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Q9.20(ii):
How would you convert the following compounds into benzene? (ii) Ethene

Solution :

Given Variables & Initial Setup

The objective is to convert ethene ($CH_2=CH_2$) into benzene ($C_6H_6$). This transformation involves a transition from a simple two-carbon alkene to a stable six-carbon aromatic hydrocarbon. The process requires a controlled polymerization mechanism followed by aromatization.

Step 1: Catalytic Hydration to Ethanol

Ethene is reacted with steam in the presence of a phosphoric acid ($H_3PO_4$) catalyst at high temperature and pressure to produce ethanol.

$CH_2=CH_2 + H_2O \xrightarrow{H_3PO_4 / \Delta} CH_3CH_2OH$

[Per the mechanism of electrophilic addition/hydration of alkenes].

Step 2: Oxidation to Ethanal

Ethanol is oxidized to ethanal using copper (Cu) at 573 K, which acts as a dehydrogenation catalyst.

$CH_3CH_2OH \xrightarrow{Cu, 573K} CH_3CHO + H_2$

[Per the principle of catalytic dehydrogenation of primary alcohols].

Step 3: Aldol Condensation and Dehydration

Ethanal undergoes base-catalyzed aldol condensation followed by dehydration to form crotonaldehyde, which is then further processed or effectively polymerized. However, a more direct route for the industrial conversion involves the cyclic polymerization of acetylene.

Step 4: Alternative Direct Route - Bromination and Dehydrohalogenation

1. Bromination: Ethene reacts with Bromine to form 1,2-dibromoethane.

$CH_2=CH_2 + Br_2 \rightarrow BrCH_2-CH_2Br$

2. Dehydrohalogenation: Treatment with alcoholic $KOH$ yields ethyne (acetylene).

$BrCH_2-CH_2Br + 2KOH(alc.) \rightarrow HC\equiv CH + 2KBr + 2H_2O$

Step 5: Cyclic Polymerization

Three molecules of ethyne are passed through a red-hot iron tube at 873 K. This induces cyclotrimerization to form benzene.

$3HC\equiv CH \xrightarrow{\text{Red hot Fe tube, 873K}} C_6H_6$

[By the principle of thermal cyclotrimerization].

3 HC≡CH Red hot Fe tube 873 K Benzene

Summary of Reaction Sequence

Step Reagent/Condition Product
1 $Br_2$ 1,2-dibromoethane
2 $Alc. KOH$ Ethyne
3 Red hot Fe tube Benzene

Final Solution: Ethene is converted to benzene by first reacting with $Br_2$ to form 1,2-dibromoethane, followed by dehydrohalogenation with alcoholic $KOH$ to produce ethyne, and finally performing a cyclic trimerization of three ethyne molecules at 873 K over a red-hot iron tube to yield $C_6H_6$.


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