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Q1.7:
A solution is obtained by mixing 300 g of 25% solution and 400 g of 40% solution by mass. Calculate the mass percentage of the resulting solution.

Solution :

Step 1: Calculating the Mass of Solute in Individual Solutions

To determine the total mass of the solute in the final mixture, we first calculate the mass of the solute contributed by each initial solution using the formula: $Mass_{solute} = \frac{Mass\%}{100} \times Total\_Mass_{solution}$.

  • For the first solution:
    $Mass_{solute,1} = \frac{25}{100} \times 300\text{ g} = 75\text{ g}$
  • For the second solution:
    $Mass_{solute,2} = \frac{40}{100} \times 400\text{ g} = 160\text{ g}$

Step 2: Calculating Total Mass and Total Solute

The total mass of the final solution is the sum of the masses of the two individual solutions [Per the Law of Conservation of Mass].

Component Mass of Solution (g) Mass of Solute (g)
Solution 1 300 75
Solution 2 400 160
Total 700 235

Step 3: Calculating Final Mass Percentage

The mass percentage of the resulting solution is calculated by dividing the total mass of the solute by the total mass of the resulting solution and multiplying by 100.

Formula: $Mass\% = \left( \frac{Total\_Mass_{solute}}{Total\_Mass_{solution}} \right) \times 100$

Calculation:
$Mass\% = \left( \frac{235\text{ g}}{700\text{ g}} \right) \times 100$
$Mass\% = 0.335714... \times 100$
$Mass\% \approx 33.57\%$

Visual Representation of Mixing Process

300g (25%) + 400g (40%) = 700g (33.57%)

Final Solution: The mass percentage of the resulting solution is 33.57%.


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