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Q1:

A circus artist is climbing a $20$ m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole, if the angle made by the rope with the ground level is $30°$ (see Fig. 9.11).

 

Solution :

Given:

  • Length of the rope ($AC$) = $20$ m.
  • Angle made by the rope with the ground level ($\angle C$) = $30^\circ$.
  • The pole is vertical, meaning the angle between the pole and the ground is $90^\circ$ ($\angle B = 90^\circ$).

To Find:

  • The height of the pole ($AB$).

Visual Representation:

20 m h 30° C B A

Step 1: Defining the Variables and Trigonometric Relationship

Let $AB$ be the height of the vertical pole. Let $AC$ be the length of the rope. In the right-angled triangle $\triangle ABC$, where $\angle B = 90^\circ$:

  • The side opposite to the angle $\angle C$ is $AB$ (the height of the pole).
  • The side opposite to the right angle $\angle B$ is $AC$ (the hypotenuse, which is the rope).

We use the trigonometric ratio that relates the opposite side and the hypotenuse, which is the sine function:

$\sin(\theta) = \frac{\text{Opposite}}{\text{Hypotenuse}}$

Step 2: Setting up the Equation

Substituting the known values into the sine formula:

$\sin(30^\circ) = \frac{AB}{AC}$

Given that $AC = 20$ m and $\sin(30^\circ) = \frac{1}{2}$ [Standard trigonometric value]:

$\frac{1}{2} = \frac{AB}{20}$

Step 3: Solving for $AB$

To isolate $AB$, multiply both sides of the equation by $20$:

$AB = 20 \times \frac{1}{2}$

$AB = 10$

Step 4: Conclusion

The height of the pole is $10$ meters.

Final Answer: The height of the pole is 10 m.


More Questions from Class 10 Mathematics Applications of Trigonometry EXERCISE 9.1


CBSE Solutions for Class 10 Mathematics Applications of Trigonometry


Chapters in CBSE - Class 10 Mathematics


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