During an experiment, a signal from a spaceship reached the ground station in five minutes. What was the distance of the spaceship from the ground station? The signal travels at the speed of light, that is, 3 × 108 m s−1?

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Time taken by the signal to reach the ground station from the spaceship = 5 min = 5 × 60 = 300 s Speed of the signal = 3 × 108 m/s ∴Distance travelled = Speed × Time taken = 3 × 108 × 300 = 9 × 1010 m Hence, the distance of the spaceship from the ground station...
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Time taken by the signal to reach the ground station from the spaceship = 5 min = 5 × 60 = 300 s Speed of the signal = 3 × 108 m/s ∴Distance travelled = Speed × Time taken = 3 × 108 × 300 = 9 × 1010 m Hence, the distance of the spaceship from the ground station is 9 × 1010 m. read less
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Distance = speed x time = 3 x 10 to the power 8m/s x 5 x 60 s = 9 x 10(10) m please understand bracketed 10 as power.
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5 mins=300 seconds. So distance is: 3*10^8*300 m.
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We know that the expression for the velocity is, Substitute the values given in the question to find the distance of the space ship from the ground station. First convert the time from minutes to seconds using the fact that there are 60 seconds in one minute. We have, time=5×60 s =300 sv=3×10^8...
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We know that the expression for the velocity is, Substitute the values given in the question to find the distance of the space ship from the ground station. First convert the time from minutes to seconds using the fact that there are 60 seconds in one minute. We have, time=5×60 s =300 sv=3×10^8 m/s So, the distance is d= v×t d=9×10^10 m read less
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