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A cube of side 3 units is formed using a set of smaller cubes of side 1 unit. Find the proportion of the number of faces of the smaller cubes visible to those which are NOT visible?

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Surface area for 3 Units cube = 6 sides area = 6 x 3^2 = 6 x9 = 54 Units^2. Surface not visible is basically 4 planes in between the cubes say 2 parallel & 2 orthogonal. So area of single plane i.e. invisible = 3x3 = 9 Unit^2. So area of 4 planes invisible = 4 x 9 = 36 Unit^2. So the Proportion of the...
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Surface area for 3 Units cube = 6 sides area = 6 x 3^2 = 6 x9 = 54 Units^2. Surface not visible is basically 4 planes in between the cubes say 2 parallel & 2 orthogonal. So area of single plane i.e. invisible = 3x3 = 9 Unit^2. So area of 4 planes invisible = 4 x 9 = 36 Unit^2. So the Proportion of the Number of Faces visible to Number of faces NOT visible = 54/36 = 6/4 = 1.5. The answer is 1.5 or Proportion is 3:2. read less
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