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Java > Learn Java > How do you handle a JSON response in Java?
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How do you handle a JSON response in Java?

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Developer and Computer Science graduate from Vellore Institute of Technology, Chennai, India

Handling JSON in Java can be done using Jackson, Gson, or org.json. Jackson (best for large projects): Use ObjectMapper to parse JSON into Java objects. ObjectMapper objectMapper = new ObjectMapper(); User user = objectMapper.readValue(json, User.class); Gson (lightweight): Use Gson to...
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Handling JSON in Java can be done using Jackson, Gson, or org.json. Jackson (best for large projects): Use ObjectMapper to parse JSON into Java objects. ObjectMapper objectMapper = new ObjectMapper(); User user = objectMapper.readValue(json, User.class); Gson (lightweight): Use Gson to convert JSON to objects. Gson gson = new Gson(); User user = gson.fromJson(json, User.class); org.json (manual handling): Parse JSON using JSONObject. JSONObject obj = new JSONObject(json); String name = obj.getString("name"); Jackson is the most powerful choice. read less
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Handling a JSON response in Java depends on the library you’re using. Here is most common way: 1. Using Jackson (Most Popular) Jackson is a widely used library for handling JSON in Java. To use it, add this dependency (if using Maven): <dependency> <groupId>com.fasterxml.jackson.core</groupId>...
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Handling a JSON response in Java depends on the library you’re using. Here is mostcommon way: 1. Using Jackson (Most Popular) Jackson is a widely used library for handling JSON in Java. To use it, add this dependency (if using Maven): <dependency> <groupId>com.fasterxml.jackson.core</groupId> <artifactId>jackson-databind</artifactId> <version>2.15.0</version></dependency> Example: Convert JSON to Java Object (Deserialization) import com.fasterxml.jackson.databind.ObjectMapper; public class Main { public static void main(String[] args) throws Exception { String jsonResponse = "{ \"name\": \"John\", \"age\": 30 }"; // Convert JSON string to Java Object ObjectMapper objectMapper = new ObjectMapper(); Person person = objectMapper.readValue(jsonResponse, Person.class); System.out.println(person.getName() + " is " + person.getAge() + " years old."); }} // Java class to map JSON dataclass Person { private String name; private int age; // Getters and Setters (Required for Jackson) public String getName() { return name; } public void setName(String name) { this.name = name; } public int getAge() { return age; } public void setAge(int age) { this.age = age; }} read less
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Experienced Full Stack Developer and Instructor.

Get the JSON string (usually from an HTTP response)Use a JSON library to parse it Convert Java object to JSON
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Wroking in IT industry from last 15 years and and trained more than 5000+ Students. Conact ME

Use a library like Jackson or Gson to parse the JSON into Java objects or maps.
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Wroking in IT industry from last 15 years and and trained more than 5000+ Students. Conact ME

To handle a JSON response in Java, you typically use a library like Jackson or Gson. These libraries help parse JSON data into Java objects. First, you need to retrieve the JSON response (often from an API or a file). Then, using the library, you map the JSON structure to Java objects, such as classes...
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To handle a JSON response in Java, you typically use a library like Jackson or Gson. These libraries help parse JSON data into Java objects. First, you need to retrieve the JSON response (often from an API or a file). Then, using the library, you map the JSON structure to Java objects, such as classes or maps, based on the JSON keys and data types. This allows you to work with the data in a structured and programmatically manageable way, rather than manually extracting values from the raw JSON string. read less
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