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What are the products formed when aqueous and ethanolic KOH reacts with 1-bromopropane?

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CBSE/Class 11 CBSE/Class 11/Science/Chemistry

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When aq. KOH reacts with 1-bromo propene gives substitution product as 1-propanol, where as alc. KOH gives elimination prod. 1-propene
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When bromopropane reacts with aq. KOH, then it will forms propanol and when it reacts with alc. KOH then it will forms Propene
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If aq. KOH then propan-1-ol If Alcoholic KOH then propene
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Professional Chemistry(NEET,WBJEE)& Physics(10th) Teacher with 4 years experience

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Its nucleophile substition reaction whr OH replace Br and formed propan-1-ol plus KBr in case of aqueous mediem Bt in alcoholic KOH gives elimination reaction to give propene
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Aq kOH is alkaline in nature so it gives hydroxide ion which is a nucleophile to replace halide(bromide in this case) and form alcohols. Alcholic KOH produces base which is stronger than OH ion,so here it brings about elimination reaction. So with Aq KOH alcohols are formed & the reaction is nucleophilic... read more

Aq kOH is alkaline in nature so it gives hydroxide ion which is a nucleophile to replace halide(bromide in this case) and form alcohols.

Alcholic KOH produces base which is stronger than OH ion,so here it brings about elimination reaction.

So with Aq KOH alcohols are formed & the reaction is nucleophilic substitution reaction.Where as with alcoholic KOH the reaction is B-Elimination rxn and the product is alkene.

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Prop-1-ene
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Mathematics Teacher with 5th highest marks in Maths in JEE 2015

Propanol and propene
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With aqueous koh 1-ethanol and with alcoholic koh propene
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Aqueous KOH releases mild OH- Which acts nucleophile and substitute the bromide to result 2-propanol, on the othe hand ethanolic KOH releases strong OH- which acts as base to result dehydrobromination gives propene.
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