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What are the products formed when aqueous and ethanolic KOH reacts with 1-bromopropane?

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When aq. KOH reacts with 1-bromo propene gives substitution product as 1-propanol, where as alc. KOH gives elimination prod. 1-propene
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With aqueous koh 1-ethanol and with alcoholic koh propene
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Prop-1-ene
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If aq. KOH then propan-1-ol If Alcoholic KOH then propene
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When bromopropane reacts with aq. KOH, then it will forms propanol and when it reacts with alc. KOH then it will forms Propene
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Aq kOH is alkaline in nature so it gives hydroxide ion which is a nucleophile to replace halide(bromide in this case) and form alcohols. Alcholic KOH produces base which is stronger than OH ion,so here it brings about elimination reaction. So with Aq KOH alcohols are formed & the reaction is nucleophilic...
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Aq kOH is alkaline in nature so it gives hydroxide ion which is a nucleophile to replace halide(bromide in this case) and form alcohols. Alcholic KOH produces base which is stronger than OH ion,so here it brings about elimination reaction. So with Aq KOH alcohols are formed & the reaction is nucleophilic substitution reaction.Where as with alcoholic KOH the reaction is B-Elimination rxn and the product is alkene. read less
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Aq. KOH gives Propan-1-ol and Al alcoho KOH gives Propene
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Its nucleophile substition reaction whr OH replace Br and formed propan-1-ol plus KBr in case of aqueous mediem Bt in alcoholic KOH gives elimination reaction to give propene
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Propanol and propene
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