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Q1.10:
What role does the molecular interaction play in a solution of alcohol and water?

Solution :

1. Theoretical Foundation of Molecular Interactions

In a solution of alcohol (e.g., ethanol, $C_2H_5OH$) and water ($H_2O$), the thermodynamic behavior of the mixture is governed by the nature and strength of the intermolecular forces (IMFs) present in the pure components versus the binary solution. Both substances are polar and exhibit extensive hydrogen bonding.

2. Analysis of Intermolecular Forces (IMFs)

To understand the role of these interactions, we categorize them into two distinct states:

State Predominant Interactions
Pure Ethanol $O-H \cdots O$ hydrogen bonding between ethanol molecules.
Pure Water $O-H \cdots O$ hydrogen bonding between water molecules.
Ethanol-Water Solution New $O-H \cdots O$ hydrogen bonds between the hydroxyl group of ethanol and the water molecules.

3. Deviation from Raoult's Law

When ethanol is added to water, the interaction between ethanol and water molecules is weaker than the hydrogen bonding present in pure water. [Per the principles of non-ideal solutions]:

  • The solute-solvent interaction ($A-B$) is weaker than the solvent-solvent ($A-A$) and solute-solute ($B-B$) interactions.
  • This leads to an increase in the escaping tendency of the molecules from the surface of the liquid.
  • Consequently, the solution exhibits positive deviation from Raoult’s Law.

4. Thermodynamic Consequences

The role of these molecular interactions manifests in specific macroscopic properties:

A. Vapor Pressure: Due to the weaker interaction in the mixture compared to pure components, the molecules escape more easily into the vapor phase, resulting in a total vapor pressure higher than that predicted by Raoult's Law ($P_{total} > P_A^o X_A + P_B^o X_B$).

B. Enthalpy of Mixing ($\Delta_{mix} H$): Energy must be absorbed to break the stronger hydrogen bonds in pure water and pure alcohol, while less energy is released upon forming the weaker ethanol-water interactions. Therefore, the process is endothermic ($\Delta_{mix} H > 0$).

C. Volume of Mixing ($\Delta_{mix} V$): The disruption of the hydrogen-bonded networks leads to an increase in the average distance between molecules, resulting in an expansion of the solution ($\Delta_{mix} V > 0$).

5. Visual Representation of Hydrogen Bonding

Ethanol ($CH_3CH_2OH$) O Water ($H_2O$) O H-bond (Intermolecular Interaction)

Final Solution: The molecular interaction between alcohol and water is characterized by the formation of new hydrogen bonds that are weaker than the existing hydrogen bonds in pure water. This causes the solution to exhibit positive deviation from Raoult’s Law, resulting in an increase in total vapor pressure, a positive enthalpy of mixing ($\Delta_{mix} H > 0$), and a positive volume of mixing ($\Delta_{mix} V > 0$).


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