The perimeter of two similar triangles ABC and LMN are 60 cm and 48 cm respectively. If LM = 8 cm, then what is the length of AB?

Asked by Last Modified  

5 Answers

Learn Mathematics +1 Class IX-X Tuition

Follow 5
Answer

Please enter your answer

Mathematician

10
Comments

Maths Tutor

AB/LM = p(ABC)/p(LMN) AB/8 = 60/48 AB = 60*8/48 AB = 10cm.
Comments

Teacher

Perimeter Ratio is 60:48 Similar side Ratio will also be the same So 60:48 :: x:8 Gives x = 60x 8/48 = 10 cm Ans
Comments

Math magician

suppose length of AB =X . IN similar triangle ABC :LMN =60:48 =AB:LM =X :8 ,OR 60/48 = X/8 , OR X/8 = 5/4 , Or x=10 .AB =10cm answer.
Comments

Math magician

suppose length of AB =X . IN similar triangle perimeter ABC :LMN =60:48 =AB:LM =X :8 ,OR 60/48 = X/8 , OR X/8 = 5/4 , Or x=10 .AB =10cm answer.
Comments

View 3 more Answers

Related Questions

How do I score 90 marks in Maths for CBSE in class 10?
Just go through your text books,solved examples.concepts should be clear for each topic.try to do more practice in each topic from initially so that no burden will left further.
Profile Photo
Navneet
Find the zeroes of the quadratic polynomial x2 + 5x + 6 and verify the relationship between the zeroes and the coefficients.
Let p(x)= x2+5x+6 Now putting p (x)=0 X2+5x+6=0 X2+3x+2x+6=0 X (x+3)+2 (x+3)=0 (X+3)(x+2)=0 (X+3)=0,(x+2)=0 X=-3,x=-2 Therefor -3 and -2 are zeros of given polynomial p (x)and names alpha and beta Now...
Profile Photo
Rekha
0 0
View Comments5
Are tuitions mandatory in the class 10 CBSE to score a 98%?
No, if you are strong in all subjects and can take guidance from your parents.
Profile Photo
Brahma
0 0
View Comments6
What are the steps to prove two triangles that they have similarities to each other?
There are the following steps to prove that two triangles are similar:- 1. AAA Test (angle angle angle): All three pairs of corresponding angles are the same. 2. SSS Test (side side side): All three pairs...
Profile Photo
Yamun
0 0
View Comments9
Find three numbers in A.P. whose sum is 21 and their product is 231.
Let, three numbers are (a-d), a, (a+d) So, (a-d)+a+(a+d)=21 => a=7 Again, (7-d)×7×(7+d)=231 => (7-d)×(7+d)=231÷7 => 7^2 - d^2 = 33=> d^2 = 49 - 33=> d^2 = 16=> d = 4 So, the numbers are 7-4= 3, 7 and 7+4=11
Profile Photo
Laxmi
0 0
View Comments5

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons

Recommended Articles

Sandhya is a proactive educationalist. She conducts classes for CBSE, PUC, ICSE, I.B. and IGCSE. Having a 6-year experience in teaching, she connects with her students and provides tutoring as per their understanding. She mentors her students personally and strives them to achieve their goals with ease. Being an enthusiastic...

Read full article >

Mohammad Wazid is a certified professional tutor for class 11 students. He has 6 years of teaching experience which he couples with an energetic attitude and a vision of making any subject easy for the students. Over the years he has developed skills with a capability of understanding the requirements of the students. This...

Read full article >

Raghunandan is a passionate teacher with a decade of teaching experience. Being a skilled trainer with extensive knowledge, he provides high-quality BTech, Class 10 and Class 12 tuition classes. His methods of teaching with real-time examples makes difficult topics simple to understand. He explains every concept in-detail...

Read full article >

Quest Academy is a professional Bangalore based NEET and JEE (Main + Advanced) training institute. The academy was incorporated in 2015 to cater to the needs of students, who aim to crack competitive exams by connecting with the best brains around. The institute helps students enhance their skills and capabilities through...

Read full article >

Looking for Class 10 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you