In which of the following options order of arrangement does not agree with the variation of property indicated against it? (a) Al3+ < Mg2+ < Na+ < F– (increasing ionic size) (b) B < C < N < O (increasing first ionization enthalpy) (c) I < Br < Cl < F (increasing electron gain enthalpy) (d) Li < Na < K < Rb (increasing metallic radius)

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Ans. C...Because Electron gain enthalpy of Cl is greater than F
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B.Sc, M.Sc, Ph.D, MBA (Finance and Marketing)

Answer is C. Fluorine due to small size and high no. Of electrons in it's outer most shell slightly repel the electrons. So Cl has highest electron gain enthalpy. Moreover electron gain enthalpy always written with negative sign as it is energy released. So, high magnitude let's say (-10 for chlorine)...
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Answer is C. Fluorine due to small size and high no. Of electrons in it's outer most shell slightly repel the electrons. So Cl has highest electron gain enthalpy. Moreover electron gain enthalpy always written with negative sign as it is energy released. So, high magnitude let's say (-10 for chlorine) with negative sign means lower value when compared with (-2 for iodine). So the order should also be reversed read less
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Specialist in Chemistry.

Option b&c
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Which of the following angle corresponds to sp2 hybridisation? (a) 90° (b) 120° (c) 180° (d) 109°
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