Find the approximate value of (17/81)^(1/4) using differentiation.

Asked by Last Modified  

23 Answers

Follow 3
Answer

Please enter your answer

question is will you evaluate (97/81)^(1/4) in the same manner?
Comments
Dislike Bookmark

question is will you evaluate (97/81)^(1/4) in the same manner?
Comments
Dislike Bookmark

Tutor

Let y = f(x) = x^(1/4) To find: Approximate value of f(17/81) using differentiation We know that, f (x + delta x) = f(x) + .....using first principle 1st degree approximation. Here 'delta x' is the increment in x. Let us choose x such that f(x) is a rational number. If, x = 16/81 f(16/81)...
read more
Let y = f(x) = x^(1/4) To find: Approximate value of f(17/81) using differentiation We know that, f (x + delta x) = f(x) + [f'(x)* (delta x)].....using first principle 1st degree approximation. Here 'delta x' is the increment in x. Let us choose x such that f(x) is a rational number. If, x = 16/81 f(16/81) = 2/3 Therefore, delta x = (17/81)-(16/81) = 1/81 And f'(x) = d(x^(1/4))/dx = (1/4)* [x^ (-3/4)] So, approx. f(17/81) = f(16/81) + [(1/4)* {(16/81)^(-3/4)}] * (1/81) = (2/3) + (1/4) * (27/8) * (1/81) = (2/3) + (1/96) = 65/96 = 0.677 This is the approx value of (17/81)^(1/4) read less
Comments
Dislike Bookmark

Question is will you evaluate (97/81)^(1/4) in the same manner?
Comments
Dislike Bookmark

question is will you evaluate (97/81)^(1/4) in the same manner
Comments
Dislike Bookmark

question is will you evaluate (97/81)^(1/4) in the same manner .
Comments
Dislike Bookmark

Best Institute For Competitive Exams

65/96 is the answer. (16/81)^(1/4) = 2/3 which is useful to check your answer
Comments
Dislike Bookmark

Best Institute For Competitive Exams

Let y = f (x) = x^(1/4). Now differentiate to find delta y in terms of delta x and then find y at the given point. Realise that (16/81)^(1/4) = 2/3. On solving you will get 65/96.
Comments
Dislike Bookmark

(17/81)^1/4 = (17)^1/4/(81)^1/4 =(17)^1/4/3 Let f(x)= x^1/4 f'(x)=1/4x^3/4 {f(x+∆x)-f(x)}= f'(x)*∆x {f(x+∆x)-f(x)}=1/4x^3/4*∆x Write 17=16+1 then put x=16 abd ∆x=1 {f(16+1)-f(16)}=1/4(16)^3/4*1 f(17)-f(16)=1/4*2^4 f(17)=1/32 + f(16) f(17) = 1/32 + (16)^1/4 f(17) = 0.03125 + 2 (17)^1/4 = 2.03125 Approximate...
read more
(17/81)^1/4 = (17)^1/4/(81)^1/4 =(17)^1/4/3 Let f(x)= x^1/4 f'(x)=1/4x^3/4 {f(x+∆x)-f(x)}= f'(x)*∆x {f(x+∆x)-f(x)}=1/4x^3/4*∆x Write 17=16+1 then put x=16 abd ∆x=1 {f(16+1)-f(16)}=1/4(16)^3/4*1 f(17)-f(16)=1/4*2^4 f(17)=1/32 + f(16) f(17) = 1/32 + (16)^1/4 f(17) = 0.03125 + 2 (17)^1/4 = 2.03125 Approximate value of (17/81)^1/4 = 2.03125/3 = 0.677 read less
Comments
Dislike Bookmark

question is will you evaluate (97/81)^(1/4) in the same manner
Comments
Dislike Bookmark

View 21 more Answers

Related Questions

How should i go about preparing for IIT JEE Advanced from Class 10?
CBSE syllubus books are best. You have some more time to go threwhem .
Geethu
Will the JEE coaching fulfill the requirement for the class 12?
Yes it will. Since the concepts are made stronger it helps. But the student should also have the time management skill to prepare the answers to answer the way CBSE expects
Millennium
0 0
5
Which book is good for mathematics iit-jee advanced for class puc?
Arihant papers are good for IIT jee. Comprehensive Maths Competition section also has a variety of questions.
Ramu
Is there any test harder than IIT JEE?
UPSC is much tougher than the IIT JEE.
Sandeep
0 0
5
Is it very necessary to go for coaching classes for case class 12?
It's not necessarily , if you are thorough with the concept. Moreover you need to find time to solve problems and practice model papers.
D
0 0
5

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons

Company Secretary (CS)
Who should one do CS? Any person interested in legal matters / strategical matters should do it.

Auxano Edutech Llp

0 0
0
Must Have JEE - Advanced Books For Physics
Concepts of Physics Vol I and II by H.C. Verma :- These all-inclusive books are tailored for the students of 10+2 level. Apart from covering all the topics related to the JEE advanced syllabus, the two...

Akhil Goyal

0 0
0
Laws of Motion example application example
This video explains using laws of motion for the case of two objects where sliding has to be avoided.

Rajan Mittal

0 0
0
Chemical bonding
Question 1: What is the difference Between CO2 and SiO2, hybridization both? Answer 1: co2 is the gas, while sio2 is the glass Due to c atomic number 6, an electronic configuration is 1s2, 2s2 2p2...

Er S.

0 0
0
Importance of Measurements Units and Uncertainties.
This is the foremost important physics topic. Students very often than not forget Conversion of Units of physical quantities to one system while solving numerical questions. This leads to wrong answers...

Bipin M.

0 0
0

Recommended Articles

Get an Expert’s Guide and Tips to Make it...

An exclusive interview with Dr. Ashok Gopalakrishnan, CEO, Magnificient2 Software Services & Technology Inc. on approaching the JEE exam and how to make it to one of the IITs. Flexiguru.com: Flexiguru.com is an e-learning company offering flexible learning solutions that enhance teaching and learning. Launched with...

Read full article >

The IIT Dream: Ways to Make it True

The students who dream or make into IITs can be categorized into two -- Some planning at a very early stage and some starting at a much later stage after their first Board/Public exam. The difference may not be pronounced but the early starters have a slight edge over the latter. The competition for the elite IITs...

Read full article >

JEE Exam: Preparation Tips for Mathematics Paper

JEE (previously known as IIT JEE) is an engineering entrance exam conducted by Central Board of Secondary Education. To crack the JEE exam, students need to focus equally in all the three subjects -- Physics, Chemistry and Mathematics. One of the most critical and dreaded subjects in the JEE Syllabus is the Mathematics...

Read full article >

Why You Should Switch to Online Coaching...

Looking forward to become an IITian? Searching for best coaching mode to prepare for IIT JEE exam? Then look no further than IIT JEE online coaching classes and start preparing for the test anywhere anytime, as per your convenience. With better connectivity provisions in India, now more and more students are connected...

Read full article >

Find IIT JEE Coaching near you
IIT JEE Coaching in Delhi
IIT JEE Coaching in Mumbai
IIT JEE Coaching in Bangalore
IIT JEE Coaching in Kolkata
IIT JEE Coaching in Hyderabad
IIT JEE Coaching in Chennai
IIT JEE Coaching in Pune
IIT JEE Coaching in Jaipur
IIT JEE Coaching in Gurgaon
IIT JEE Coaching in Chandigarh
Online IIT JEE Coaching

Looking for IIT JEE Coaching ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you