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Q9.13(iv):
How will you convert benzene into (iv) acetophenone?

Solution :

Given Variables & Initial Setup

The objective is to convert Benzene ($C_6H_6$) into Acetophenone ($C_6H_5COCH_3$). This transformation requires the introduction of an acetyl group ($-COCH_3$) onto the benzene ring. The standard synthetic pathway for this transformation is the Friedel-Crafts Acylation.

Step 1: Reagents and Conditions

The reaction utilizes an acylating agent, typically Acetyl Chloride ($CH_3COCl$), in the presence of a Lewis acid catalyst, anhydrous Aluminum Chloride ($AlCl_3$).

Reaction Equation: $C_6H_6 + CH_3COCl \xrightarrow{Anhydrous AlCl_3} C_6H_5COCH_3 + HCl$

Step 2: Mechanism of Friedel-Crafts Acylation

The reaction proceeds via an electrophilic aromatic substitution mechanism involving three distinct phases:

  • Generation of the Electrophile: The Lewis acid ($AlCl_3$) coordinates with the chlorine atom of the acetyl chloride, facilitating the cleavage of the $C-Cl$ bond to produce the acylium ion (electrophile).
    $CH_3COCl + AlCl_3 \rightarrow [CH_3CO]^+ + [AlCl_4]^-$ [Per Lewis Acid-Base Theory]
  • Electrophilic Attack: The pi-electron cloud of the benzene ring attacks the acylium ion, forming a resonance-stabilized carbocation intermediate known as the sigma complex (arenium ion).
  • Deprotonation: The $[AlCl_4]^-$ ion removes a proton from the $sp^3$ hybridized carbon of the arenium ion, restoring aromaticity to the ring and regenerating the $AlCl_3$ catalyst.
    $[AlCl_4]^- + H^+ \rightarrow HCl + AlCl_3$ [Per Aromatic Stability Axiom]

Step 3: Visualizing the Transformation

Benzene CH₃COCl / AlCl₃ C(=O)CH₃ Acetophenone

Summary of Reaction Conditions

Reagent Role
$C_6H_6$ Substrate (Nucleophile)
$CH_3COCl$ Acylating Agent (Electrophile source)
$AlCl_3$ Lewis Acid Catalyst

Final Solution: Benzene is converted to Acetophenone via Friedel-Crafts Acylation by reacting it with acetyl chloride in the presence of anhydrous aluminum chloride ($AlCl_3$).


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