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Q5:
A kite is flying at a height of $60$ m above the ground. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is $60°$. Find the length of the string, assuming that there is no slack in the string.
Solution :
Given:
1. The height of the kite above the ground ($AB$) = $60$ m.
2. The angle of inclination of the string with the ground ($\angle ACB$) = $60^\circ$.
3. The string is assumed to be taut (no slack), forming a straight line.
To Find:
The length of the string ($AC$).
Step 1: Defining the Geometric Model
Let the position of the kite be point $A$, the point on the ground directly below the kite be $B$, and the point where the string is tied to the ground be $C$.
This forms a right-angled triangle $\triangle ABC$, where:
- $\angle B = 90^\circ$ (The height is measured perpendicular to the ground).
- $AB = 60$ m (The side opposite to $\angle C$).
- $\angle C = 60^\circ$ (The angle of inclination).
- $AC$ is the length of the string (the hypotenuse of the triangle).
Step 2: Selecting the Trigonometric Ratio
In a right-angled triangle, the relationship between the side opposite to an angle and the hypotenuse is given by the sine function:
$\sin(\theta) = \frac{\text{Opposite}}{\text{Hypotenuse}}$
Applying this to $\triangle ABC$:
$\sin(60^\circ) = \frac{AB}{AC}$
Step 3: Substituting Known Values
We know that $\sin(60^\circ) = \frac{\sqrt{3}}{2}$ [Standard trigonometric value].
Substituting the values into the equation:
$\frac{\sqrt{3}}{2} = \frac{60}{AC}$
Step 4: Solving for $AC$
To isolate $AC$, we perform cross-multiplication:
$\sqrt{3} \times AC = 60 \times 2$
$\sqrt{3} \times AC = 120$
$AC = \frac{120}{\sqrt{3}}$
Step 5: Rationalizing the Denominator
To simplify the expression, multiply the numerator and denominator by $\sqrt{3}$:
$AC = \frac{120}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}}$
$AC = \frac{120\sqrt{3}}{3}$
$AC = 40\sqrt{3}$
Step 6: Final Calculation
Using the approximation $\sqrt{3} \approx 1.732$:
$AC = 40 \times 1.732 = 69.28$ m
Final Answer: The length of the string is $40\sqrt{3}$ m or approximately $69.28$ m.
More Questions from Class 10 Mathematics Applications of Trigonometry EXERCISE 9.1
- Q1: A circus artist is climbing a $20$ m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole, if the angle made by the rope with the ground level is $30°$ (see Fig. 9.11).
- Q2: A tree breaks due to storm and the broken part bends so that the top of the tree touches the ground making an angle $30°$ with it. The distance between the foot of the tree to the point where the top touches the ground is $8$ m. Find the height of the tree.
- Q3: A contractor plans to install two slides for the children to play in a park. For the children below the age of $5$ years, she prefers to have a slide whose top is at a height of $1.5$ m, and is inclined at an angle of $30°$ to the ground, whereas for elder children, she wants to have a steep slide at a height of $3$m, and inclined at an angle of $60°$ to the ground. What should be the length of the slide in each case?
- Q4: The angle of elevation of the top of a tower from a point on the ground, which is $30$ m away from the foot of the tower, is $30°$. Find the height of the tower.
- Q6: A $1.5$ m tall boy is standing at some distance from a $30$ m tall building. The angle of elevation from his eyes to the top of the building increases from $30°$ to $60°$ as he walks towards the building. Find the distance he walked towards the building.
- Q7: From a point on the ground, the angles of elevation of the bottom and the top of a transmission tower fixed at the top of a $20$ m high building are $45°$ and $60°$ respectively. Find the height of the tower.
- Q8: A statue, $1.6$ m tall, stands on the top of a pedestal. From a point on the ground, the angle of elevation of the top of the statue is $60°$ and from the same point the angle of elevation of the top of the pedestal is $45°$. Find the height of the pedestal.
- Q9: The angle of elevation of the top of a building from the foot of the tower is $30°$ and the angle of elevation of the top of the tower from the foot of the building is $60°$. If the tower is $50$ m high, find the height of the building.
- Q10: Two poles of equal heights are standing opposite each other on either side of the road, which is $80$ m wide. From a point between them on the road, the angles of elevation of the top of the poles are $60°$ and $30°$, respectively. Find the height of the poles and the distances of the point from the poles.
- Q11: A TV tower stands vertically on a bank of a canal. From a point on the other bank directly opposite the tower, the angle of elevation of the top of the tower is $60°$. From another point $20$ m away from this point on the line joing this point to the foot of the tower, the angle of elevation of the top of the tower is $30°$ (see Fig. 9.12). Find the height of the tower and the width of the canal.
- Q12: From the top of a $7$ m high building, the angle of elevation of the top of a cable tower is $60°$ and the angle of depression of its foot is $45°$. Determine the height of the tower.
- Q13: As observed from the top of a $75$ m high lighthouse from the sea-level, the angles of depression of two ships are $30°$ and $45°$. If one ship is exactly behind the other on the same side of the lighthouse, find the distance between the two ships.
- Q14: A $1.2$ m tall girl spots a balloon moving with the wind in a horizontal line at a height of $88.2$ m from the ground. The angle of elevation of the balloon from the eyes of the girl at any instant is $60°$. After some time, the angle of elevation reduces to $30°$ (see Fig. 9.13). Find the distance travelled by the balloon during the interval.
- Q15: A straight highway leads to the foot of a tower. A man standing at the top of the tower observes a car at an angle of depression of $30°$, which is approaching the foot of the tower with a uniform speed. Six seconds later, the angle of depression of the car is found to be $60°$. Find the time taken by the car to reach the foot of the tower from this point.
CBSE Solutions for Class 10 Mathematics Applications of Trigonometry
Chapters in CBSE - Class 10 Mathematics
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