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If the radius of the base of a cone is doubled keeping the height same. What is the ratio of the volume of the larger cone to the smaller cone?

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Given: Smaller cone's radius 'r' Larger cone's radius '2r' W.K.T: Volume of cone =1/3 * pi* r^2 * h ----? A Therefore, volume of larger cone = 1/3 * pi * (2r)^2 * h =4/3 * pi * r^2 *h ----? B To Find: Volume of larger cone : vol of smaller Which is B : A as labelled... read more

Given: Smaller cone's radius 'r' Larger cone's radius '2r' W.K.T: Volume of cone =1/3 * pi* r^2 * h ----? A Therefore, volume of larger cone = 1/3 * pi * (2r)^2 * h =4/3 * pi * r^2 *h ----? B To Find: Volume of larger cone : vol of smaller Which is B : A as labelled above Therefore 4:1 Hence the solution! read less

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