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Q1(i):
Express each number as a product of its prime factors: (i) 140

Solution :

Given: The integer $140$.

To find: The prime factorization of $140$, expressed as a product of its prime factors.

Step 1: Understanding Prime Factorization
Prime factorization is the process of expressing a composite number as a product of prime numbers. A prime number is a natural number greater than $1$ that has no positive divisors other than $1$ and itself. We will use the method of successive division by the smallest prime numbers ($2, 3, 5, 7, 11, \dots$).

Step 2: Sequential Division

We begin by dividing $140$ by the smallest prime number, which is $2$:

$140 \div 2 = 70$ [Since $140$ is an even number, it is divisible by $2$]

Next, we divide the quotient $70$ by the smallest prime number, which is $2$:

$70 \div 2 = 35$ [Since $70$ is an even number, it is divisible by $2$]

Next, we check if $35$ is divisible by $2$ or $3$. Since $35$ is odd and the sum of its digits ($3+5=8$) is not divisible by $3$, we move to the next prime number, $5$:

$35 \div 5 = 7$ [Since the last digit is $5$, it is divisible by $5$]

Finally, we divide the quotient $7$ by the prime number $7$:

$7 \div 7 = 1$ [Since $7$ is a prime number, it is only divisible by itself]

Step 3: Compiling the Factors
The prime factors obtained are $2, 2, 5,$ and $7$.

We can write the product as:
$140 = 2 \times 2 \times 5 \times 7$

Step 4: Expressing in Exponential Form
Using the law of exponents, where $a \times a = a^2$:

$140 = 2^2 \times 5^1 \times 7^1$

Final Answer: The prime factorization of $140$ is $2^2 \times 5 \times 7$.


More Questions from Class 10 Mathematics Real numbers EXERCISE 1.1


CBSE Solutions for Class 10 Mathematics Real numbers


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