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Q9.6:
An alkene ‘$A$’ contains three $C-C$, eight $C-H$ $\sigma$ bonds and one $C-C$ $\pi$ bond. ‘$A$’ on ozonolysis gives two moles of an aldehyde of molar mass 44 u. Write IUPAC name of ‘$A$’.

Solution :

Step 1: Analyzing the Molecular Composition of Alkene ‘$A$’

The problem states that alkene ‘$A$’ contains three $C-C$ $\sigma$ bonds, eight $C-H$ $\sigma$ bonds, and one $C-C$ $\pi$ bond. To determine the number of carbon atoms ($n$), we utilize the bonding constraints:

  • Total $C-H$ $\sigma$ bonds = $8$. Since each $H$ atom forms one bond with a $C$ atom, the number of Hydrogen atoms in the molecule is $8$.
  • General formula for an alkene is $C_nH_{2n}$. Substituting $2n = 8$, we find $n = 4$.
  • Thus, the molecular formula of ‘$A$’ is $C_4H_8$.
  • Verification of $\sigma$ bonds: In a chain of 4 carbons ($C-C-C-C$), there are 3 $C-C$ $\sigma$ bonds. Adding 8 $C-H$ $\sigma$ bonds satisfies the valence requirements.

Step 2: Ozonolysis Product Analysis

Ozonolysis of an alkene involves the cleavage of the $C=C$ double bond to produce carbonyl compounds. The problem states that ‘$A$’ yields two moles of an aldehyde with a molar mass of $44\text{ u}$.

Let the aldehyde be $R-CHO$. The molar mass is calculated as:

$M_{aldehyde} = M_R + M_C + M_O + M_H$

$44 = M_R + 12 + 16 + 1$

$44 = M_R + 29 \implies M_R = 15$

An alkyl group with a molar mass of $15$ corresponds to a methyl group ($-CH_3$). Therefore, the aldehyde produced is $CH_3CHO$ (Ethanal or Acetaldehyde).

Step 3: Deduce the Structure of Alkene ‘$A$’

Since the ozonolysis of one mole of alkene ‘$A$’ produces two moles of ethanal ($CH_3CHO$), the alkene must be symmetric about the double bond:

$CH_3-CH=CH-CH_3 + O_3 \rightarrow 2CH_3CHO$

[By the Principle of Oxidative Cleavage in Ozonolysis]

Step 4: Visualization of the Molecule

CH₃ CH CH CH₃

Step 5: IUPAC Nomenclature

The structure is $CH_3-CH=CH-CH_3$.

  • The longest carbon chain contains 4 carbons: But-
  • The double bond is located at the second carbon position: -2-ene
  • The configuration is typically trans or cis, but the general IUPAC name is But-2-ene.

Final Solution: The IUPAC name of alkene ‘$A$’ is But-2-ene.


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