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Class 10 > The lengths of the diagonals of a rhombus are 30 cm...
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The lengths of the diagonals of a rhombus are 30 cm and 40 cm. Find the side of the rhombus.

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diagonals of a rhombus are perpendicular bisector so we can find side of rhombus with pythagoras theorem. H^2 = P^2 + B^2 Side^2 = 15^2 + 20^2 Side^2 = 225 + 400 Side^2 = 625 Side = 25
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As we know , the diagonals of rhombus are perpendicular bisectors. We can apply pythagorus theorem in one triangle, Side of rhombus = sqrt(15^2+20^2) = 25
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Let ABCD is a rhombus BD, AC are diagonals of a rhombus. Diagonals are bisects each other at O Now ∆AOB is a right angle triangle, by Pythagoras theorem AB^2=AO^2+OB^2 Given AC=40, BD=30 ,O is midpoint of AC,BD Ao=20, OB=15 AB^2=(20×20)+(15×15)=400+225=625 AB=√625=25 Therefore side of the rhombus is...
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For Rhombus ABCD with BD, AC as diagonals of a rhombus. We know Diagonals are bisects each other at O Now ?AOB is a right angle triangle and by Pythagoras theorem AB^2=AO^2+OB^2 Given AC=40, BD=30 ,O is midpoint of AC,BD AO=20, OB=15 AB^2=(20×20)+(15×15)=400+225=625 AB=?625=25 Therefore side of the...
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For Rhombus ABCD with BD, AC as diagonals of a rhombus. We know Diagonals are bisects each other at O Now ?AOB is a right angle triangle and by Pythagoras theorem AB^2=AO^2+OB^2 Given AC=40, BD=30 ,O is midpoint of AC,BD AO=20, OB=15 AB^2=(20×20)+(15×15)=400+225=625 AB=?625=25 Therefore side of the rhombus is 25cm read less
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25cm.
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