https://www.urbanpro.com/hyderabad/ram-mohan-arumilli # Ram Mohan A.

## TEACHING IS MY PASSION-I STILL STRIVE TO BETTER MY TEACHING ABILITIES

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## Reviews (24)

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## Answers by Ram Mohan (38)

## Teaches

IN FACT, I HAVE NOT TAUGHT AT ANY SCHOOL.BUT I TAUGHT AT TUTORIAL COLLEGES AND COACHING INSTITUTES FOR ABOUT 5 YEARS. AFTER THAT I STARTED MY TUITIONS AT MY HOME AND CONTINUED THAT STREAK FOR ABOUT 20 YEARS. ON AN AVERAGE, I HAD RUN TWO BATCHES DAILY DURING NON-OFFICE HOURS. AFTER RETIREMENT, I HAVE NOT TAUGHT ON REGULAR BASIS EXCEPT GUIDING THE CHILDREN OF SOME OF MY OLD STUDENTS AND GRAND CHILDREN OF MY FRIENDS AND EX-COLLEAGUES.

IF FACT, I HAVE NOT TAUGHT AT ANY SCHOOL. I TAUGHT AT TUTORIAL COLLEGES AND COACHING INSTITUTES FOR ABOUT 5 YEARS. AFTER THAT, I STARTED TEACHING AT MY HOME DURING NON-OFFICE HOURS. THIS STREAK CONTINUED FOR ABOUT 20 YEARS, PERHAPS MOUTH PUBLICITY BY MY OLD STUDENTS AND BY THEIR PARENTS. ON AN AVERAGE, I HAD CONDUCTED TWO BATCHES DAILY, ONE EACH FOR 9th CLASS AND 10th CLASS. STUDENTS.

## Courses

## Answers by Ram Mohan A. (38)

Given that A:B = 4:5, B:C = 6:7 and C:D = 14:15. Therefore, A/B =4/5; B/A = 6/7; C/D = 14/15 We can write A/D as A/D = A/B * B/C *C/D = 4/5 * 6/7 * 14/15 = 16/25 Thus, A : D = 16 : 25. ### Learn More

NCERT Solutions for Class 9 CBSE Class 10 Syllabus NCERT Class 10 Solutions NCERT Solutions for Class 9 Maths NCERT Solutions for Class 9 Science Chapter 1 - Matter In Our Surroundings Chapter 2 - Is Matter Around Us Pure? Chapter 3 - Atoms and Molecules Chapter 4 - Structure of the Atom Chapter 5 - The Fundamental Unit of Life

Serlingampally, Hyderabad, India - 500084.

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I am a Post Graduate in Nuclear Physics. Aged 61 yrs with a teaching experience of about 25 yrs.

Can teach MATHS, PHYSICS, CHEMISTRY FOR 8th - 10th Standards (CAN TEACH PHYSICS UP TO 12th Standard)

I have a special passion to TEACH VEDIC ARITHMETIC

Can teach MATHS, PHYSICS, CHEMISTRY FOR 8th - 10th Standards (CAN TEACH PHYSICS UP TO 12th Standard)

I have a special passion to TEACH VEDIC ARITHMETIC

Intro Video

- Class 9 Tuition , Class 10 Tuition +3

Telugu Mother Tongue (Native)

English Proficient

GOVERNMENT DEGREE COLLEGE, RAZOLE, E.G.Dst, ANDHRA PRADESH 1973

Bachelor of Science (B.Sc.)

NUCLEAR RESEARCH LANORATORIES, ANDHRA UNIVERSITY 1975

MSc IN NUCLEAR PHYSICS

Serlingampally, Hyderabad, India - 500084

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British School

Marathahalli, Bangalore

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Class 10 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

20

Board

State, International Baccalaureate, ICSE, CBSE, IGCSE

State boards taught

Andhra Pradesh State Board

IB Subjects taught

Mathematics, Physics, Chemistry

Preferred class strength

Group Classes, One on one/ Private Tutions

CBSE Subjects taught

Mathematics, Science

ICSE Subjects taught

Physics, Mathematics, Chemistry

IGCSE Subjects taught

Mathematics, Physics, Chemistry

Experience in School or College

IN FACT, I HAVE NOT TAUGHT AT ANY SCHOOL.BUT I TAUGHT AT TUTORIAL COLLEGES AND COACHING INSTITUTES FOR ABOUT 5 YEARS. AFTER THAT I STARTED MY TUITIONS AT MY HOME AND CONTINUED THAT STREAK FOR ABOUT 20 YEARS. ON AN AVERAGE, I HAD RUN TWO BATCHES DAILY DURING NON-OFFICE HOURS. AFTER RETIREMENT, I HAVE NOT TAUGHT ON REGULAR BASIS EXCEPT GUIDING THE CHILDREN OF SOME OF MY OLD STUDENTS AND GRAND CHILDREN OF MY FRIENDS AND EX-COLLEAGUES.

Taught in School or College

Yes

State Syllabus Subjects taught

Science, Mathematics

Teaching Experience in detail in Class 10 Tuition

Teaching is my Passion. I have taught Mathematics, Physics and Chemistry to several students during 20+ years of my teaching. Many of my students who initially were scarred of Mathematics, have developed interest on the subject and opted MPC group in their Intermediate and are now earning Dollars as Software Engineers in USA, CANADA, UK and Australia.

Class 9 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

20

Board

State, International Baccalaureate, ICSE, CBSE

State boards taught

Andhra Pradesh State Board

IB Subjects taught

Mathematics, Physics, Chemistry

Preferred class strength

Group Classes, One on one/ Private Tutions

CBSE Subjects taught

Mathematics, Science

ICSE Subjects taught

Physics, Mathematics, Chemistry

Experience in School or College

IF FACT, I HAVE NOT TAUGHT AT ANY SCHOOL. I TAUGHT AT TUTORIAL COLLEGES AND COACHING INSTITUTES FOR ABOUT 5 YEARS. AFTER THAT, I STARTED TEACHING AT MY HOME DURING NON-OFFICE HOURS. THIS STREAK CONTINUED FOR ABOUT 20 YEARS, PERHAPS MOUTH PUBLICITY BY MY OLD STUDENTS AND BY THEIR PARENTS. ON AN AVERAGE, I HAD CONDUCTED TWO BATCHES DAILY, ONE EACH FOR 9th CLASS AND 10th CLASS. STUDENTS.

Taught in School or College

Yes

State Syllabus Subjects taught

Science, Mathematics

Teaching Experience in detail in Class 9 Tuition

Teaching is my Passion. I have taught Maths, Physics and Chemistry to several students during 20 years of my teaching. Many of my students who initially were scarred of Maths, have developed interest on the subject and opted MPC group in their Intermediate and are now earning Dollars as Software Engineers in USA,CANADA,UK and Australia.

4.8 out of 5 24 reviews

RAM MOHAN A. https://p.urbanpro.com/tv-prod/member/photo/226856-small.jpg Serlingampally

4.80524 RAM MOHAN A.

I

Isa Sinha

Verified Student

Reviewed on 06 Jul, 2022

LEARN THE ART OF HIGH SPEED MENTAL CALCULATION SYSTEM

"He is Very inflexible and very weird. Didnāt like the attitude. Keeps cancelling class and disappearing. "

RAM MOHAN A.

R

Rajesh

Verified Student

Reviewed on 02 Jul, 2022

Class 10 Tuition

"It has been good experience so far. I would request you to resolve last year's question papers chapter wise as on when you progress on chapter. It will help her to keep thorough preparation for term exam as well as board . Also , request you to take exam chapter wise from your end . Is it possible to take 2 hours class together on Saturday instead of taking one hour class on Sunday. Please let us know. "

RAM MOHAN A.

M

Manvika

Verified Student

Reviewed on 26 Aug, 2021

Class 9 Tuition

"A very good teacher and a knowledgeable one also. I have seen improvement in my grades before and after joining the classes. During my exam times the revision given by teacher was very helpful. "

RAM MOHAN A.

M

Mohor

Verified Student

Reviewed on 03 Aug, 2021

Class 10 Tuition

"Very Good classes. Great explanation of topic. Always helped with step-by-step explanation. Very Helpful. "

Have you attended any class with Ram Mohan?

1. Which school boards of Class 10 do you teach for?

State, International Baccalaureate, ICSE and others

2. Do you have any prior teaching experience?

Yes

3. Which classes do you teach?

I teach Class 10 Tuition and Class 9 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 20 years.

Answered on 08/12/2016 Learn CBSE/Class 10/Mathematics

If 'r' stands for the percentage rate of Sales Tax say then (100+r) will be the Sale Price. While its cost price is 100 and 'r' will be the Sales Tax '. Therefore, if 'SP stands for actual Sale Price and 'ST' stands for actual Sales tax then we have:- (100+r) : r :: SP : ST OR (100+r)/r = SP / ST... ...more

If 'r' stands for the percentage rate of Sales Tax say then (100+r) will be the Sale Price. While its cost price is 100 and 'r' will be the Sales Tax '. Therefore, if 'SP stands for actual Sale Price and 'ST' stands for actual Sales tax then we have:- (100+r) : r :: SP : ST OR (100+r)/r = SP / ST From this formula , given the values of any two of 'r' ; 'SP' ; 'ST' the value of the third can be found. In the given Sum, r = 10, SP = 17600 ST =? from the above formula, we can write ST =r * SP /(100+r) = 10 * 17600 /(100+10) = 10 * 17600/110 = Rs.1600. Therefore, the Sales Tax on the Refrigerator is Rs.1600.

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Answers 7 Comments Answered on 02/12/2016 Learn CBSE/Class 10/Mathematics

If l, b, h, S and V are length, breadth, height, surface area and volume respectively of a cuboid, Then We have S = 2( lb + bh + lh ) and V = lbh Let us take the relation S = 2(lb +bh + lh). Now dividing both sides with V * S, we get 1/V = 2 ( lb + bh = lh )/ (V * S) = 2 ( lb + bh +lh )/ (lbh *... ...more

If l, b, h, S and V are length, breadth, height, surface area and volume respectively of a cuboid, Then We have S=2( lb + bh + lh ) and V=lbh Let us take the relation S=2(lb +bh + lh). Now dividing both sides with V * S, we get 1/V = 2 ( lb + bh=lh )/ (V * S) = 2 ( lb + bh +lh )/ (lbh * S) ...... ( after Substituting lbh for V) ==> 1/V = 2 [(lb/lbh )+( bh/lbh ) + (lh/lbh )] / S==> 1/V = 2/S(1/l + 1/b + 1/h) proved.

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Answers 4 Comments Answered on 02/12/2016 Learn CBSE/Class 10/Mathematics

If l, b, h, S and V are length, breadth, height, surface area and volume respectively of a cuboid, Then, V = lbh Let us take the relation S = 2 (lb +bh + lh). Now dividing both sides with V * S, we get:- 1/V = 2 ( lb + bh = lh )/ (V * S) = 2 ( lb + bh = lh )/ (lbh * S) ...... ( Substituting lbh for... ...more

If l, b, h, S and V are length, breadth, height, surface area and volume respectively of a cuboid, Then, V=lbh Let us take the relation S=2 (lb +bh + lh). Now dividing both sides with V * S, we get:- 1/V = 2 ( lb + bh=lh )/ (V * S) = 2 ( lb + bh=lh )/ (lbh * S) ...... ( Substituting lbh for V) ==> 1/V = =2 [(lb/lbh )+( bh/lbh ) + (lh/ibh )] / S==> 1/V = 2/S(1/l + 1/b + 1/h) proved.

Like 0

Answers 4 Comments Answered on 28/11/2016 Learn CBSE/Class 10/Mathematics

Given that A:B = 4:5, B:C = 6:7 and C:D = 14:15. Therefore, A/B =4/5; B/A = 6/7; C/D = 14/15 We can write A/D as A/D = A/B * B/C *C/D = 4/5 * 6/7 * 14/15 = 16/25 Thus, A : D = 16 : 25.

Like 0

Answers 8 Comments Answered on 25/11/2016 Learn CBSE/Class 10/Mathematics

We know that, log 'x' to base 'y' = log 'x' to base ' z ' * log'z' to base' y' ............. (1) and log 'p' to base 'q' = 1/ log 'q' to base 'x' ............(2) In the present context, It is given that log 'x' to base '3' = A log 'x'to base '5' by using formula (2) above, we can rewrite this equation... ...more

We know that, log 'x' to base 'y' = log 'x' to base ' z ' * log'z' to base' y' ............. (1) and log 'p' to base 'q' = 1/ log 'q' to base 'x' ............(2) In the present context, It is given that log 'x' to base '3' = A log 'x'to base '5' by using formula (2) above, we can rewrite this equation as:- log 'x' to base '3' = A * 1/ log '5' to base 'x' ==> log '5' to base 'x' * log 'x' to base '3' = A==> log '5' to base '3' = A ( [By using the Formula (1) above, (log'5' to base 'x' * log 'x' to base '3') becomes (" log '5' to base '3'). Therefore, A = log 5 to base 3.

Like 0

Answers 4 Comments Class 10 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

20

Board

State, International Baccalaureate, ICSE, CBSE, IGCSE

State boards taught

Andhra Pradesh State Board

IB Subjects taught

Mathematics, Physics, Chemistry

Preferred class strength

Group Classes, One on one/ Private Tutions

CBSE Subjects taught

Mathematics, Science

ICSE Subjects taught

Physics, Mathematics, Chemistry

IGCSE Subjects taught

Mathematics, Physics, Chemistry

Experience in School or College

Taught in School or College

Yes

State Syllabus Subjects taught

Science, Mathematics

Teaching Experience in detail in Class 10 Tuition

Teaching is my Passion. I have taught Mathematics, Physics and Chemistry to several students during 20+ years of my teaching. Many of my students who initially were scarred of Mathematics, have developed interest on the subject and opted MPC group in their Intermediate and are now earning Dollars as Software Engineers in USA, CANADA, UK and Australia.

Class 9 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

20

Board

State, International Baccalaureate, ICSE, CBSE

State boards taught

Andhra Pradesh State Board

IB Subjects taught

Mathematics, Physics, Chemistry

Preferred class strength

Group Classes, One on one/ Private Tutions

CBSE Subjects taught

Mathematics, Science

ICSE Subjects taught

Physics, Mathematics, Chemistry

Experience in School or College

Taught in School or College

Yes

State Syllabus Subjects taught

Science, Mathematics

Teaching Experience in detail in Class 9 Tuition

Teaching is my Passion. I have taught Maths, Physics and Chemistry to several students during 20 years of my teaching. Many of my students who initially were scarred of Maths, have developed interest on the subject and opted MPC group in their Intermediate and are now earning Dollars as Software Engineers in USA,CANADA,UK and Australia.

Answered on 08/12/2016 Learn CBSE/Class 10/Mathematics

If 'r' stands for the percentage rate of Sales Tax say then (100+r) will be the Sale Price. While its cost price is 100 and 'r' will be the Sales Tax '. Therefore, if 'SP stands for actual Sale Price and 'ST' stands for actual Sales tax then we have:- (100+r) : r :: SP : ST OR (100+r)/r = SP / ST... ...more

If 'r' stands for the percentage rate of Sales Tax say then (100+r) will be the Sale Price. While its cost price is 100 and 'r' will be the Sales Tax '. Therefore, if 'SP stands for actual Sale Price and 'ST' stands for actual Sales tax then we have:- (100+r) : r :: SP : ST OR (100+r)/r = SP / ST From this formula , given the values of any two of 'r' ; 'SP' ; 'ST' the value of the third can be found. In the given Sum, r = 10, SP = 17600 ST =? from the above formula, we can write ST =r * SP /(100+r) = 10 * 17600 /(100+10) = 10 * 17600/110 = Rs.1600. Therefore, the Sales Tax on the Refrigerator is Rs.1600.

Like 0

Answers 7 Comments Answered on 02/12/2016 Learn CBSE/Class 10/Mathematics

If l, b, h, S and V are length, breadth, height, surface area and volume respectively of a cuboid, Then We have S = 2( lb + bh + lh ) and V = lbh Let us take the relation S = 2(lb +bh + lh). Now dividing both sides with V * S, we get 1/V = 2 ( lb + bh = lh )/ (V * S) = 2 ( lb + bh +lh )/ (lbh *... ...more

If l, b, h, S and V are length, breadth, height, surface area and volume respectively of a cuboid, Then We have S=2( lb + bh + lh ) and V=lbh Let us take the relation S=2(lb +bh + lh). Now dividing both sides with V * S, we get 1/V = 2 ( lb + bh=lh )/ (V * S) = 2 ( lb + bh +lh )/ (lbh * S) ...... ( after Substituting lbh for V) ==> 1/V = 2 [(lb/lbh )+( bh/lbh ) + (lh/lbh )] / S==> 1/V = 2/S(1/l + 1/b + 1/h) proved.

Like 0

Answers 4 Comments Answered on 02/12/2016 Learn CBSE/Class 10/Mathematics

If l, b, h, S and V are length, breadth, height, surface area and volume respectively of a cuboid, Then, V = lbh Let us take the relation S = 2 (lb +bh + lh). Now dividing both sides with V * S, we get:- 1/V = 2 ( lb + bh = lh )/ (V * S) = 2 ( lb + bh = lh )/ (lbh * S) ...... ( Substituting lbh for... ...more

If l, b, h, S and V are length, breadth, height, surface area and volume respectively of a cuboid, Then, V=lbh Let us take the relation S=2 (lb +bh + lh). Now dividing both sides with V * S, we get:- 1/V = 2 ( lb + bh=lh )/ (V * S) = 2 ( lb + bh=lh )/ (lbh * S) ...... ( Substituting lbh for V) ==> 1/V = =2 [(lb/lbh )+( bh/lbh ) + (lh/ibh )] / S==> 1/V = 2/S(1/l + 1/b + 1/h) proved.

Like 0

Answers 4 Comments Answered on 28/11/2016 Learn CBSE/Class 10/Mathematics

Like 0

Answers 8 Comments Answered on 25/11/2016 Learn CBSE/Class 10/Mathematics

We know that, log 'x' to base 'y' = log 'x' to base ' z ' * log'z' to base' y' ............. (1) and log 'p' to base 'q' = 1/ log 'q' to base 'x' ............(2) In the present context, It is given that log 'x' to base '3' = A log 'x'to base '5' by using formula (2) above, we can rewrite this equation... ...more

We know that, log 'x' to base 'y' = log 'x' to base ' z ' * log'z' to base' y' ............. (1) and log 'p' to base 'q' = 1/ log 'q' to base 'x' ............(2) In the present context, It is given that log 'x' to base '3' = A log 'x'to base '5' by using formula (2) above, we can rewrite this equation as:- log 'x' to base '3' = A * 1/ log '5' to base 'x' ==> log '5' to base 'x' * log 'x' to base '3' = A==> log '5' to base '3' = A ( [By using the Formula (1) above, (log'5' to base 'x' * log 'x' to base '3') becomes (" log '5' to base '3'). Therefore, A = log 5 to base 3.

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