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Class 10 > Learn Mathematics > A train, travelling at a uniform speed for 360 km,...
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A train, travelling at a uniform speed for 360 km, would have taken 48 minutes less to travel the same distance if its speed were 5 km/hr more. Find the original speed of the train.

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45 km/hr
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360/x -360/x+5 =48 and solve the question because speed=distance/time and it is given distance is 360 and speed is 5 more
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Math magician

Suppose the train is travelling X km/h . then it will take 360/X hour . if it speed is( X +5 )km/ h .then it will take 360/(X+5) hour. According to question -- 360/X - 360/(X+5) =48/60 h=4/5 .OR By solving the equation we find ,2250 = X2 +5X OR X
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Suppose  the train  is travelling  X km/h    . then it will  take 360/X hour . if it speed is( X +5 )km/ h .then it will take  360/(X+5)  hour.    According to question --  360/X  - 360/(X+5)  =48/60 h=4/5   .OR  By solving the equation  we  find   ,2250  = X2 +5X  OR X

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Math magician

Suppose the train is travelling X km/h . then it will take 360/X hour . if it speed is( X +5 )km/ h .then it will take 360/(X+5) hour. According to question -- 360/X - 360/(X+5) =48/60 h=4/5 .OR By solving the equation we find ,2250 = X2 +5X OR X2
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Suppose  the train  is travelling  X km/h    . then it will  take 360/X hour . if it speed is( X +5 )km/ h .then it will take  360/(X+5)  hour.    According to question --  360/X  - 360/(X+5)  =48/60 h=4/5   .OR  By solving the equation  we  find   ,2250  = X2 +5X  OR X2  

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Math magician

Suppose the train is travelling X km/h . then it will take 360/X hour . if it speed is( X +5 )km/ h .then it will take 360/(X+5) hour. According to question -- 360/X - 360/(X+5) =48/60 h=4/5 .OR By solving the equation we find ,2250 = X2 +5X OR X2 +5X - 2250 =0 . OR X2...
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Suppose  the train  is travelling  X km/h    . then it will  take 360/X hour . if it speed is( X +5 )km/ h .then it will take  360/(X+5)  hour.    According to question --  360/X  - 360/(X+5)  =48/60 h=4/5   .OR  By solving the equation  we  find   ,2250  = X2 +5X  OR     X2  +5X - 2250 =0 .    OR  X2 +50X - 45X  - 2250.                                           OR                     (X2 +50X)  -  (45X  +2250 )  . OR     X ( X + 50 ) - 45 ( X +50 )  .          OR     ( X - 45 )( X+ 50 )  .  OR   X =  45 and  - 50  .. OR speed  = 45km / hour ANSWER           

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Science Teacher

the answer is 45 km per hour for detail answer see the attachment.
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Trainer

Distance=360 KM Let speed be S time (t) =360/s Other Speed=S+5 Time=360/(S+5) As per question, 360/S-360(S+5)=48/60 =>x2+5x -2250 = 0=>(x+50)(x-45)=0 Speed = 45 km/hr as speed cannot be negative
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