}O_{2}\)) and 200 g of water. Calculate the molality of the solution. If the density of the solution is 1.072 g \(mL^{-1}\), then what shall be the molarity of the solution?
- Q1.8: An antifreeze solution is prepared from 222.6 g of ethylene glycol ((C_{2}H_{6}O_{2})) and 200 g of water. Calculate the molality of the solution. If the density of the solution is 1.072 g mL–1, then what shall be the molarity of the solution?
- Q1.9 (i): A sample of drinking water was found to be severely contaminated with chloroform (\(CHCl_{3}\)) supposed to be a carcinogen. The level of contamination was 15 ppm (by mass): (i) express this in percent by mass
- Q1.9 (ii): A sample of drinking water was found to be severely contaminated with chloroform (\(CHCl_{3}\)) supposed to be a carcinogen. The level of contamination was 15 ppm (by mass): (ii) determine the molality of chloroform in the water sample.
- Q1.9(i): A sample of drinking water was found to be severely contaminated with chloroform ((CHCl_{3})) supposed to be a carcinogen. The level of contamination was 15 ppm (by mass): (i) express this in percent by mass
- Q1.9(ii): A sample of drinking water was found to be severely contaminated with chloroform ((CHCl_{3})) supposed to be a carcinogen. The level of contamination was 15 ppm (by mass): (ii) determine the molality of chloroform in the water sample.
CBSE Solutions for Class 12 Chemistry Solutions
Chapters in CBSE - Class 12 Chemistry
Top Tutors who teach Solutions
I feel myself God-blessed, having been able to guide thousands of students/learners English, as a school subject as well as a language since 1992. I'm glad to notice that these learners have not only been doing well in their respective areas but also excelling in the real-life situations. May God bless them!!
My one-on-one tutoring experience in English and French was exceptional. The lessons were customized to my learning style and pace, which made a huge difference. My tutor was patient and skilled, offering clear explanations that helped me better understand grammar and improve my speaking abilities in both languages. The sessions were engaging, with interactive exercises and valuable feedback that kept me motivated. I've gained confidence in using English and French daily, and I highly recommend this personalized tutoring service!
I am actively teaching physics up to class XII ( including JEE and NEET aspirants) from last 8 years. I run my own Tuition center where I provide physics class to NEET and IIT JEE aspirants and provide home Tuitions to deserving students. There is a separate doubt clearance & numerical problem solving batch for candidate who already joined Aakash, fiit jee, Allen and other coaching institutes.
Even if you have weak fundamental knowledge in chemistry at the beginning of class 12th, you don't have to be worried if you come under my tutelage. I have many students that feel scared from chemistry before they start taking my classes but I structure my course in such a way that they start enjoying Chemistry and their conceptual knowledge of class 11th also becomes good so that they can prepare for competitive exams easily.
A sincerity ,very professional and approachable attitude has helped my daughter to grasp the basics of class 12 chemistry and as my daughter was slightly behind the syllabus extra classes are being conducted to cover the syllabus. The cryptic and holistic notes also have helped a lot I am hopeful that my daughter will benefit immensely.
I teach students thoroughly as teaching is my hobby,I try to understand student point of view first then proceed accordingly, prefer to teach students from board qualified books along with refreshers,being an MBA I believe in using latest methodology like powerpoint presentation including animation,videos . Practical approach with real examples,result is guaranteed,focuses on achieving goals of independent learning, learner autonomy, self-reflection, knowledge construction, collaborative or group-based learning, E learning is also a way of adding extra value and service to traditional educational services
Best teacher. Gives all the whole attention. Clear all the doubts. Provides good ways to understand the work. She's so humble and kind towards the students.
I am a teacher of Psychology and other social science subjects. I am giving online video tuition classes at affordable rates. I have a Master's degree in Psychology from Banaras Hindu University and am currently pursuing my PhD. I have also qualified UGC-NET in Psychology.
Ma'am is a wonderful teacher. And I am glad that I have learnt many thing not only about study but also many things that only books cannot teach us. She is very polite and she admires all efforts of me in study that can make me more knowledgeable. Thank you so much ma'am for being such a admirable teacher.
Other Subjects in CBSE - Class 12
Download free CBSE - Class 12 Chemistry Solutions Exercises worksheets
Download Now