One mole of any substance contains 6.022 x 1023 atoms/molecules. Number of molecules of H2S04 present in 100 mL of 0.02 M H2S04 solution is __________(a)12.044 x 1020 molecules (b) 6.022 x 1023 molecules (c) 1 x 1023 molecules (d) 12.044 x 1023 molecules" "

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To find the number of molecules of H2SO4H2SO4 present in 100 mL of a 0.02 M H2SO4H2SO4 solution, we need to first calculate the number of moles of H2SO4H2SO4 present in the solution using the given concentration. Given: Concentration of H2SO4H2SO4 solution = 0.02 M Volume of H2SO4H2SO4 solution =...
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To find the number of molecules of H2SO4H2SO4 present in 100 mL of a 0.02 M H2SO4H2SO4 solution, we need to first calculate the number of moles of H2SO4H2SO4 present in the solution using the given concentration. Given: Concentration of H2SO4H2SO4 solution = 0.02 M Volume of H2SO4H2SO4 solution = 100 mL = 0.1 L Using the formula for molarity, M=molesvolume(inL)M=volume(inL)moles, we can rearrange it to find the number of moles: moles=M×volume(inL)moles=M×volume(inL) moles=0.02 mol/L×0.1 Lmoles=0.02mol/L×0.1L moles=0.002 molmoles=0.002mol Now, to find the number of molecules, we'll use Avogadro's number, 6.022×10236.022×1023 molecules/mol: Numberofmolecules=moles×Avogadro’snumberNumberofmolecules=moles×Avogadro’snumber Numberofmolecules=0.002 mol×6.022×1023 molecules/molNumberofmolecules=0.002mol×6.022×1023molecules/mol Numberofmolecules=1.2044×1021 moleculesNumberofmolecules=1.2044×1021molecules So, the correct answer is: (a) 1.2044×10211.2044×1021 molecules read less
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