If tan|+sin|=m and tan|- sin|=n, show that (m2-n2)=4?mn

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On Squaring and subtracting, we get m^2-n^2=4tanlsinl Now, taking rhs, on multiplying 1*2, we get mn=tan^2l- sin^2l( by property of a^2-b^2) Again, by changing tan into sin cos we get, mn=tan^2lsin^2l Taking under root, we get √ mn=tanlsinl Hence proved!
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