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Q3(ii):
Find the LCM and HCF of the following integers by applying the prime factorisation method. (ii) 17, 23 and 29

Solution :

Given: Three integers: $17$, $23$, and $29$.

To find: The Highest Common Factor (HCF) and the Least Common Multiple (LCM) of the given integers using the prime factorisation method.

Step 1: Prime Factorisation of the given integers

We express each number as a product of its prime factors:

For $17$: Since $17$ is a prime number, its only factors are $1$ and itself.
$17 = 17^1 \times 1^1$

For $23$: Since $23$ is a prime number, its only factors are $1$ and itself.
$23 = 23^1 \times 1^1$

For $29$: Since $29$ is a prime number, its only factors are $1$ and itself.
$29 = 29^1 \times 1^1$

Step 2: Finding the HCF

The Highest Common Factor (HCF) is defined as the product of the smallest power of each common prime factor in the numbers.

Comparing the prime factors of $17$, $23$, and $29$:
The prime factors are $17$, $23$, and $29$. There are no common prime factors other than $1$.

Therefore, $HCF(17, 23, 29) = 1$.

Step 3: Finding the LCM

The Least Common Multiple (LCM) is defined as the product of the greatest power of each prime factor involved in the numbers.

The prime factors involved are $17$, $23$, and $29$. The greatest power of each is $1$.

$LCM(17, 23, 29) = 17^1 \times 23^1 \times 29^1$

Calculation:
First, multiply $17$ and $23$:
$17 \times 23 = 17 \times (20 + 3) = 340 + 51 = 391$

Next, multiply the result by $29$:
$391 \times 29 = 391 \times (30 - 1)$
$= (391 \times 30) - (391 \times 1)$
$= 11730 - 391$

Performing the subtraction:
$11730 - 391 = 11339$

Therefore, $LCM(17, 23, 29) = 11339$.

Final Answer: The HCF is 1 and the LCM is 11339.


More Questions from Class 10 Mathematics Real numbers EXERCISE 1.1


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