Kalyan Vihar Rajpura, Delhi Details verified of Harsh Sharma✕
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University of Delhi Pursuing
Bachelor of Science (B.Sc.)
178/1, Rajpura, Kalyan Vihar
Kalyan Vihar Rajpura, Delhi, India - 110007
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Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
CBSE
Subjects taught
Physics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
CBSE
Subjects taught
Physics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
CBSE
Subjects taught
Science, Mathematics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
CBSE
Subjects taught
Science, Mathematics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
CBSE
Subjects taught
Mathematics, Science
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
CBSE
Subjects taught
Mathematics, Science
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
CBSE
Subjects taught
Mathematics, Science
Taught in School or College
No
Answered on 29/10/2019 Learn CBSE - Class 9/Science/Unit 3-Motion, Force and Work/Motion/NCERT Solutions/Intext Exercise 8.2
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Post a Lesson
We know that the expression for the velocity is,
Substitute the values given in the question to find the distance of the space ship from the ground station.
First convert the time from minutes to seconds using the fact that there are 60 seconds in one minute.
We have,
time=5×60 s
=300 s
v=3×10^8 m/s
So, the distance is
d= v×t
d=9×10^10 m
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Answers 4 
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Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
CBSE
Subjects taught
Physics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
CBSE
Subjects taught
Physics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
CBSE
Subjects taught
Science, Mathematics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
CBSE
Subjects taught
Science, Mathematics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
CBSE
Subjects taught
Mathematics, Science
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
CBSE
Subjects taught
Mathematics, Science
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
CBSE
Subjects taught
Mathematics, Science
Taught in School or College
No
Answered on 29/10/2019 Learn CBSE - Class 9/Science/Unit 3-Motion, Force and Work/Motion/NCERT Solutions/Intext Exercise 8.2
Ask a Question
Post a Lesson
We know that the expression for the velocity is,
Substitute the values given in the question to find the distance of the space ship from the ground station.
First convert the time from minutes to seconds using the fact that there are 60 seconds in one minute.
We have,
time=5×60 s
=300 s
v=3×10^8 m/s
So, the distance is
d= v×t
d=9×10^10 m
Like 0 Answers 4 Comments Ask a Question
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