A train, travelling at a uniform speed for 360 km, would have taken 48 minutes less to travel the same distance if its speed were 5 km/hr more. Find the original speed of the train.

Asked by Last Modified  

9 Answers

Learn Mathematics +1 Class IX-X Tuition

Follow 9
Answer

Please enter your answer

Science Teacher

the answer is 45 km per hour for detail answer see the attachment.
Comments

Tutor

45 km/hr
Comments

Trainer

Distance=360 KM Let speed be S time (t) =360/s Other Speed=S+5 Time=360/(S+5) As per question, 360/S-360(S+5)=48/60 =>x2+5x -2250 = 0=>(x+50)(x-45)=0 Speed = 45 km/hr as speed cannot be negative
Comments

360/x -360/x+5 =48 and solve the question because speed=distance/time and it is given distance is 360 and speed is 5 more
Comments

Math magician

Suppose the train is travelling X km/h . then it will take 360/X hour . if it speed is( X +5 )km/ h .then it will take 360/(X+5) hour. According to question -- 360/X - 360/(X+5) =48/60 h=4/5 .OR By solving the equation we find ,2250 = X2 +5X OR X
read more
Suppose the train is travelling X km/h . then it will take 360/X hour . if it speed is( X +5 )km/ h .then it will take 360/(X+5) hour. According to question -- 360/X - 360/(X+5) =48/60 h=4/5 .OR By solving the equation we find ,2250 = X2 +5X OR X read less
Comments

Math magician

Suppose the train is travelling X km/h . then it will take 360/X hour . if it speed is( X +5 )km/ h .then it will take 360/(X+5) hour. According to question -- 360/X - 360/(X+5) =48/60 h=4/5 .OR By solving the equation we find ,2250 = X2 +5X OR X2
read more
Suppose the train is travelling X km/h . then it will take 360/X hour . if it speed is( X +5 )km/ h .then it will take 360/(X+5) hour. According to question -- 360/X - 360/(X+5) =48/60 h=4/5 .OR By solving the equation we find ,2250 = X2 +5X OR X2 read less
Comments

Math magician

Suppose the train is travelling X km/h . then it will take 360/X hour . if it speed is( X +5 )km/ h .then it will take 360/(X+5) hour. According to question -- 360/X - 360/(X+5) =48/60 h=4/5 .OR By solving the equation we find ,2250 = X2 +5X OR X2 +5X - 2250 =0 . OR X2...
read more
Suppose the train is travelling X km/h . then it will take 360/X hour . if it speed is( X +5 )km/ h .then it will take 360/(X+5) hour. According to question -- 360/X - 360/(X+5) =48/60 h=4/5 .OR By solving the equation we find ,2250 = X2 +5X OR X2+5X - 2250 =0 . OR X2 +50X - 45X - 2250. OR (X2 +50X) - (45X +2250 ) . OR X ( X + 50 ) - 45 ( X +50 ) . OR ( X - 45 )( X+ 50 ) . OR X = 45 and - 50 .. OR speed = 45km / hour ANSWER read less
Comments

JU-IITKGP & 10+ years experienced for boards, JEE,NEET,OLYMPIAD & 5-12

45 km/hr
Comments

JU-IITKGP & 10+ years experienced for boards, JEE,NEET,OLYMPIAD & 5-12

45 km/hr
Comments

View 7 more Answers

Related Questions

If x:y = 9:10, find the value of (5x + 3y) : (5x - 3y)?
(5x + 3y) : (5x - 3y)=(5x/y+3):(5x/y-3) =(5*9/10+3):(5*9/10-3) =15/3=5
Profile Photo
Altaf
How many of you feel that student should know Vedic mathematics for quick calculations?
Yeah! Vedic should be used for fast calculation. But, when I suggest the students, I found them hesitant in using vedic_maths for fast calculation. I think students should practice well before using this...
Profile Photo
Shweta G.
What is the difference between histogram and bar diagrams?
Bar Chart:- The columns are positioned over a label that represents a categorical variable. The height of the column indicates the size of the group defined by the categories. Histogram:- The columns...
Profile Photo
Vivek
0 0
View Comments7
How hard is basic algebra?
It is very easy to learn, but you should know the formulas ,rules & theorms.
Profile Photo
Shaun
0 0
View Comments8
Is there any relation between AM, GM, HM in Progressions?
Yes relationship is present and also equation is also present
Profile Photo
Avinash

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons


Coordinate Geometry notes on Section Formula Applications in a conceptual, equation-free format
Class 10 Mathematics – Section Formula Applications 1. What is Section Formula? The section formula helps us find a point that divides a line segment joining two points into a given ratio. The...
Profile Photo



SURFACE AREA OF SPHERE
SURFACE AREA OF SPHERE:- If, the radius of a sphere=r Then, SURFACE AREA OF SPHERE=4πr2 Ex;- If, radius of a sphere=r=14cm SURFACE AREA OF SPHERE=4πr2 ...
Profile Photo

Recommended Articles

Mohammad Wazid is a certified professional tutor for class 11 students. He has 6 years of teaching experience which he couples with an energetic attitude and a vision of making any subject easy for the students. Over the years he has developed skills with a capability of understanding the requirements of the students. This...

Read full article >

Quest Academy is a professional Bangalore based NEET and JEE (Main + Advanced) training institute. The academy was incorporated in 2015 to cater to the needs of students, who aim to crack competitive exams by connecting with the best brains around. The institute helps students enhance their skills and capabilities through...

Read full article >

Raghunandan is a passionate teacher with a decade of teaching experience. Being a skilled trainer with extensive knowledge, he provides high-quality BTech, Class 10 and Class 12 tuition classes. His methods of teaching with real-time examples makes difficult topics simple to understand. He explains every concept in-detail...

Read full article >

Sandhya is a proactive educationalist. She conducts classes for CBSE, PUC, ICSE, I.B. and IGCSE. Having a 6-year experience in teaching, she connects with her students and provides tutoring as per their understanding. She mentors her students personally and strives them to achieve their goals with ease. Being an enthusiastic...

Read full article >

Looking for Class 10 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you