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The angles of a triangle are arranged in ascending order of magnitude. If the difference between two consecutive angles is 10°, find all the three angles.

Tutor

Let a be the one of the given triangle Let a+10, a+20 be another two angles a+a+10+a+20=180 3a+30=180 3a=150 a=50 50, 60, 70 are the required angles

Teacher

Let the angles of the triangle be A,B and C Given that B = A +10 and C = B + 10 = A +20 By adding we get A + (A + 10) + (A + 20)= 3 A + 30 = 180 This gives 3A = 150 Or A = 50 So the angles are 50,60 and 70 degrees Check 50+60+70 = 180

Math Magician

Let the any one of the angle of triangle be x then other two angle are x+10, x+20 According to Question, x + (x+10) + (x+20)=180 3x + 30 = 180 3x = 150 x = 50 Thus, angles would be 50, 60, and 70.

Tutor

The angles are x,x+10 and x+20. We have 3x+30=180 or x=50. Other two angles are 60 and 70.

Let first angle be A. Then the second angle will be A+10 and third angle will be A+20. As we know the sum of angles of a triangle=180 therefore A+A+10+A+20 = 180=> 3A+30=180 => 3A=150 => A=50 Therefore the 3 angles are 50, 60,70 degs.

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