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Q2(ii):
Find the sums given below : (ii) 34 + 32 + 30 + . . . + 10

Solution :

Given: An arithmetic series $34 + 32 + 30 + \dots + 10$.

To find: The sum of the given arithmetic series.

Step 1: Identify the components of the Arithmetic Progression (AP)

The given series is $34, 32, 30, \dots, 10$.

Let the first term be $a = 34$.

Let the common difference be $d$.

$d = a_2 - a_1 = 32 - 34 = -2$.

The last term (or $n^{th}$ term) is $a_n = l = 10$.

Step 2: Determine the number of terms ($n$)

We use the formula for the $n^{th}$ term of an AP: $a_n = a + (n - 1)d$.

Substituting the known values into the formula:

$10 = 34 + (n - 1)(-2)$

Subtract $34$ from both sides:

$10 - 34 = (n - 1)(-2)$

$-24 = (n - 1)(-2)$

Divide both sides by $-2$:

$\frac{-24}{-2} = n - 1$

$12 = n - 1$

$n = 12 + 1 = 13$.

[Since there are 13 terms in the series]

Step 3: Calculate the sum of the AP

The formula for the sum of the first $n$ terms of an AP when the last term is known is:

$S_n = \frac{n}{2}(a + l)$

Substituting $n = 13$, $a = 34$, and $l = 10$:

$S_{13} = \frac{13}{2}(34 + 10)$

$S_{13} = \frac{13}{2}(44)$

Simplify the expression:

$S_{13} = 13 \times \left(\frac{44}{2}\right)$

$S_{13} = 13 \times 22$

Step 4: Final Arithmetic Calculation

$13 \times 22 = 13 \times (20 + 2)$

$= 260 + 26$

$= 286$

Final Answer: The sum of the series 34 + 32 + 30 + . . . + 10 is 286.


More Questions from Class 10 Mathematics Arithmetic Progression EXERCISE 5.3


CBSE Solutions for Class 10 Mathematics Arithmetic Progression


Chapters in CBSE - Class 10 Mathematics


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