A train, travelling at a uniform speed for 360 km, would have taken 48 minutes less to travel the same distance if its speed were 5 km/hr more. Find the original speed of the train.

Asked by Last Modified  

9 Answers

Learn Mathematics +1

Follow 9
Answer

Please enter your answer

Deepraj Pandit

Science Teacher

the answer is 45 km per hour for detail answer see the attachment.
Comments
Dislike Bookmark

Tutor

45 km/hr
Comments
Dislike Bookmark

Trainer

Distance=360 KM Let speed be S time (t) =360/s Other Speed=S+5 Time=360/(S+5) As per question, 360/S-360(S+5)=48/60 =>x2+5x -2250 = 0=>(x+50)(x-45)=0 Speed = 45 km/hr as speed cannot be negative
Comments
Dislike Bookmark

360/x -360/x+5 =48 and solve the question because speed=distance/time and it is given distance is 360 and speed is 5 more
Comments
Dislike Bookmark

Math magician

Suppose the train is travelling X km/h . then it will take 360/X hour . if it speed is( X +5 )km/ h .then it will take 360/(X+5) hour. According to question -- 360/X - 360/(X+5) =48/60 h=4/5 .OR By solving the equation we find ,2250 = X2 +5X OR X
read more
Suppose the train is travelling X km/h . then it will take 360/X hour . if it speed is( X +5 )km/ h .then it will take 360/(X+5) hour. According to question -- 360/X - 360/(X+5) =48/60 h=4/5 .OR By solving the equation we find ,2250 = X2 +5X OR X read less
Comments
Dislike Bookmark

Math magician

Suppose the train is travelling X km/h . then it will take 360/X hour . if it speed is( X +5 )km/ h .then it will take 360/(X+5) hour. According to question -- 360/X - 360/(X+5) =48/60 h=4/5 .OR By solving the equation we find ,2250 = X2 +5X OR X2
read more
Suppose the train is travelling X km/h . then it will take 360/X hour . if it speed is( X +5 )km/ h .then it will take 360/(X+5) hour. According to question -- 360/X - 360/(X+5) =48/60 h=4/5 .OR By solving the equation we find ,2250 = X2 +5X OR X2 read less
Comments
Dislike Bookmark

Math magician

Suppose the train is travelling X km/h . then it will take 360/X hour . if it speed is( X +5 )km/ h .then it will take 360/(X+5) hour. According to question -- 360/X - 360/(X+5) =48/60 h=4/5 .OR By solving the equation we find ,2250 = X2 +5X OR X2 +5X - 2250 =0 . OR X2...
read more
Suppose the train is travelling X km/h . then it will take 360/X hour . if it speed is( X +5 )km/ h .then it will take 360/(X+5) hour. According to question -- 360/X - 360/(X+5) =48/60 h=4/5 .OR By solving the equation we find ,2250 = X2 +5X OR X2+5X - 2250 =0 . OR X2 +50X - 45X - 2250. OR (X2 +50X) - (45X +2250 ) . OR X ( X + 50 ) - 45 ( X +50 ) . OR ( X - 45 )( X+ 50 ) . OR X = 45 and - 50 .. OR speed = 45km / hour ANSWER read less
Comments
Dislike Bookmark

JU-IITKGP & 10+ years experienced for boards, JEE,NEET,OLYMPIAD & 5-12

45 km/hr
Comments
Dislike Bookmark

JU-IITKGP & 10+ years experienced for boards, JEE,NEET,OLYMPIAD & 5-12

45 km/hr
Comments
Dislike Bookmark

View 7 more Answers

Related Questions

What do you mean by sales tax?
For example, if you purchase a new television for Rs. 400 and live in an area where the sales tax is 7%, you would pay Rs. 28 in sales tax. Your total bill would be Rs. 428. It is important to note that...
Neha
Is polynomial y4 + 4y2 + 5 have zeroes or not?
The polynomial y4 + 4y2 + 5 has no zero(s) because the roots are not real.
Veerendra
Two different dice are tossed together. Find the probability: (i) That the numbers on either die is even. (ii) That the sum of numbers appearing on the two dice is 5.
Even numbers can occur in the following ways : Dice I Dice II
Anish
1 0
9
Find the zeroes of the quadratic polynomial x2 + 5x + 6 and verify the relationship between the zeroes and the coefficients.
Let p(x)= x2+5x+6 Now putting p (x)=0 X2+5x+6=0 X2+3x+2x+6=0 X (x+3)+2 (x+3)=0 (X+3)(x+2)=0 (X+3)=0,(x+2)=0 X=-3,x=-2 Therefor -3 and -2 are zeros of given polynomial p (x)and names alpha and beta Now...
Rekha
0 0
5
How much monthly fees for Maths for class 10 in Delhi or NCR?
350-400/ hour.
Vishal Ranjan

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons

How to find out trigonometry function value
Angle. 0 30 45 . 60 . 90 Put 0. 1 . 2. 3 . 4 Diviede all by 4 0/4 . 1/4 . 2/4. ...

Tarun Kant Gautam

0 0
0
Class-10 L-5 Arithmetic Progressions Ex-5.1 Q4 (xiii)-(xv)

Ashish Bhatia

0 0
0
class-10 L-6 Triangles Ex-6.2 Q9

Ashish Bhatia

0 0
0
Class-10 L-1 Real Numbers Ex-1.1 Q1 (v)

Ashish Bhatia

0 0
0
PERIMETER OF THE RECTANGLE
PERIMETER OF THE RECTANGLE:- The perimeter of the rectangle is the total length of the outline of the rectangle. It is nothing but sum of the all the four sides of the rectangle. ...

Ramakrishna Dhooli

0 0
0

Recommended Articles

Meet Mohammad Wazid, a skilled trainer for...

Mohammad Wazid is a certified professional tutor for class 11 students. He has 6 years of teaching experience which he couples with an energetic attitude and a vision of making any subject easy for the students. Over the years he has developed skills with a capability of understanding the requirements of the students. This...

Read full article >

Quest Academy - Institute of the month

Quest Academy is a professional Bangalore based NEET and JEE (Main + Advanced) training institute. The academy was incorporated in 2015 to cater to the needs of students, who aim to crack competitive exams by connecting with the best brains around. The institute helps students enhance their skills and capabilities through...

Read full article >

Meet Raghunandan.G.H, a B. Tech Tutor from...

Raghunandan is a passionate teacher with a decade of teaching experience. Being a skilled trainer with extensive knowledge, he provides high-quality BTech, Class 10 and Class 12 tuition classes. His methods of teaching with real-time examples makes difficult topics simple to understand. He explains every concept in-detail...

Read full article >

Meet Sandhya R, a B.Sc tutor from Bangalore

Sandhya is a proactive educationalist. She conducts classes for CBSE, PUC, ICSE, I.B. and IGCSE. Having a 6-year experience in teaching, she connects with her students and provides tutoring as per their understanding. She mentors her students personally and strives them to achieve their goals with ease. Being an enthusiastic...

Read full article >

Find Class 10 Tuition near you
Class 10 Tuition in Delhi
Class 10 Tuition in Bangalore
Class 10 Tuition in Hyderabad
Class 10 Tuition in Kolkata
Class 10 Tuition in Chennai
Class 10 Tuition in Mumbai
Class 10 Tuition in Pune
Class 10 Tuition in Lucknow
Class 10 Tuition in Noida
Class 10 Tuition in Gurgaon
Online Tuition Class 10

Looking for Class 10 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you