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Q9.7:
Propanal and pentan-3-one are the ozonolysis products of an alkene? What is the structural formula of the alkene?

Solution :

Step 1: Theoretical Foundation of Ozonolysis

Ozonolysis involves the oxidative cleavage of an alkene ($C=C$) using ozone ($O_3$), followed by reductive workup ($Zn/H_2O$). The reaction follows the principle of "breaking the double bond and inserting oxygen atoms on each of the resulting carbonyl fragments." If we have a carbonyl fragment $R_1-C(=O)-R_2$ and $R_3-C(=O)-R_4$, the parent alkene must have been $R_1R_2C=CR_3R_4$. [Per the Criegee mechanism of ozonolysis].

Step 2: Analysis of the Given Fragments

The fragments provided are:

  • Fragment A (Propanal): $CH_3-CH_2-CHO$
  • Fragment B (Pentan-3-one): $CH_3-CH_2-C(=O)-CH_2-CH_3$

Step 3: Structural Reconstruction

To identify the parent alkene, we remove the oxygen atoms from the carbonyl groups and connect the two carbonyl carbons with a double bond.

Fragment A ($C_3$): $CH_3-CH_2-CH=O$
Fragment B ($C_5$): $O=C(CH_2-CH_3)_2$

By joining the carbons where the oxygen atoms were bonded:

$CH_3-CH_2-CH = C(CH_2-CH_3)_2$

Step 4: IUPAC Nomenclature & Structure

The resulting structure is a heptene derivative. The chain contains 7 carbons. The double bond is at position 3.

Structure: $CH_3-CH_2-CH=C(CH_2-CH_3)-CH_2-CH_3$

IUPAC Name: 3-ethylhept-3-ene

CH3 CH2 CH C CH2 CH3 CH2-CH3

Step 5: Verification of the Reaction

Reactant Fragment Original Alkene Part Resulting Product
Left side of $C=C$ $CH_3CH_2CH=$ Propanal
Right side of $C=C$ $=C(CH_2CH_3)_2$ Pentan-3-one

Final Solution: The alkene is 3-ethylhept-3-ene, with the structural formula $CH_3CH_2CH=C(C_2H_5)CH_2CH_3$.


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