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Q9.8(i):
Write chemical equations for combustion reaction of the following hydrocarbons: (i) Butane

Solution :

Step 1: Chemical Formula and Combustion Definition

Butane is an alkane with the chemical formula $C_4H_{10}$ [Per the general formula for alkanes, $C_nH_{2n+2}$]. Combustion is a redox reaction where a hydrocarbon reacts with molecular oxygen ($O_2$) to produce carbon dioxide ($CO_2$) and water ($H_2O$) while releasing energy [Law of Conservation of Mass].

Step 2: Skeletal Equation

The unbalanced chemical equation for the complete combustion of butane is:

$C_4H_{10}(g) + O_2(g) \rightarrow CO_2(g) + H_2O(l/g)$

Step 3: Balancing the Equation

To satisfy the law of conservation of mass, we balance the atoms sequentially:

  • Carbon (C): There are 4 carbon atoms on the left, so we require 4 molecules of $CO_2$.
  • Hydrogen (H): There are 10 hydrogen atoms on the left, so we require 5 molecules of $H_2O$ ($5 \times 2 = 10$).
  • Oxygen (O): On the right side, we have $(4 \times 2) + (5 \times 1) = 13$ oxygen atoms. To obtain 13 oxygen atoms from $O_2$, we use the coefficient $\frac{13}{2}$.

The balanced equation is: $C_4H_{10}(g) + \frac{13}{2}O_2(g) \rightarrow 4CO_2(g) + 5H_2O(l)$

Step 4: Converting to Whole Number Coefficients

Multiply the entire equation by 2 to eliminate the fraction [Standard chemical convention requires smallest whole-number coefficients]:

$2C_4H_{10}(g) + 13O_2(g) \rightarrow 8CO_2(g) + 10H_2O(l)$

Visual Representation of Butane Combustion

2 C₄H₁₀ + 13 O₂ 8 CO₂ + 10 H₂O + Heat Reactants (High Potential Energy) Products (Low Potential Energy)

Summary of Stoichiometry

Species Coefficient Phase
$C_4H_{10}$ 2 Gas
$O_2$ 13 Gas
$CO_2$ 8 Gas
$H_2O$ 10 Liquid

Final Solution: $2C_4H_{10}(g) + 13O_2(g) \rightarrow 8CO_2(g) + 10H_2O(l)$


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