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Q2.10(b)(i):
A man walks on a straight road from his home to a market 2.5 km away with a speed of 5 km h(^{-1}). Finding the market closed, he instantly turns and walks back home with a speed of 7.5 km h(^{-1}). What is the (b) average speed of the man over the interval of time (i) 0 to 30 min ?

Solution :

Step 1: Identifying Kinematic Parameters

Given the linear motion of the man, we define the parameters as follows:

  • Distance to market ($d_1$): $2.5 \text{ km}$
  • Speed to market ($v_1$): $5 \text{ km h}^{-1}$
  • Speed returning home ($v_2$): $7.5 \text{ km h}^{-1}$
  • Time interval of interest ($\Delta t$): $0 \text{ to } 30 \text{ min} = 0.5 \text{ hours}$

Step 2: Calculating Time Taken to Reach the Market

To determine the man's position at $30 \text{ minutes}$ ($0.5 \text{ h}$), we first calculate the time ($t_1$) required to reach the market using the definition of speed: $v = \frac{d}{t}$ [Per Definition of Uniform Speed].

$t_1 = \frac{d_1}{v_1} = \frac{2.5 \text{ km}}{5 \text{ km h}^{-1}} = 0.5 \text{ h}$

Since $t_1 = 0.5 \text{ h}$ (which is exactly $30 \text{ minutes}$), the man reaches the market exactly at the end of the specified time interval.

Step 3: Visual Representation of Motion

Home (0 km) Market (2.5 km) v = 5 km/h

Step 4: Calculating Average Speed

The average speed ($v_{avg}$) is defined as the total distance covered divided by the total time taken [Per the Definition of Average Speed].

$v_{avg} = \frac{\text{Total Distance}}{\text{Total Time}}$

In the interval $0$ to $30 \text{ minutes}$, the man has traveled exactly from home to the market.

Total Distance ($D$) = $2.5 \text{ km}$

Total Time ($T$) = $0.5 \text{ h}$

$v_{avg} = \frac{2.5 \text{ km}}{0.5 \text{ h}} = 5 \text{ km h}^{-1}$

Step 5: Theoretical Justification

Since the man moved at a constant speed of $5 \text{ km h}^{-1}$ for the entire duration of the $30$-minute interval without changing direction, his instantaneous speed and average speed are identical [By the properties of Uniform Motion].

Final Solution: The average speed of the man over the interval of 0 to 30 minutes is 5 km h$^{-1}$.


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