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Kartika 09/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Compound Interest

What happen to the time period if the interest is compounded half yearly?

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Sreedevi replied | 07/12/2016

Time period gets doubled and Rate become half.

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Shambhavi replied | 07/12/2016

Time period gets doubled in this case.

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Rawinder 09/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Compound Interest

The SI on a sum of money is 1/9 of the principle, and the number of years is equal to the rate % per annum. Find the rate %?

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Sarvajeet replied | 26/11/2016

(10/3)%

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Rituraj 09/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Compound Interest

Ramesh invests Rs. 12800 for three years at the rate of 10% per annum compound interest. Find the sum due to Ramesh at the end of the first year?

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Sreedevi replied | 21/11/2016

The amount at the end of Year I is 10% of the principle added to the principle itself. So it would be 12800+(10% of 12800)=14080

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V

Vijay 09/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Compound Interest

The cost of car, purchased 2 years ago, depreciates at the rate of 20% every year. If its present worth is Rs 315600, find its purchase value?

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Ashwini replied | 26/11/2016

Rs. 493175.

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V

Vinay 09/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Compound Interest

What is the formula for finding amount?

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Kumar replied | 27/11/2016

A=P(1+r/100)^n. Where, A is amount, P is Principal , r is rate p.a., n is nos. of years.

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Supriyo 09/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Compound Interest

The difference between simple interest and compound interest compounded annually on a certain sum of money for 2 years at 4% per annum is Rs 1. What is the sum of rupees?

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Ram Mohan replied | 18/11/2016

If 'P' is the Principal Sum , then Compound Interest (CI) @4%, after 2 years is:
CI = P{ (1+4/100) (1+4/100) -1} =P { 1+16/10000 +2*4/100 -1} = P{16/10000+2*4/100}
Simple Interest SI, @ 4% after 2 years is:
SI = P*2*4/100
It is given that, CI - SI= Rs.1, Substituting the values of CI and SI in the above eqn, we get:
P{16/10000 + 2*4/100} - P*2*4/100 =1,...  more»
If 'P' is the Principal Sum , then Compound Interest (CI) @4%, after 2 years is:
CI = P{ (1+4/100) (1+4/100) -1} =P { 1+16/10000 +2*4/100 -1} = P{16/10000+2*4/100}
Simple Interest SI, @ 4% after 2 years is:
SI = P*2*4/100
It is given that, CI - SI= Rs.1, Substituting the values of CI and SI in the above eqn, we get:
P{16/10000 + 2*4/100} - P*2*4/100 =1, ==> P*16/10000 = 1, ==> P = 10000/16, ==> p= 625
Therefore, the principal Sum lent was, Rs.625/-
One Can use the Formula
P*(r/100)*(r/100) = d , where, 'P' is Principal Sum, 'r' is rate of interest for a prescribed period, and 'd' is the difference between CI and SI, for two such periods; can be used in this case. «less

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Suyash replied | 19/11/2016

Given,
Compound Interest -Simple Interest = 1
P { 1+ ( 4/100) } ^ 2 - P - ( P×4×2 / 100 ) = 1
On solving,
P = 625

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S

Srinu 09/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Compound Interest

What is the difference between the compound interest on Rs. 5000 for 1 year at the rate 4% per annum compounded yearly and half yearly?

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Shikha replied | 22/11/2016

Compound interest = Amount +Principal. One and a half year can be calculated as 3 and half years.

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G

Geeta 09/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Compound Interest

The compound interest on Rs 30000 at the 7% per annum is Rs 4347. What is the period (in years)?

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Ram Mohan replied | 21/11/2016

The period is 2 years. Very simple solution
30000[ (1+7/100) power n] - 30000 = 4347 = = > 30000 [ (1+7/100) power n] = 34347 ==>
[ (1+7/100) power n] = 34347/30000 ==> [ (100+7)/100) power n] = [ (100+7)/100 ) power 2 ==> n=2

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K

Kiran 09/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Compound Interest

What will be the compound interest on a sum of Rs. 25000 after 3 years at the rate of 12 p.a?

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Shikha replied | 23/11/2016

Amount =[25000(1+12/100)3]
=[25000*28*28*28]/25*25*25
=Rs 35123.20
CI = Rs 35123.2+ Rs 25000= Rs 10,123.20.

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A

Apollo 09/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Compound Interest

Define compound interest?

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Shikha replied | 23/11/2016

Compound interest is the interest to the principal sum i.e., Compound interest = Principal of last year + Amount
Amount = (1+r%) to the power n, number of years.

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P

Preeti 09/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Compound Interest

If the simple interest on a sum of money for 2 years at rate 5% per annum is Rs. 50, What is the compound interest on the same rate and for the same time?

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Sarvajeet replied | 26/11/2016

Rs. 51.25.

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Nagaraj 09/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Compound Interest

What is the formula for calculating time period when number of years and number of months in conversion period is given?

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A

Awdhesh 09/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Compound Interest

A man invests Rs. 5000 for three years at a certain rate of interest, compounded annually. At the end of one year it amounts to Rs. 5600. Calculate the rate of interest per annum?

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Renuka 09/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Compound Interest

A certain sum amounts to be Rs. 5292 in 2 yrs and to be Rs 5556.60 in 3 years at the compound interest. Find the rate and the sum?

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Sriomprakash 09/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Compound Interest

A bank offers 5 % compound interest calculated on half yearly basis. A customer deposits Rs 1600 each on 1st january and 1st july of a year. At the end of the year, what amount he would have gained by way of interest?

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Jitendra 09/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Compound Interest

What is the difference between simple interest and compound interest?

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Vathsala 09/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Compound Interest

There is 60% increase in an amount in 6 years at the simple interest. What will be the compound interest of 1200 after 3 years at the same rate?

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Hima 09/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Compound Interest

At what rate of compound interest per annum will be a sum of Rs 1200 become Rs 1348.32 in 2 years?

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Pratheema 09/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Compound Interest

The least number of complete years in which a sum of money put out at 20% compound interest will be more than doubled is______?

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Rksanthosh 09/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Compound Interest

What is the effective annual rate of interest corresponding to nominal rate of 6 % per annum payable half yearly?

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Nazia 09/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Compound Interest

What is the sum placed on simple interest if simple interest on a certain sum of money for 3 years at 8% per annum is half the compound interest on Rs. 4000 for 2 years at 10% per annum?

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Naveen 09/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Compound Interest

The difference between simple interest and compounded on Rs 1200 for one year at 105 per annum reckoned half yearly?

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K

Kamal 09/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Compound Interest

The compound interest on a certain sum for 2 years at 105 per annum is Rs 525. The simple interest on the same sum for double the time at half the rate percent per annum is______?

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