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Q2(ii):
Find the LCM and HCF of the following pairs of integers and verify that LCM $\times$ HCF = product of the two numbers. (ii) 510 and 92

Solution :

Given: Two integers, $a = 510$ and $b = 92$.

To Find: The Highest Common Factor (HCF) and the Least Common Multiple (LCM) of the given integers, and to verify the relationship: $LCM \times HCF = \text{Product of the two numbers}$.

Step 1: Prime Factorization of the given numbers

We express each number as a product of its prime factors.

For $510$:
$510 = 2 \times 255$
$255 = 3 \times 85$
$85 = 5 \times 17$
$17 = 17 \times 1$
So, $510 = 2^1 \times 3^1 \times 5^1 \times 17^1$

For $92$:
$92 = 2 \times 46$
$46 = 2 \times 23$
$23 = 23 \times 1$
So, $92 = 2^2 \times 23^1$

Step 2: Determining HCF and LCM

HCF (Highest Common Factor): The HCF is the product of the smallest power of each common prime factor in the numbers.
Common prime factor is $2$. The smallest power of $2$ is $2^1$.
$HCF(510, 92) = 2^1 = 2$.

LCM (Least Common Multiple): The LCM is the product of the greatest power of each prime factor involved in the numbers.
Prime factors involved are $2, 3, 5, 17, 23$.
Greatest powers are $2^2, 3^1, 5^1, 17^1, 23^1$.
$LCM(510, 92) = 2^2 \times 3^1 \times 5^1 \times 17^1 \times 23^1$
$LCM(510, 92) = 4 \times 3 \times 5 \times 17 \times 23$
$LCM(510, 92) = 12 \times 5 \times 17 \times 23$
$LCM(510, 92) = 60 \times 17 \times 23$
$LCM(510, 92) = 1020 \times 23$
$LCM(510, 92) = 23460$.

Step 3: Verification of the relationship

We need to verify if $LCM \times HCF = a \times b$.

Left Hand Side (LHS):
$LCM \times HCF = 23460 \times 2$
$LCM \times HCF = 46920$.

Right Hand Side (RHS):
Product of numbers $= 510 \times 92$
$510 \times 92 = 510 \times (90 + 2)$
$= 45900 + 1020$
$= 46920$.

Since $LHS = RHS$, the relationship is verified.

Final Answer: The HCF is $2$, the LCM is $23460$, and the relationship $LCM \times HCF = \text{Product of the two numbers}$ is verified as $46920 = 46920$.


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