The larger of two supplementary angles exceeds thrice the smaller by 20 degrees. Find them.

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Chandrakanth

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Larger angle X Smaller angle Y We have X+Y=180..(1) larger angle exceeds thrice smaller by 20 ∴X=3Y+20..(2) Solving (1)&(2) X+Y=180 X-3Y=20 4Y=160⇒Y=40... smaller angle ∴larger angle X=140 Tq.
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Larger angle X Smaller angle Y We have X+Y=180..(1) larger angle exceeds thrice smaller by 20 ∴X=3Y+20..(2) Solving (1)&(2) X+Y=180 X-3Y=20 4Y=160⇒Y=40... smaller angle ∴larger angle X=140 Tq. read less
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Let first angle = x And second number = y As both angles are supplementary so that sum will 180 x + y = 180 x = 180 - y ... (1) Difference is 18 degree so that x -- y = 18 Plug the value of x we get 180-- y -- y = 18 - 2 y = -162 y...
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Let first angle = x And second number = y As both angles are supplementary so that sum will 180 x + y = 180 x = 180 - y ... (1) Difference is 18 degree so that x – y = 18 Plug the value of x we get 180– y – y = 18 - 2 y = -162 y = -162/-2 y = 81 Plug the value back in equation first we get x = 180 – 81 = 99 read less
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Let x and y be Larger angle and smaller angle of two suplimentary angles respectively I.e., x+y=180 also given x-3y=20 Now solving (x+y)-(x-3y)=180-20 4y=160 Y=160/4=40 X=180-40=140
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Two angle are supplementary, hence the sum of two angles is 180deg. Let the larger angle be A, then the other angle will be 180-A As given, A=3(180-A)+20 A=540-3A+20 4A = 560 A=140 Hence, the larger angle is 140deg and the smaller angle is 40deg. A = 72.5
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x=3y+20 and x+y=180. So, y=40 and x= 140
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If smaller angle =X , then larger = 3X +20 . so X + 3X +20 = 180 , or 4X +20 = 180 or 4X = 160, then X = 40 smaller angle ,and larger angle =140 , answer
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