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Q18:

A spiral is made up of successive semicircles, with centres alternately at A and B, starting with centre at A, of radii 0.5 cm, 1.0 cm, 1.5 cm, 2.0 cm, . . . as shown in Fig. 5.4. What is the total length of such a spiral made up of thirteen consecutive semicircles? (Take $\pi = \frac{22}{7}$) [Hint : Length of successive semicircles is $l_1, l_2, l_3, l_4, . . .$ with centres at A, B, A, B, . . ., respectively.]

Solution :

Given:

A spiral is formed by successive semicircles with centers alternating between points A and B. The radii of these semicircles form an arithmetic progression: $r_1 = 0.5\text{ cm}$, $r_2 = 1.0\text{ cm}$, $r_3 = 1.5\text{ cm}$, $r_4 = 2.0\text{ cm}$, and so on. The total number of semicircles is $n = 13$. The value of $\pi$ is given as $\frac{22}{7}$.

To Find:

The total length of the spiral, which is the sum of the lengths of the 13 consecutive semicircles.

A B Spiral of Semicircles

Step 1: Determine the formula for the length of each semicircle.

The circumference of a full circle is $2\pi r$. Therefore, the length of a semicircle with radius $r$ is given by $l = \pi r$.

Let $l_1, l_2, l_3, \dots, l_{13}$ be the lengths of the 13 semicircles.

$l_1 = \pi r_1 = \pi(0.5)$

$l_2 = \pi r_2 = \pi(1.0)$

$l_3 = \pi r_3 = \pi(1.5)$

... and so on.

Step 2: Identify the Arithmetic Progression (AP).

The sequence of lengths is: $\pi(0.5), \pi(1.0), \pi(1.5), \dots$

This is an AP where:

First term ($a$) = $0.5\pi$

Common difference ($d$) = $l_2 - l_1 = \pi(1.0) - \pi(0.5) = 0.5\pi$

Number of terms ($n$) = $13$

Step 3: Apply the sum formula for an AP.

The sum of the first $n$ terms of an AP is given by the formula: $S_n = \frac{n}{2} [2a + (n - 1)d]$

Substituting the known values:

$S_{13} = \frac{13}{2} [2(0.5\pi) + (13 - 1)(0.5\pi)]$

$S_{13} = \frac{13}{2} [1.0\pi + 12(0.5\pi)]$

$S_{13} = \frac{13}{2} [1.0\pi + 6.0\pi]$

$S_{13} = \frac{13}{2} [7\pi]$

Step 4: Calculate the final numerical value.

Substitute $\pi = \frac{22}{7}$ into the expression:

$S_{13} = \frac{13}{2} \times 7 \times \frac{22}{7}$

[Canceling the 7 in the numerator and denominator]:

$S_{13} = \frac{13}{2} \times 22$

$S_{13} = 13 \times 11$

$S_{13} = 143$

Final Answer: The total length of the spiral is 143 cm.


More Questions from Class 10 Mathematics Arithmetic Progression EXERCISE 5.3


CBSE Solutions for Class 10 Mathematics Arithmetic Progression


Chapters in CBSE - Class 10 Mathematics


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