On a straight road, if a car is moving with the speed of 180 kmh-1 and the driver stops the car in 25 s by applying brakes, then determine the distance covered by the car during the time brakes are applied. Assume, acceleration of the car be uniform throughout the retarding motion.

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Arvind Kumar

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u= 180 km/h= 50 m/s (to convert km/h to m/s multiply 180 by 5/18) v=0; t=25s; use v=u+at⇒ a= -2m/s^2 and then use ⇒ S= 625m
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Speed of the car =180km/h = When the driver applies Break, the speed of the car is 5m/s. So that we can take initial speed 'u' as 5m/s. When the car stops after 25 seconds, the final speed is 0 m/s = ??. Then, the distance travelled can be calculated from the above formula. Where, Therefore,
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Speed of the car =180km/h = When the driver applies Break, the speed of the car is 5m/s. So that we can take initial speed 'u' as 5m/s. When the car stops after 25 seconds, the final speed is 0 m/s = ??. Then, the distance travelled can be calculated from the above formula. Where, Therefore, read less
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Here u=180 km /hr ,v=0 U=180×5/18=50m/sec From 1st equation of motion V=u+at 0=50+a(25) a=-2m/sec^2 (- ) signs shows their is retardation
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