A constant retarding force of 50N is applied to a body of mass 20 kg moving initially with a speed of 15 ms-1. How long does the body take to stop?

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Dushyant

Physics is fun. Love for physics. Physician in South delhi

time will be 6sec.. because from f=ma we find acceleration .Which is retarded means (-). Then put according to question.in ist equation of motion. V=0. And u given we know acceleration (a) then find.time.. very easily...
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retardation = - 50/20 = - 2.5 m/s u= 15 m/s, v = 0 m/s v = u - at 0 = 15 - 2.5 ( t ) t = 15 / 2.5 t = 6 sec.
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force exerts deceleration in body which can be find by F=ma 52=20xa a=2.5ms-2 the deceleration is 2.5ms-2 to find time taken to stop the mass, we can use newton equation of motion v=u+at 0=15-2.2t t=15/2.5 t=6s. therefore it would take 6 seconds to stop the mass
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force exerts deceleration in body which can be find by F=ma 52=20xa a=2.5ms-2 the deceleration is 2.5ms-2 to find time taken to stop the mass, we can use newton equation of motion v=u+at 0=15-2.2t t=15/2.5 t=6s. therefore it would take 6 seconds to stop the mass read less
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