default_background

Find the best tutors and institutes for Class 10 Tuition

Find Best Class 10 Tuition

Please select a Category.

Please select a Locality.

No matching category found.

No matching Locality found.

Q13:
As observed from the top of a $75$ m high lighthouse from the sea-level, the angles of depression of two ships are $30°$ and $45°$. If one ship is exactly behind the other on the same side of the lighthouse, find the distance between the two ships.

Solution :

Given:

  • Height of the lighthouse ($AB$) = $75$ m.
  • Angle of depression of the first ship ($C$) = $45^\circ$.
  • Angle of depression of the second ship ($D$) = $30^\circ$.
  • The ships are on the same side of the lighthouse and lie on the same straight line.

To Find:

The distance between the two ships, i.e., the length of segment $CD$.

75m A B C D 45° 30°

Step 1: Defining Variables and Geometric Relationships

Let $AB$ be the lighthouse of height $75$ m. Let $C$ and $D$ be the positions of the two ships. Since the angles of depression are $45^\circ$ and $30^\circ$, the angles of elevation from the ships to the top of the lighthouse are also $45^\circ$ and $30^\circ$ respectively [By the property of alternate interior angles].

Let $BC = x$ and $BD = y$. The distance between the ships is $CD = y - x$.

Step 2: Calculating distance $BC$ in $\triangle ABC$

In right-angled triangle $\triangle ABC$:

$\tan(45^\circ) = \frac{\text{Opposite}}{\text{Adjacent}} = \frac{AB}{BC}$

We know $\tan(45^\circ) = 1$ and $AB = 75$ m.

$1 = \frac{75}{x}$

$x = 75$ m

Step 3: Calculating distance $BD$ in $\triangle ABD$

In right-angled triangle $\triangle ABD$:

$\tan(30^\circ) = \frac{\text{Opposite}}{\text{Adjacent}} = \frac{AB}{BD}$

We know $\tan(30^\circ) = \frac{1}{\sqrt{3}}$ and $AB = 75$ m.

$\frac{1}{\sqrt{3}} = \frac{75}{y}$

$y = 75\sqrt{3}$ m

Step 4: Finding the distance between the ships ($CD$)

The distance between the two ships is $CD = BD - BC$.

$CD = y - x$

$CD = 75\sqrt{3} - 75$

$CD = 75(\sqrt{3} - 1)$

Using the approximation $\sqrt{3} \approx 1.732$:

$CD = 75(1.732 - 1)$

$CD = 75(0.732)$

$CD = 54.9$ m

Final Answer: The distance between the two ships is $75(\sqrt{3} - 1)$ m or approximately $54.9$ m.


More Questions from Class 10 Mathematics Applications of Trigonometry EXERCISE 9.1


CBSE Solutions for Class 10 Mathematics Applications of Trigonometry


Chapters in CBSE - Class 10 Mathematics


Top Tutors who teach Applications of Trigonometry

(15)
Top Tutor
locationImg Ashok Vihar, Gurgaon
experience 10 yrs of Exp students 1 student
greenClock 209 hrs of classes completed
rsIcon 350 per hour
Experienced & Certified Maths Lecturer with 10+ years of teaching experience
Online Classes Online Classes

With a strong academic foundation in Mathematics, including an M.Sc. in Mathematics, B.Sc., BTC, and CTET qualification, I am a dedicated Mathematics educator committed to helping students build conceptual clarity, logical reasoning, and analytical problem-solving skills. I have been successfully teaching Mathematics for over 12 years through my coaching institute in Gurgaon, while also conducting engaging online classes for students across India and internationally. I teach students across CBSE, ICSE, NIOS, and State Boards, adapting my teaching methodology to suit each curriculum and the individual learning needs of every student. My teaching approach focuses on simplifying complex mathematical concepts through structured lesson planning, personalised instruction, continuous assessment, and interactive learning techniques. I believe every student can excel in Mathematics with the right guidance, consistent practice, and a strong conceptual foundation. I also specialise in Vedic Mathematics, helping students significantly improve calculation speed, accuracy, mental agility, and confidence in school, competitive, and entrance examinations. As an UrbanPro Super Tutor, I am recognised for consistently delivering high-quality teaching and maintaining excellent student and parent satisfaction. Over the years, I have helped hundreds of students achieve outstanding academic results while developing confidence and a genuine interest in Mathematics. My passion for teaching, commitment to academic excellence, and student-centred approach enable me to create an engaging, motivating, and result-oriented learning environment where every learner can achieve their highest potential. If you are looking for a dedicated and experienced Mathematics tutor who can help you achieve excellent results and build strong fundamentals, I invite you to book a demo class today. Let’s work together to make Mathematics simple, enjoyable, and rewarding for you!

Palak Gupta

Jaya mam helped me to learn different concepts of mathematics. She is very experienced and helpful. Thanks.

Skills: Mathematics
Also teaches: Class 7 Tuition, Class 8 Tuition and more

(16)
Top Tutor
locationImg Begur Road, Bangalore
experience 5 yrs of Exp students 3 students
greenClock 4 hrs of classes completed
rsIcon 300 per hour
To Teach students in a very simple and easy level and more that 5 years of experience.
Online Classes Online Classes
regularClasses Tutor's home

I have been teaching since last more than 5 years. My way of teaching style is so simple so that it make students very easier to understand. I am taking classes of Math, Hindi and Sanskrit subject.

Skills: Mathematics , Physics and more
Also teaches: Class 11 Tuition, Class 7 Tuition and more

(9)
Top Tutor
locationImg Bavdhan Vidnyan Nagar, Pune
experience 5 yrs of Exp students 1 student
greenClock 54 hrs of classes completed
rsIcon 250 per hour
You can visit my blog and call me directly at 7709072277
Online Classes Online Classes
regularClasses Tutor's home

I have taught in an institution to state ,ICSE , CBSE kids. Extra-ordinary Results. Ample of Study Material will be provided. We can have a demo class . You would enjoy the interactive and interesting sessions.

Vikram Singh

My experience with Parag sir was great, It is because of him that I got really good grades in my 10th and 12th standard.

Skills: English , Mathematics and more

Ramakrishna Koutha Class 10 Tuition trainer in Mount Olive
(17)
Top Tutor
locationImg Flanders, Mount Olive
experience 5 yrs of Exp students 2 students
greenClock 22 hrs of classes completed
rsIcon 100 per hour
Experience Software engineer and volunteer teacher in math , science and computer science.
Online Classes Online Classes

I have volunteer teacher for evidyaloka ..I thought higg school students math and science

Skills: Mathematics , Physics and more

(11)
Top Tutor
locationImg Melakalkandarkottai, Tiruchirappalli
experience 10 yrs of Exp students 1 student
greenClock 15 hrs of classes completed
rsIcon 300 per hour
M.Sc.,B.Ed. with 13 years of teaching experience
Online Classes Online Classes
homeTutions Student's Home

I specialize in Class 10 Mathematics tuition with an exam-oriented and concept-based teaching approach. I simplify complex mathematical concepts using step-by-step explanations, making them easy for students to understand and apply confidently. I assess each student's learning level, identify weak areas, and provide personalized guidance to improve both accuracy and speed. My classes include regular practice, chapter-wise tests, previous years' board exam questions, doubt-clearing sessions, and effective exam strategies. I maintain a friendly and motivating learning environment where students feel comfortable asking questions. My objective is to help every student strengthen their mathematical foundation, gain confidence, and achieve excellent results in the Class 10 board examinations.

Sathesh

Experienced Mathematics tutor with a strong focus on concept-based learning. I help students improve their understanding, problem-solving skills, and academic performance through personalized guidance.

Skills: Mathematics

Find more Tutor for Applications of Trigonometry in your City


Other Subjects in CBSE - Class 10

Worksheet Icon

Download free CBSE - Class 10 Mathematics Applications of Trigonometry EXERCISE 9.1 worksheets

Download Now

Find Best Class 10 Tuition ?

Find Now »