Rajesh Yadav

Mehrauli, Delhi, India - 110016

Rajesh Yadav photo

Rajesh Yadav

Tutor

Mehrauli, Delhi, India - 110016.

3.9

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Education

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Overview

I am seeking for a challenging position as a tutor, where in given chance of proving my skills and abilities in the teaching field. To accomplish my responsibilities to the best of my efficiency and to work hard to achieve objectives.

Languages Spoken

Hindi

English

Education

feroze gandhi institute of engineering & technology raebareli 2017

Bachelor of Technology (B.Tech.)

Address

Mehrauli, Delhi, India - 110016

Verified Info

Phone Verified

Email Verified

Demo Class

No

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BTech Tuition Overview

BTech Tuition

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in BTech Tuition

1

BTech Branch

Telecom Engineering, BTech 1st Year Engineering

Type of class

Regular Classes, Crash Course

Class strength catered to

One on one/ Private Tutions

Taught in School or College

Yes

BTech 1st Year subjects

Engineering Mathematics (M1), Engineering Physics, Basic Electronics, Advanced Mathematics (M2)

Reviews

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FAQs

1. Which BTech branches do you tutor for?

Telecom Engineering and BTech 1st Year Engineering

2. Do you have any prior teaching experience?

Yes

3. Which classes do you teach?

I teach BTech Tuition, Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 6 Tuition, Class 7 Tuition, Class 8 Tuition, Class 9 Tuition and Engineering Entrance Coaching Classes.

4. Do you provide a demo class?

No, I don't provide a demo class.

5. How many years of experience do you have?

I have been teaching for 1 year.

Answers by Rajesh Yadav (1)

Answered on 16/03/2018 CBSE/Class 11/Science/Physics Tuition/Class IX-X Tuition

(1) Energy of the photon (E) = hν = hc/λ = (6.626×10-34 Js×3.0×108 ms-1)/4×10-7 m = 4.97×10-19 J= 4.97×10-19/1.602×10-19 eV (2) Kinetic energy of emission (1/2 mv2) = hν- hνo = 3.10-2.13 = 0.97 eV (3) 1/2 mv2 = 0.97 eV = 0.97×1.602×10-19... ...more

(1) Energy of the photon (E) = hν = hc/λ = (6.626×10-34 Js×3.0×10ms-1)/4×10-7 m = 4.97×10-19 J
= 4.97×10-19/1.602×10-19 eV


(2) Kinetic energy of emission (1/2 mv2) = hν- hνo = 3.10-2.13 = 0.97 eV


(3) 1/2 mv= 0.97 eV = 0.97×1.602×10-19 J
⇒ 1/2×(9.11×10-31 kg)×v= 0.97×1.602×10-19 J
⇒ v= 0.341×1012 = 34.1×1010
⇒ v = 5.84×10ms-1

Answers 26 Comments
Dislike Bookmark

Rajesh YadavDirections

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BTech Tuition 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in BTech Tuition

1

BTech Branch

Telecom Engineering, BTech 1st Year Engineering

Type of class

Regular Classes, Crash Course

Class strength catered to

One on one/ Private Tutions

Taught in School or College

Yes

BTech 1st Year subjects

Engineering Mathematics (M1), Engineering Physics, Basic Electronics, Advanced Mathematics (M2)

Class 9 Tuition 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 9 Tuition

3

Board

CBSE, ICSE, State

CBSE Subjects taught

Mathematics, Science, Information and Comunication Technology

ICSE Subjects taught

Physics, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Science, Mathematics

Class 10 Tuition 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 10 Tuition

3

Board

CBSE, ICSE, State

CBSE Subjects taught

Mathematics, Science, Information and Comunication Technology

ICSE Subjects taught

Physics, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Science, Mathematics

Class 6 Tuition 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 6 Tuition

3

Board

CBSE, State

CBSE Subjects taught

Science, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, Science

Class 7 Tuition 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 7 Tuition

3

Board

CBSE, State

CBSE Subjects taught

Science, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, Science

Class 8 Tuition 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 8 Tuition

3

Board

CBSE, State

CBSE Subjects taught

Science, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, Science

Class 11 Tuition 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 11 Tuition

1

Board

State, International Baccalaureate, CBSE

IB Subjects taught

Mathematics, Physics

CBSE Subjects taught

Physics, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Physics, Mathematics

Class 12 Tuition 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 12 Tuition

1

Board

State, International Baccalaureate, CBSE

IB Subjects taught

Mathematics, Physics

CBSE Subjects taught

Physics, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Physics, Mathematics

Engineering Entrance Coaching classes 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Engineering Entrance Coaching classes

1

Engineering Entrance Exams

IIT JEE Coaching Classes

IITJEE Coaching

IIT JEE Mains Coaching

Type of class

Regular Classes, Crash Course

IIT-JEE Subjects

Physics , Maths

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Answers by Rajesh Yadav (1)

Answered on 16/03/2018 CBSE/Class 11/Science/Physics Tuition/Class IX-X Tuition

(1) Energy of the photon (E) = hν = hc/λ = (6.626×10-34 Js×3.0×108 ms-1)/4×10-7 m = 4.97×10-19 J= 4.97×10-19/1.602×10-19 eV (2) Kinetic energy of emission (1/2 mv2) = hν- hνo = 3.10-2.13 = 0.97 eV (3) 1/2 mv2 = 0.97 eV = 0.97×1.602×10-19... ...more

(1) Energy of the photon (E) = hν = hc/λ = (6.626×10-34 Js×3.0×10ms-1)/4×10-7 m = 4.97×10-19 J
= 4.97×10-19/1.602×10-19 eV


(2) Kinetic energy of emission (1/2 mv2) = hν- hνo = 3.10-2.13 = 0.97 eV


(3) 1/2 mv= 0.97 eV = 0.97×1.602×10-19 J
⇒ 1/2×(9.11×10-31 kg)×v= 0.97×1.602×10-19 J
⇒ v= 0.341×1012 = 34.1×1010
⇒ v = 5.84×10ms-1

Answers 26 Comments
Dislike Bookmark

Rajesh Yadav describes himself as Tutor. He conducts classes in BTech Tuition, Class 10 Tuition and Class 11 Tuition. Rajesh is located in Mehrauli, Delhi. Rajesh takes at students Home, Regular Classes- at his Home and Online Classes- via online medium. He has 3 years of teaching experience . Rajesh has completed Bachelor of Technology (B.Tech.) from feroze gandhi institute of engineering & technology raebareli in 2017. HeĀ is well versed in Hindi and English.

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