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Q3.1(c):
In which of the following examples of motion, can the body be considered approximately a point object: (c) a spinning cricket ball that turns sharply on hitting the ground.

Solution :

Analysis of the Physical System

To determine if an object can be treated as a point object, we evaluate the ratio of the object's spatial dimensions (size) to the total distance covered during its motion. If the displacement over which the motion is observed is significantly larger than the physical dimensions of the body, the internal structure and rotational dynamics can be neglected [Concept: Approximation in Kinematics].

Step 1: Evaluating the Motion Parameters

In the scenario of a "spinning cricket ball that turns sharply on hitting the ground," we must analyze the two distinct phases of motion:

  • Phase A (The Path): The distance traveled by the ball from the bowler to the ground and then to the batsman is typically in the range of $15$ to $20\text{ meters}$.
  • Phase B (The Interaction): The interaction at the ground (the "turn") involves a change in momentum due to friction and impulsive forces acting on the surface of the ball.

Step 2: Analytical Reasoning

The defining characteristic of this specific motion is the "sharp turn". The rotation (spin) of the ball is the primary causal mechanism for the change in direction upon impact with the ground [Per Newton’s Laws of Motion and Magnus Effect Principles].

If we treat the ball as a point object, we mathematically reduce its geometry to a position vector $\vec{r}(t)$. A point object, by definition, has no orientation and no surface area for friction to act upon to induce a torque $\vec{\tau} = \vec{r} \times \vec{F}$.

Step 3: Verification via Diagrammatic Representation

Spin ($\omega$) Point object approximation fails here due to rotation and bounce.

Step 4: Logical Conclusion

Because the "sharp turn" depends entirely on the ball's rotation (spin) and the contact patch between the ball and the ground, we cannot ignore the physical dimensions of the ball. If the ball were a point object, the rotational kinetic energy $K_{rot} = \frac{1}{2}I\omega^2$ would be zero, and the interaction with the ground would only result in a specular reflection (if elastic) or a simple stop, rather than a spin-induced "turn."

Parameter Point Object Assumption Actual Scenario
Rotation Not applicable ($I=0$) Critical for trajectory change
Geometry Dimensionless point Spherical with friction/torque
Validity Invalid Necessary for physical accuracy

Final Solution: The body cannot be considered a point object in this case, as the spin and the finite size of the ball are essential to explaining the "sharp turn" that occurs upon hitting the ground.


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