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# Finding the equation of a straight line

B.Sudhakar
05/02/2017 0 0

Find the equation of a straight line passing through ( -2, 5 ) and (4, -3 )

We can use two point formula to solve this problem

( y - y1) = ( x - x1) • ( y2 - y1)/(x2 - x1 )-----------------------------( 1 )

x1 = -2 , x2 = 4 , y1 = 5 and y2 = -3  by substituting all these values in equation (1 )

( y - 5 ) = { x - ( -2 ) } • { -3 - 5 } / { 4 - (-2) }

( y - 5 ) = ( x + 2 ) • (-8)/(6)

( y - 5 ) = ( x + 2 ) • (-4)/(3)

3 ( y - 5 ) = -4 ( x + 2 )

3y - 15 = -4x - 8

3y + 4x -7 = 0

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