default_background

Find the best tutors and institutes for Class 10 Tuition

Find Best Class 10 Tuition

Please select a Category.

Please select a Locality.

No matching category found.

No matching Locality found.

Q7:
From a point on the ground, the angles of elevation of the bottom and the top of a transmission tower fixed at the top of a $20$ m high building are $45°$ and $60°$ respectively. Find the height of the tower.

Solution :

Given:

  • Height of the building ($BC$) = $20$ m.
  • The transmission tower ($CD$) is fixed on top of the building.
  • Angle of elevation from a point $A$ on the ground to the bottom of the tower (point $C$) = $45^\circ$.
  • Angle of elevation from point $A$ on the ground to the top of the tower (point $D$) = $60^\circ$.

To find:

The height of the transmission tower ($h = CD$).

A B C D 45° 60° 20m h

Step 1: Define variables and identify triangles.

Let $AB = x$ be the distance from the point on the ground to the base of the building. Let $CD = h$ be the height of the tower. The total height of the building and tower is $BD = BC + CD = 20 + h$.

Step 2: Analyze $\triangle ABC$ (Right-angled at $B$).

In $\triangle ABC$, the angle of elevation $\angle BAC = 45^\circ$.

Using the trigonometric ratio: $\tan(\theta) = \frac{\text{Opposite}}{\text{Adjacent}}$

$\tan(45^\circ) = \frac{BC}{AB}$

Since $\tan(45^\circ) = 1$ [Trigonometric table value]:

$1 = \frac{20}{x}$

$x = 20$ m [Equation 1]

Step 3: Analyze $\triangle ABD$ (Right-angled at $B$).

In $\triangle ABD$, the angle of elevation $\angle BAD = 60^\circ$.

$\tan(60^\circ) = \frac{BD}{AB}$

Since $\tan(60^\circ) = \sqrt{3}$ [Trigonometric table value]:

$\sqrt{3} = \frac{20 + h}{x}$

Step 4: Solve for $h$.

Substitute $x = 20$ from Equation 1 into the equation from Step 3:

$\sqrt{3} = \frac{20 + h}{20}$

$20\sqrt{3} = 20 + h$ [Multiplying both sides by 20]

$h = 20\sqrt{3} - 20$

$h = 20(\sqrt{3} - 1)$

Using $\sqrt{3} \approx 1.732$:

$h = 20(1.732 - 1)$

$h = 20(0.732)$

$h = 14.64$ m

Final Answer: The height of the transmission tower is $20(\sqrt{3} - 1)$ m or approximately $14.64$ m.


More Questions from Class 10 Mathematics Applications of Trigonometry EXERCISE 9.1


CBSE Solutions for Class 10 Mathematics Applications of Trigonometry


Chapters in CBSE - Class 10 Mathematics


Top Tutors who teach Applications of Trigonometry

(6)
Top Tutor
locationImg Bajaj Nagar, Nagpur
experience 3 yrs of Exp students 1 student
Tutor
Online Classes Online Classes
homeTutions Student's Home

Coaching is about improvising a student from where he/she is at. Not about converting an already bright student into an achiever. It should be obvious. The whole idea of ONE ON ONE coaching is to improvise and to elimate the problems in a detailed manner, exactly the way a student desires. To connect and respond to a student cannot be everybodys cup of tea. This is where a capable one comes in to fill the gaps where modern day educationalists fail to fill.

Skills: Mathematics , Physics and more
Also teaches: Class 8 Tuition, BTech Tuition and more

(43)
Top Tutor
locationImg SCB Nagar, Kothagudem
experience 20 yrs of Exp students 31 students
greenClock 1966 hrs of classes completed
rsIcon 450 per hour
Mathematics Facilitator 22 Years experience
Online Classes Online Classes

22 Years Experience in Schools IN ICSE/CBSE/IGCSE IN DIFFERENT STATE BOARDS

Abhinav Sidhardha

Sir is very friendly teacher he will support us more he is the best teacher of the year his teaching skills are really good.

Skills: Mathematics , Science and more
Also teaches: Math Olympiad, Class 8 Tuition and more

(5)
Top Tutor
locationImg Chopasni Housing Board, Jodhpur
experience 5 yrs of Exp
LEARN WITH ME AND FEEL THE DIFFERENCE IN YOUR MARKS
Online Classes Online Classes
regularClasses Tutor's home

My aim is to prepare students in there best ability and help them achieve good marks. My students scored above 80% in all subjects in class 10th

Skills: English , Mathematics and more
Also teaches: Class 11 Tuition, Class 9 Tuition and more

(7)
Top Tutor
locationImg Sector 12, Noida
experience 6 yrs of Exp students 4 students
greenClock 148 hrs of classes completed
rsIcon 400 per hour
M.Tech , M.Sc More than six years of teaching experience
Online Classes Online Classes

I have worked as PGT teacher in one of the best CBSE schools and all of my students gained more than 90 percent marks. I have full concept of subjects and can assist students in gaining more than 90 percent marks.

Diya Yadav

She’s a excellent teacher , her behaviour her talking style is very sweet and if you didn’t understand any topic she’ll repeat it for you as many times you want!! Satisfied and loved her teaching

Skills: Mathematics , Science and more
Also teaches: Class I-V Tuition, Class 9 Tuition and more

(1)
Top Tutor
locationImg Munirka, Delhi
experience 3 yrs of Exp students 1 student
greenClock 48 hrs of classes completed
rsIcon 200 per hour
Online Classes Online Classes

I am a teacher since last 3-4 years. I have teaching tuition to students of class 9th and 10th CBSE board. In these covid times i prefer online classes and my subjects of expertise are science, maths ans social science.

Skills: Mathematics , Physics and more
Also teaches: Class 9 Tuition

Find more Tutor for Applications of Trigonometry in your City


Other Subjects in CBSE - Class 10

Worksheet Icon

Download free CBSE - Class 10 Mathematics Applications of Trigonometry EXERCISE 9.1 worksheets

Download Now

Find Best Class 10 Tuition ?

Find Now »