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Ram Mohan A. Class 10 trainer in Hyderabad

Ram Mohan A.

(24)
Super Tutor
(24)
Super Tutor
locationImg Serlingampally, Hyderabad
20 yrs of Exp
students 25 students
623 hrs of classes completed
rsIcon 400 per hour
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TEACHING IS MY PASSION-I STILL STRIVE TO BETTER MY TEACHING ABILITIES

Online Classes
I am a Post Graduate in Nuclear Physics. Aged 61 yrs with a teaching experience of about 25 yrs.

Can teach MATHS, PHYSICS, CHEMISTRY FOR 8th - 10th Standards (CAN TEACH PHYSICS UP TO 12th Standard)

I have a special passion to TEACH VEDIC ARITHMETIC
Isa

He is Very inflexible and very weird. Didn’t like the attitude. Keeps cancelling class and disappearing.

Languages Spoken

Telugu Mother Tongue (Native)

English Proficient

Education

GOVERNMENT DEGREE COLLEGE, RAZOLE, E.G.Dst, ANDHRA PRADESH 1973

Bachelor of Science (B.Sc.)

NUCLEAR RESEARCH LANORATORIES, ANDHRA UNIVERSITY 1975

MSc IN NUCLEAR PHYSICS

Address

Serlingampally, Hyderabad, India - 500084

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Taught Students from these Schools

B

British School

Marathahalli, Bangalore

Teaches

Class 10 Tuition
13 Students

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

20

Board

State, ICSE, International Baccalaureate, CBSE, IGCSE

Preferred class strength

One on one/ Private Tutions, Group Classes

Experience in School or College

IN FACT, I HAVE NOT TAUGHT AT ANY SCHOOL.BUT I TAUGHT AT TUTORIAL COLLEGES AND COACHING INSTITUTES FOR ABOUT 5 YEARS. AFTER THAT I STARTED MY TUITIONS AT MY HOME AND CONTINUED THAT STREAK FOR ABOUT 20 YEARS. ON AN AVERAGE, I HAD RUN TWO BATCHES DAILY DURING NON-OFFICE HOURS. AFTER RETIREMENT, I HAVE NOT TAUGHT ON REGULAR BASIS EXCEPT GUIDING THE CHILDREN OF SOME OF MY OLD STUDENTS AND GRAND CHILDREN OF MY FRIENDS AND EX-COLLEAGUES.

Subjects taught

Chemistry, Mathematics, Physics, Science

Taught in School or College

Yes

Teaching Experience in detail in Class 10 Tuition

Teaching is my Passion. I have taught Mathematics, Physics and Chemistry to several students during 20+ years of my teaching. Many of my students who initially were scarred of Mathematics, have developed interest on the subject and opted MPC group in their Intermediate and are now earning Dollars as Software Engineers in USA, CANADA, UK and Australia.

Class 9 Tuition
3 Students

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

20

Board

State, ICSE, International Baccalaureate, CBSE

Preferred class strength

One on one/ Private Tutions, Group Classes

Experience in School or College

IF FACT, I HAVE NOT TAUGHT AT ANY SCHOOL. I TAUGHT AT TUTORIAL COLLEGES AND COACHING INSTITUTES FOR ABOUT 5 YEARS. AFTER THAT, I STARTED TEACHING AT MY HOME DURING NON-OFFICE HOURS. THIS STREAK CONTINUED FOR ABOUT 20 YEARS, PERHAPS MOUTH PUBLICITY BY MY OLD STUDENTS AND BY THEIR PARENTS. ON AN AVERAGE, I HAD CONDUCTED TWO BATCHES DAILY, ONE EACH FOR 9th CLASS AND 10th CLASS. STUDENTS.

Subjects taught

Chemistry, Science, Physics, Mathematics

Taught in School or College

Yes

Teaching Experience in detail in Class 9 Tuition

Teaching is my Passion. I have taught Maths, Physics and Chemistry to several students during 20 years of my teaching. Many of my students who initially were scarred of Maths, have developed interest on the subject and opted MPC group in their Intermediate and are now earning Dollars as Software Engineers in USA,CANADA,UK and Australia.

Reviews

4.8 out of 5 24 reviews

RAM MOHAN A. https://p.urbanpro.com/tv-prod/member/photo/226856-small.jpg Serlingampally
4.80524
RAM MOHAN A.
I
Verified Student

LEARN THE ART OF HIGH SPEED MENTAL CALCULATION SYSTEM

"He is Very inflexible and very weird. Didn’t like the attitude. Keeps cancelling class and disappearing. "

RAM MOHAN A.
R
Verified Student

Class 10 Tuition

"It has been good experience so far. I would request you to resolve last year's question papers chapter wise as on when you progress on chapter. It will help her to keep thorough preparation for term exam as well as board . Also , request you to take exam chapter wise from your end . Is it possible to take 2 hours class together on Saturday instead of taking one hour class on Sunday. Please let us know. "

RAM MOHAN A.
M
Verified Student

Class 9 Tuition

"A very good teacher and a knowledgeable one also. I have seen improvement in my grades before and after joining the classes. During my exam times the revision given by teacher was very helpful. "

RAM MOHAN A.
M
Verified Student

Class 10 Tuition

"Very Good classes. Great explanation of topic. Always helped with step-by-step explanation. Very Helpful. "

Have you attended any class with Ram Mohan?

Answers by Ram Mohan (38)

Answered on 08/12/2016 +2 Sales Tax and VAT

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Post a Lesson

If 'r' stands for the percentage rate of Sales Tax say then (100+r) will be the Sale Price. While its cost price is 100 and 'r' will be the Sales Tax '. Therefore, if 'SP stands for actual Sale Price and 'ST' stands for actual Sales tax then we have:- (100+r) : r :: SP : ST OR (100+r)/r = SP / ST... ...more
If 'r' stands for the percentage rate of Sales Tax say then (100+r) will be the Sale Price. While its cost price is 100 and 'r' will be the Sales Tax '. Therefore, if 'SP stands for actual Sale Price and 'ST' stands for actual Sales tax then we have:- (100+r) : r :: SP : ST OR (100+r)/r = SP / ST From this formula , given the values of any two of 'r' ; 'SP' ; 'ST' the value of the third can be found. In the given Sum, r = 10, SP = 17600 ST =? from the above formula, we can write ST =r * SP /(100+r) = 10 * 17600 /(100+10) = 10 * 17600/110 = Rs.1600. Therefore, the Sales Tax on the Refrigerator is Rs.1600.
Answers 7 Comments
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Answered on 02/12/2016 +2 Volumes

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If l, b, h, S and V are length, breadth, height, surface area and volume respectively of a cuboid, Then We have S = 2( lb + bh + lh ) and V = lbh Let us take the relation S = 2(lb +bh + lh). Now dividing both sides with V * S, we get 1/V = 2 ( lb + bh = lh )/ (V * S) = 2 ( lb + bh +lh )/ (lbh *... ...more
If l, b, h, S and V are length, breadth, height, surface area and volume respectively of a cuboid, Then We have S=2( lb + bh + lh ) and V=lbh Let us take the relation S=2(lb +bh + lh). Now dividing both sides with V * S, we get 1/V = 2 ( lb + bh=lh )/ (V * S) = 2 ( lb + bh +lh )/ (lbh * S) ...... ( after Substituting lbh for V) ==> 1/V = 2 [(lb/lbh )+( bh/lbh ) + (lh/lbh )] / S==> 1/V = 2/S(1/l + 1/b + 1/h) proved.
Answers 4 Comments
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Answered on 02/12/2016 +2 Volumes

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Post a Lesson

If l, b, h, S and V are length, breadth, height, surface area and volume respectively of a cuboid, Then, V = lbh Let us take the relation S = 2 (lb +bh + lh). Now dividing both sides with V * S, we get:- 1/V = 2 ( lb + bh = lh )/ (V * S) = 2 ( lb + bh = lh )/ (lbh * S) ...... ( Substituting lbh for... ...more
If l, b, h, S and V are length, breadth, height, surface area and volume respectively of a cuboid, Then, V=lbh Let us take the relation S=2 (lb +bh + lh). Now dividing both sides with V * S, we get:- 1/V = 2 ( lb + bh=lh )/ (V * S) = 2 ( lb + bh=lh )/ (lbh * S) ...... ( Substituting lbh for V) ==> 1/V = =2 [(lb/lbh )+( bh/lbh ) + (lh/ibh )] / S==> 1/V = 2/S(1/l + 1/b + 1/h) proved.
Answers 4 Comments
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Answered on 28/11/2016 +2 Ratio and Proportion

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Given that A:B = 4:5, B:C = 6:7 and C:D = 14:15. Therefore, A/B =4/5; B/A = 6/7; C/D = 14/15 We can write A/D as A/D = A/B * B/C *C/D = 4/5 * 6/7 * 14/15 = 16/25 Thus, A : D = 16 : 25.
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Answered on 25/11/2016 +2 Logarithms

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We know that, log 'x' to base 'y' = log 'x' to base ' z ' * log'z' to base' y' ............. (1) and log 'p' to base 'q' = 1/ log 'q' to base 'x' ............(2) In the present context, It is given that log 'x' to base '3' = A log 'x'to base '5' by using formula (2) above, we can rewrite this equation... ...more
We know that, log 'x' to base 'y' = log 'x' to base ' z ' * log'z' to base' y' ............. (1) and log 'p' to base 'q' = 1/ log 'q' to base 'x' ............(2) In the present context, It is given that log 'x' to base '3' = A log 'x'to base '5' by using formula (2) above, we can rewrite this equation as:- log 'x' to base '3' = A * 1/ log '5' to base 'x' ==> log '5' to base 'x' * log 'x' to base '3' = A==> log '5' to base '3' = A ( [By using the Formula (1) above, (log'5' to base 'x' * log 'x' to base '3') becomes (" log '5' to base '3'). Therefore, A = log 5 to base 3.
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Teaches

Class 10 Tuition
13 Students

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

20

Board

State, ICSE, International Baccalaureate, CBSE, IGCSE

Preferred class strength

One on one/ Private Tutions, Group Classes

Experience in School or College

IN FACT, I HAVE NOT TAUGHT AT ANY SCHOOL.BUT I TAUGHT AT TUTORIAL COLLEGES AND COACHING INSTITUTES FOR ABOUT 5 YEARS. AFTER THAT I STARTED MY TUITIONS AT MY HOME AND CONTINUED THAT STREAK FOR ABOUT 20 YEARS. ON AN AVERAGE, I HAD RUN TWO BATCHES DAILY DURING NON-OFFICE HOURS. AFTER RETIREMENT, I HAVE NOT TAUGHT ON REGULAR BASIS EXCEPT GUIDING THE CHILDREN OF SOME OF MY OLD STUDENTS AND GRAND CHILDREN OF MY FRIENDS AND EX-COLLEAGUES.

Subjects taught

Chemistry, Mathematics, Physics, Science

Taught in School or College

Yes

Teaching Experience in detail in Class 10 Tuition

Teaching is my Passion. I have taught Mathematics, Physics and Chemistry to several students during 20+ years of my teaching. Many of my students who initially were scarred of Mathematics, have developed interest on the subject and opted MPC group in their Intermediate and are now earning Dollars as Software Engineers in USA, CANADA, UK and Australia.

Class 9 Tuition
3 Students

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

20

Board

State, ICSE, International Baccalaureate, CBSE

Preferred class strength

One on one/ Private Tutions, Group Classes

Experience in School or College

IF FACT, I HAVE NOT TAUGHT AT ANY SCHOOL. I TAUGHT AT TUTORIAL COLLEGES AND COACHING INSTITUTES FOR ABOUT 5 YEARS. AFTER THAT, I STARTED TEACHING AT MY HOME DURING NON-OFFICE HOURS. THIS STREAK CONTINUED FOR ABOUT 20 YEARS, PERHAPS MOUTH PUBLICITY BY MY OLD STUDENTS AND BY THEIR PARENTS. ON AN AVERAGE, I HAD CONDUCTED TWO BATCHES DAILY, ONE EACH FOR 9th CLASS AND 10th CLASS. STUDENTS.

Subjects taught

Chemistry, Science, Physics, Mathematics

Taught in School or College

Yes

Teaching Experience in detail in Class 9 Tuition

Teaching is my Passion. I have taught Maths, Physics and Chemistry to several students during 20 years of my teaching. Many of my students who initially were scarred of Maths, have developed interest on the subject and opted MPC group in their Intermediate and are now earning Dollars as Software Engineers in USA,CANADA,UK and Australia.

Courses

Answers by Ram Mohan A.

Answered on 08/12/2016 +2 Sales Tax and VAT

Ask a Question

Post a Lesson

If 'r' stands for the percentage rate of Sales Tax say then (100+r) will be the Sale Price. While its cost price is 100 and 'r' will be the Sales Tax '. Therefore, if 'SP stands for actual Sale Price and 'ST' stands for actual Sales tax then we have:- (100+r) : r :: SP : ST OR (100+r)/r = SP / ST... ...more
If 'r' stands for the percentage rate of Sales Tax say then (100+r) will be the Sale Price. While its cost price is 100 and 'r' will be the Sales Tax '. Therefore, if 'SP stands for actual Sale Price and 'ST' stands for actual Sales tax then we have:- (100+r) : r :: SP : ST OR (100+r)/r = SP / ST From this formula , given the values of any two of 'r' ; 'SP' ; 'ST' the value of the third can be found. In the given Sum, r = 10, SP = 17600 ST =? from the above formula, we can write ST =r * SP /(100+r) = 10 * 17600 /(100+10) = 10 * 17600/110 = Rs.1600. Therefore, the Sales Tax on the Refrigerator is Rs.1600.
Answers 7 Comments
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Answered on 02/12/2016 +2 Volumes

Ask a Question

Post a Lesson

If l, b, h, S and V are length, breadth, height, surface area and volume respectively of a cuboid, Then We have S = 2( lb + bh + lh ) and V = lbh Let us take the relation S = 2(lb +bh + lh). Now dividing both sides with V * S, we get 1/V = 2 ( lb + bh = lh )/ (V * S) = 2 ( lb + bh +lh )/ (lbh *... ...more
If l, b, h, S and V are length, breadth, height, surface area and volume respectively of a cuboid, Then We have S=2( lb + bh + lh ) and V=lbh Let us take the relation S=2(lb +bh + lh). Now dividing both sides with V * S, we get 1/V = 2 ( lb + bh=lh )/ (V * S) = 2 ( lb + bh +lh )/ (lbh * S) ...... ( after Substituting lbh for V) ==> 1/V = 2 [(lb/lbh )+( bh/lbh ) + (lh/lbh )] / S==> 1/V = 2/S(1/l + 1/b + 1/h) proved.
Answers 4 Comments
Dislike Bookmark

Answered on 02/12/2016 +2 Volumes

Ask a Question

Post a Lesson

If l, b, h, S and V are length, breadth, height, surface area and volume respectively of a cuboid, Then, V = lbh Let us take the relation S = 2 (lb +bh + lh). Now dividing both sides with V * S, we get:- 1/V = 2 ( lb + bh = lh )/ (V * S) = 2 ( lb + bh = lh )/ (lbh * S) ...... ( Substituting lbh for... ...more
If l, b, h, S and V are length, breadth, height, surface area and volume respectively of a cuboid, Then, V=lbh Let us take the relation S=2 (lb +bh + lh). Now dividing both sides with V * S, we get:- 1/V = 2 ( lb + bh=lh )/ (V * S) = 2 ( lb + bh=lh )/ (lbh * S) ...... ( Substituting lbh for V) ==> 1/V = =2 [(lb/lbh )+( bh/lbh ) + (lh/ibh )] / S==> 1/V = 2/S(1/l + 1/b + 1/h) proved.
Answers 4 Comments
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Answered on 28/11/2016 +2 Ratio and Proportion

Ask a Question

Post a Lesson

Given that A:B = 4:5, B:C = 6:7 and C:D = 14:15. Therefore, A/B =4/5; B/A = 6/7; C/D = 14/15 We can write A/D as A/D = A/B * B/C *C/D = 4/5 * 6/7 * 14/15 = 16/25 Thus, A : D = 16 : 25.
Answers 9 Comments
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Answered on 25/11/2016 +2 Logarithms

Ask a Question

Post a Lesson

We know that, log 'x' to base 'y' = log 'x' to base ' z ' * log'z' to base' y' ............. (1) and log 'p' to base 'q' = 1/ log 'q' to base 'x' ............(2) In the present context, It is given that log 'x' to base '3' = A log 'x'to base '5' by using formula (2) above, we can rewrite this equation... ...more
We know that, log 'x' to base 'y' = log 'x' to base ' z ' * log'z' to base' y' ............. (1) and log 'p' to base 'q' = 1/ log 'q' to base 'x' ............(2) In the present context, It is given that log 'x' to base '3' = A log 'x'to base '5' by using formula (2) above, we can rewrite this equation as:- log 'x' to base '3' = A * 1/ log '5' to base 'x' ==> log '5' to base 'x' * log 'x' to base '3' = A==> log '5' to base '3' = A ( [By using the Formula (1) above, (log'5' to base 'x' * log 'x' to base '3') becomes (" log '5' to base '3'). Therefore, A = log 5 to base 3.
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