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A train, travelling at a uniform speed for 360 km, would have taken 48 minutes less to travel the same distance if its speed were 5 km/hr more. Find the original speed of the train.

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Suppose the train is travelling X km/h . then it will take 360/X hour . if it speed is( X +5 )km/ h .then it will take 360/(X+5) hour. According to question -- 360/X - 360/(X+5) =48/60 h=4/5 .OR By solving the equation we find ,2250 = X2 +5X OR X read more

Suppose the train is travelling X km/h . then it will take 360/X hour . if it speed is( X +5 )km/ h .then it will take 360/(X+5) hour. According to question -- 360/X - 360/(X+5) =48/60 h=4/5 .OR By solving the equation we find ,2250 = X2 +5X OR X

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Suppose the train is travelling X km/h . then it will take 360/X hour . if it speed is( X +5 )km/ h .then it will take 360/(X+5) hour. According to question -- 360/X - 360/(X+5) =48/60 h=4/5 .OR By solving the equation we find ,2250 = X2 +5X OR X2 read more

Suppose the train is travelling X km/h . then it will take 360/X hour . if it speed is( X +5 )km/ h .then it will take 360/(X+5) hour. According to question -- 360/X - 360/(X+5) =48/60 h=4/5 .OR By solving the equation we find ,2250 = X2 +5X OR X^{2 }

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Suppose the train is travelling X km/h . then it will take 360/X hour . if it speed is( X +5 )km/ h .then it will take 360/(X+5) hour. According to question -- 360/X - 360/(X+5) =48/60 h=4/5 .OR By solving the equation we find ,2250 = X2 +5X OR X2 +5X - 2250 =0 . OR X2... read more

Suppose the train is travelling X km/h . then it will take 360/X hour . if it speed is( X +5 )km/ h .then it will take 360/(X+5) hour. According to question -- 360/X - 360/(X+5) =48/60 h=4/5 .OR By solving the equation we find ,2250 = X2 +5X OR X^{2 }+5X - 2250 =0 . OR X^{2} +50X - 45X - 2250. OR (X2 +50X) - (45X +2250 ) . OR X ( X + 50 ) - 45 ( X +50 ) . OR ( X - 45 )( X+ 50 ) . OR X = 45 and - 50 .. OR speed = 45km / hour ANSWER

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