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Q9.4(iii):
Write IUPAC names of the products obtained by the ozonolysis of the following compounds : (iii) 2-Ethylbut-1-ene

Solution :

Step 1: Structural Representation of 2-Ethylbut-1-ene

The chemical structure of 2-ethylbut-1-ene is defined by a four-carbon principal chain with a double bond at the $C_1$ position and an ethyl substituent at the $C_2$ position. The condensed structural formula is $CH_2=C(C_2H_5)CH_2CH_3$.

CH2 C CH2CH3 CH2CH3

Step 2: Mechanism of Ozonolysis

Ozonolysis involves the addition of ozone ($O_3$) to the carbon-carbon double bond to form an intermediate ozonide, followed by reductive cleavage using zinc dust ($Zn$) and water ($H_2O$). [Per the cleavage mechanism of alkenes during oxidative ozonolysis]:

  1. The double bond ($C=C$) is cleaved entirely.
  2. Each carbon atom involved in the double bond is converted into a carbonyl group ($C=O$).

Step 3: Identification of Cleavage Products

Given the structure $CH_2=C(C_2H_5)CH_2CH_3$:

  • Part A (The $C_1$ fragment): The terminal $CH_2$ group is oxidized to formaldehyde ($HCHO$).
  • Part B (The $C_2$ fragment): The $C_2$ atom, which is bonded to an ethyl group and the rest of the original chain (an ethyl group as well), becomes a ketone. Specifically, it is a $3$-pentanone derivative, but based on the specific connectivity: the $C_2$ is bonded to an ethyl group ($-CH_2CH_3$) and another ethyl group coming from the parent chain. Wait—re-evaluating the parent structure 2-ethylbut-1-ene:
    Structure: $CH_2=C(CH_2CH_3)CH_2CH_3$.
    The $C_2$ position is bonded to two identical ethyl groups.

Step 4: Final IUPAC Nomenclature

Following the cleavage of the $C=C$ bond:

Fragment Resulting Structure IUPAC Name
$C_1$ $HCHO$ Methanal
$C_2$ $O=C(CH_2CH_3)_2$ Pentan-3-one

The reaction equation is represented as:

$CH_2=C(C_2H_5)CH_2CH_3 + O_3 \xrightarrow[H_2O]{Zn} HCHO + CH_3CH_2COCH_2CH_3$

Final Solution: The products obtained are Methanal (formaldehyde) and Pentan-3-one (diethyl ketone).


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